The answer to your question is a
Answer:
Compression of hydrogen gas within the container.
Answer: 
Explanation:
cM 0 0
So dissociation constant will be:
Given: c = 0.15 M
pH = 1.86
= ?
Putting in the values we get:
Also ![pH=-log[H^+]](https://tex.z-dn.net/?f=pH%3D-log%5BH%5E%2B%5D)
![1.86=-log[H^+]](https://tex.z-dn.net/?f=1.86%3D-log%5BH%5E%2B%5D)
![[H^+]=0.01](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D0.01)
![[H^+]=c\times \alpha](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3Dc%5Ctimes%20%5Calpha)
As ![[H^+]=[ClCH_2COO^-]=0.01](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D%5BClCH_2COO%5E-%5D%3D0.01)
![K_a=1.67\times 10^{-3]](https://tex.z-dn.net/?f=K_a%3D1.67%5Ctimes%2010%5E%7B-3%5D)
Thus the vale of for the acid is
Answer:
<h3>The answer is option B</h3>
Explanation:
The pH of a solution can be found by using the formula
pH = - log [ H+ ]
To find the hydrogen ion concentration substitute the pH into the above formula and solve for the [ H+ ]
From the question
pH = 4.25
So we have
4.25 = - log [ H+ ]
<u>Find the antilog of both sides</u>
That's
<h3>
![[ H+ ] = {10}^{ - 4.25}](https://tex.z-dn.net/?f=%5B%20H%2B%20%5D%20%3D%20%20%7B10%7D%5E%7B%20-%204.25%7D%20)
</h3>
We have the final answer as
<h2>
![[ H+ ] = 5.6 \times {10}^{ - 5} \: M](https://tex.z-dn.net/?f=%5B%20H%2B%20%5D%20%3D%205.6%20%5Ctimes%20%20%7B10%7D%5E%7B%20-%205%7D%20%20%5C%3A%20M)
</h2>
Hope this helps you
Answer:
(a) I⁻ (charge 1-)
(b) Sr²⁺ (charge 2+)
(c) K⁺ (charge 1+)
(d) N³⁻ (charge 3-)
(e) S²⁻ (charge 2-)
(f) In³⁺ (charge 3+)
Explanation:
To predict the charge on a monoatomic ion we need to consider the octet rule: atoms will gain, lose or share electrons to complete their valence shell with 8 electrons.
(a) |
I has 7 valence electrons so it gains 1 electron to form I⁻ (charge 1-).
(b) Sr
Sr has 2 valence electrons so it loses 2 electrons to form Sr²⁺ (charge 2+).
(c) K
K has 1 valence electron so it loses 1 electron to form K⁺ (charge 1+).
(d) N
N has 5 valence electrons so it gains 3 electrons to form N³⁻ (charge 3-).
(e) S
S has 6 valence electrons so it gains 2 electrons to form S²⁻ (charge 2-).
(f) In
In has 3 valence electrons so it loses 3 electrons to form In³⁺ (charge 3+).
