All categories

2 years ago

A roll of tape measures 45.5 inches. What is the length of the tape in meters?

Chemistry

1 answer:

FinnZ [79.3K]2 years ago

8 0

1.5 metres is the length of the tape. Hope this helps :)

You might be interested in

What elements of paint can help forensic scientists compare samples to each other?

saul85 [17]

It would have to be paints consists of pigments,solvents, and binders. Once the [paint has been applied and has dried, the pigments are still able to determine the matched samples.

4 0

2 years ago

A cylinder contains 4.0 g of nitrogen gas. A piston compresses the gas to half its initial volume. Afterward, by what factor has

notka56 [123]

Answer:

The mass density will be doubled

Explanation:

Density is given by dividing the mass of a substance by its volume.
An increase in mass causes an increase in density and vice versa, while a decrease in volume causes an increase in density and volume.
Therefore, when the volume is halved, then the density will be doubled if the mass is kept constant.
This has no effect on the number of moles as the mass is constant.

8 0

2 years ago

We have an object with a density of 620 g/ cm3 and a volume of 75 cm3. What is the mass of this object?

Anna11 [10]

M=D*V
D=620 g/cm³
V=75 cm³

m= 620 g/cm³ * 75 cm³=46500 g
m=46500g

8 0

2 years ago

Acetic acid, ch3cooh, is a weak organic acid, pka 4.47. determine the position of the equilibrium for the reaction of acetic aci

Alexeev081 [22]

Acetic acid (CH3COOH) is a weak acid while methylamine (CH3NH2) is a weak base. During an acid base reaction, an acid tends to lose a proton while a base tends to accept a proton. The reaction at equilibrium is as follows:

$CH3COOH +CH3NH2$ ↔ $CH3COO^{-} +CH3NH3^{+}$

Hence the species in equilibrium are:

Acetate anion: CH3COO-

Methyl ammonium cation: CH3NH3+

4 0

2 years ago

Read 2 more answers

Calculate the empirical formula for each of the following substances. (Express answer as a chemical formula) 1) 2.90 g of Ag and

exis [7]

Answer:

1) Ag3N

2)Na2S

3)NaHSO4

4) KNO3

Explanation:

We divide each mass by the element's relative atomic mass

1) 2.90/108-Ag, 0.125/14-N

0.027-Ag, 0.0089-N

Divide by the lowest ratio

0.027/0.0089-Ag, 0.0089/0.0089 N

3-Ag, 1-N

Empirical formula- Ag3N

2)2.22/23-Na, 1.55/32-S

0.097-Na, 0.048-S

Divide by the lowest ratio

0.097/0.048-Na, 0.048/0.048-S

2-Na, 1-S

Empirical formula- Na2S

3) 2.11/23-Na, 0.0900/1-H, 2.94/32-S,5.86/16-O

0.09-Na, 0.09-H, 0.09-S,0.366-O

Divide by the lowest ratio

0.09/0.09-Na, 0.09/0.09-H, 0.09/0.09-S, 0.366/0.09-O

1-Na, 1-H, 1-S, 4-O

Empirical formula- NaHSO4

4)1.84/39, 0.657/14-N, 2.25/16-O

0.047-K, 0.047-N, 0.14-O

Divide through by the lowest ratio

0.047/0.047-K, 0.047/0.047-N, 0.14/0.047-O

1-K, 1-N, O-3

Empirical formula- KNO3

4 0

2 years ago