Answer:
that looks pretty and also well NGC 1427A has no general shape, so it is an irregular galaxy. U has a bulge in the center and arms, so it is a spiral galaxy. They are similar in the both certain plenty of dust and gas. Both also have active star-forming sites.
Remember the formula as per the second Law of Newton: F = m*a
And also remember that the weight is the force with which the mass is attracted by the planet (or satellite in the case of the moon).
With that information you can answer the questions:
a) Weight = F = m*a
m = 175 slugs = 175 lbm
i) Earth
a = 32.17 ft/s^2
Weight on Earth = 175 lbm * 32.17 ft / s^2 = 5,629.75 poundal
ii) Moon
a = [1/6] 32.17 ft/s^2
Weight on the Moon = [1/6]*5,629.75 poundal = 938.29 poundal
b) Force = 355 poundal
m = 25.0 slug
a in m/s^2 = ?
First calculate the force in ft/s^2
F = m*a => a = F/m = 355 poundal / 25.0 slug = 14.2 ft/s^2
Conversion:
14.2 ft / s^2 * [ 0.3048 m/ft] = 4.32816 m/s^2
Answer: 4.33 m/s^2
Answer
5
Explanation:
We can go about this using the percentage compositions.
First, we calculate the percentage composition of the copper sulphate. This is obtainable by using the mass.
0.96/1.5 * 100 = 64%
Hence the percentage by mass of the water present is 36%
The molar mass of the anhydrous sulphate is 64 + 32 +4(16) = 160g/mol
The molar mass of the water is 2(1) + 16 = 18g/mol
Not forgetting that it is in multiples of x, the total molar mass of the water is 18x moles
The total mass of the copper sulphate hydrate is 160+ 18x
Now how do we get x? Like it is said earlier, the percentage composition is constant.
Hence, 64/100 * (160 + 18x) = 160
16000 = 64(160 + 18x)
16000 = 10,240 + 1152x
16,000 - 10,240 = 1152x
1152x = 5760
x = 5760/1152
x = 5
MgCl₂)= Mg²⁺ + 2Cl⁻
V(MgCl₂)=285cm³=0,285dm³
c(MgCl₂)=0,015 mol/dm³
n(MgCl₂)=c·V= 0,015 mol/dm³ · 0,285dm³ = 0,0042 mol
n(Mg²⁺)=n(MgCl₂)=0,0042 mol
n(Cl⁻)=2n(MgCl₂)=0,0084 mol
