Hydrocarbons may vary from state to state depending on the length of the carbon chain. For methane to butane, they are usually in gas form. Starting from pentane, they are in the liquid form. For very long carbon chains, that occur as solids. Now, it depends if the pentane is in a nonpolar liquid or polar liquid. Since pentane is nonpolar, it is miscible in the liquid solvent. The movements would most likely be free flowing. But if he solvent is polar, the molecules would repel with one another. In the end, it will form two liquid phases, on for the pentane and one for the polar solvent.
Answer:
a. 95.35 L b. 20.52 L c. 19.07 L
Explanation:
Hello,
In the attached picture, you will find the solution for this exercise.
Take into account that for the Redllich-Kwong volume, a cubic polynomial must be solved to get the roots, thus, two roots are complex and one contains the molar volume which is converted to the volume I am showing.
In the following link you will find the corresponding states graph I used: https://www.slideserve.com/taipa/che-201-introduction-to-chemical-engineering
Best regards.
Answer:
Use E = h*c / lambda, where h is Planck's constant, c is the speed of light, and lambda is the wavelength.
E = (6.626 * 10^-34 J*s x 3.00 * 10^8 m/s) / (1*10^-6 m) = 1.99 * 10^-19 J
Explanation:
Answer:
Aluminium atoms = 4.13 *10^22 aluminium atoms
The correct answer is E
Explanation:
Step 1: Data given
Mass of Al2O3 = 3.50 grams
Molar mass of Al2O3 = 101.96 g/mol
Number of Avogadro = 6.022 * 10^23 /mol
Step 2: Calculate moles Al2O3
Moles Al2O3 = mass Al2O3 / molar mass Al2O3
Moles Al2O3 = 3.50 grams / 101.96 g/mol
Moles Al2O3 = 0.0343 moles
Step 3: Calculate moles Aluminium
In 1 mol Al2O3 we have 2 moles Al
in 0.0343 moles Al2O3 we have 2*0.0343 = 0.0686 moles Al
Step 4: Calculate aluminium atoms
Aluminium atoms = moles aluminium * Number of Avogadro
Aluminium atoms = 0.0686 * 6.022 * 10^23
Aluminium atoms = 4.13 *10^22 aluminium atoms
The correct answer is E
