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NeTakaya
2 years ago
14

Type in the maximum number of electrons that can be present in each shell or subshell below.

Chemistry
2 answers:
diamong [38]2 years ago
7 0

<span>n = 5 shell=50</span>

<span>n = 2 shell=8</span>

<span>n = 2, l = 0 subshell=2</span>

<span>n = 2, l = 1 subshell=6</span>

<span><span>3d subshell=</span>10</span>

<span>2s subshell=2</span>

<span><span>5f subshell=14</span></span><span><span> sorry if I'm late I just did this! hope it helps..</span></span>
IRISSAK [1]2 years ago
4 0

Pauli's principle states that in an atom there cannot be more than one electron described by the same combination of the 4 quantum numbers. As an orbital is described by a particular combination of the first three quantum numbers (n, l, and ml), each orbital can only accommodate 2 electrons (one of ms = + 1/2 and the other of ms = -1 / 2). Thus the layer K (n = 1), for which there is only one possible combination of n, l, and ml (that is to say an orbital), can accommodate a maximum of 2 electrons.

That is to say, that contains 4 orbitals, can contain a maximum of 8 electrons.


The orbitals are named s (contains 2 electrons max) p (contains 6 electrons max) d (contains 10 electrons max) and f (contains 14 electrons max).


As you get into the orbitals they have an extra "l" number.


The maximum number of electrons that can contain a given electronic layer is 2 n^2.




Let's go back to the question, for n = 5 the corresponding layer is the "O" layer, as well as the lower layers, and they can contain 50 electrons.


For n = 2 the corresponding layer is the layer "L" and the lower layer "K", and they can contain 8 electrons (2 + 6 electrons).


For n = 3 L = 0 it corresponds to the first under layer with 2 electrons.


For n = 3 L = 1 it corresponds to the second 6-electron sub-layer.


For n = 3 d (corresponding to l = 2) the corresponding layer is the layer "M" and it can contain 10 electrons.


For n = 2 s (corresponding to l = 0) it corresponds to 2 electrons


For n = 5 f (corresponding to l = 3) it corresponds to 14 electrons

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See explanation

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Our answer options for this question are:

a. 2-chlorobutanoic acid:_______ 2-chlorobutanoic acid:_______ 3-chlorobutanoic acid:______.

b. 2,4-dinitrobenzoic acid:______ p-nitrobenzoic acid:______ p-bromobenzoic acid:_______.

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<u>a. 2-chlorobutanoic acid,</u> <u>3-chlorobutanoic acid</u>

<u />

In this case, the difference between these molecules is the position of "Cl". If the chlorine atom is closer to the acid group, we will have a higher inductive effect. So, the bond O-H would be weaker and we will have more acidity. So, the molecule with more acidity is <u>2-chlorobutanoic acid</u> and the less acidic would be <u>3-chlorobutanoic acid.</u>

<u />

<u>b. 2,4-dinitrobenzoic acid,</u> <u>p-nitrobenzoic acid,</u> <u>p-bromobenzoic acid</u>

<u />

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<u>c. p-cyanobenzoic acid</u>, <u>benzoic acid</u>, <u>p-aminobenzoic acid</u>

On these molecules, we have several structural differences. In <u>p-cyanobenzoic acid</u> we have a deactivating group, therefore in this molecule we will have more acidity. In the <u>p-aminobenzoic acid,</u> we have an activating group, so, this would be the less acidic compound.

<u />

See figure 1

I hope it helps!

<u />

<u />

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