answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
NeTakaya
2 years ago
14

Type in the maximum number of electrons that can be present in each shell or subshell below.

Chemistry
2 answers:
diamong [38]2 years ago
7 0

<span>n = 5 shell=50</span>

<span>n = 2 shell=8</span>

<span>n = 2, l = 0 subshell=2</span>

<span>n = 2, l = 1 subshell=6</span>

<span><span>3d subshell=</span>10</span>

<span>2s subshell=2</span>

<span><span>5f subshell=14</span></span><span><span> sorry if I'm late I just did this! hope it helps..</span></span>
IRISSAK [1]2 years ago
4 0

Pauli's principle states that in an atom there cannot be more than one electron described by the same combination of the 4 quantum numbers. As an orbital is described by a particular combination of the first three quantum numbers (n, l, and ml), each orbital can only accommodate 2 electrons (one of ms = + 1/2 and the other of ms = -1 / 2). Thus the layer K (n = 1), for which there is only one possible combination of n, l, and ml (that is to say an orbital), can accommodate a maximum of 2 electrons.

That is to say, that contains 4 orbitals, can contain a maximum of 8 electrons.


The orbitals are named s (contains 2 electrons max) p (contains 6 electrons max) d (contains 10 electrons max) and f (contains 14 electrons max).


As you get into the orbitals they have an extra "l" number.


The maximum number of electrons that can contain a given electronic layer is 2 n^2.




Let's go back to the question, for n = 5 the corresponding layer is the "O" layer, as well as the lower layers, and they can contain 50 electrons.


For n = 2 the corresponding layer is the layer "L" and the lower layer "K", and they can contain 8 electrons (2 + 6 electrons).


For n = 3 L = 0 it corresponds to the first under layer with 2 electrons.


For n = 3 L = 1 it corresponds to the second 6-electron sub-layer.


For n = 3 d (corresponding to l = 2) the corresponding layer is the layer "M" and it can contain 10 electrons.


For n = 2 s (corresponding to l = 0) it corresponds to 2 electrons


For n = 5 f (corresponding to l = 3) it corresponds to 14 electrons

You might be interested in
Enter the chemical equation 2H+(aq)+S2−(aq)→H2S(g). Express your answer as a chemical equation.
amm1812

Answer : The complete chemical equation is,

2H^+(aq)+S^{2-}(aq)\rightarrow H_2S(aq)

Explanation :

As we know that, in a chemical equation the reacting species present on left side and the product formed present on right side and a right arrow inserted between the reactants and product that show a chemical reaction taking place.

In the chemical reaction, the phases of the substances are also included and subscripts and superscripts are also used for the numbers.

For the given chemical reaction, the balanced chemical equation including the phases, is given by:

2H^+(aq)+S^{2-}(aq)\rightarrow H_2S(aq)

4 0
1 year ago
Read 2 more answers
In Philip’s French class, the students are learning how to pronounce closed vowels and open vowels. The students are most likely
Sladkaya [172]

Answer:

It sounds like they are studying French phonemes

Explanations:

I just learned this.

7 0
2 years ago
Read 2 more answers
Write an equation to show how HC2O4− can act as a base with HS− acting as an acid.
Artyom0805 [142]

An acid donates H^{+} ion in aqueous solution. A base accepts H^{+} ion in aqueous solution.

The equation representing the acid base reaction of HC_{2}O_{4}^{-} and HS^{-}:

HC_{2}O_{4}^{-}(aq) + HS^{-}(aq) ----> H_{2}C_{2}O_{4}(aq)+S^{2-}(aq)

In the above reaction, as HC_{2}O_{4}^{-} acts as a base it is accepting the hydrogen ion from HS^{-}. Similarly, HS^{-} donates its hydrogen ion to HC_{2}O_{4}^{-} acting as an acid.

7 0
2 years ago
A chemist adds 180.0 mL of a 1.42M sodium carbonate (Na CO,) solution to a reaction flask. Calculate the millimoles of sodium ca
svet-max [94.6K]

Answer: The millimoles of sodium carbonate the chemist has added to the flask are 256

Explanation:

Molarity is defined as the number of moles dissolved per liter of the solution.

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{milli moles of solute}}{\text{Volume of solution in ml}}     .....(1)

Molarity of BaCl_2 solution = 1.42 M

Volume of solution = 180.0 mL

Putting values in equation 1, we get:

1.42M=\frac{\text{milli moles of }BaCl_2}{180.0ml}\\\\\text{milli moles of }BaCl_2}={1.42M\times 180.0ml}=256milli mol

Thus the millimoles of sodium carbonate the chemist has added to the flask are 256.

6 0
2 years ago
A slug takes 4.25 minutes to travel 11.2 centimeters. What is the speed of the slug in minutes per second?
nexus9112 [7]

Answer:

4.39 ×  10^{-4} m/sec

Explanation:

7 0
2 years ago
Other questions:
  • CH3CH2CH(Cl)CHO iupac name?
    12·1 answer
  • A car moves at a speed of 50 kilometers/hour. Its kinetic energy is 400 joules. If the same car moves at a speed of 100 kilomete
    10·1 answer
  • Type the correct answer in the box. Express your answer to three significant figures.
    6·2 answers
  • The equilibrium constant, Kc, for the reaction H2 (g) + I2 (g) ⇄ 2HI (g) at 425°C is 54.8. A reaction vessel contains 0.0890 M H
    14·1 answer
  • On a cool morning (12"C), a balloon is filled with 1.5 L of helium. By mid afternoon, the temperature has soared to 32°C. What i
    14·1 answer
  • A 0.5 mol sample of He(g) and a 0.5 mol sample of Ne(g) are placed separately in two 10.0 L rigid containers at 25°C. Each conta
    15·1 answer
  • When 189.6 g of ethylene (C2H4) burns in oxygen to give carbon dioxide and water, how many grams of CO2 are formed? C2H4(g) + O2
    7·1 answer
  • A metal, M , of atomic mass 56 amu reacts with chlorine to form a salt that can be represented as MClx. A boiling point elevatio
    8·1 answer
  • One litre of hydrogen at STP weight 0.09gm of 2 litre of gas at STP weight 2.880gm. Calculate the vapour density and molecular w
    9·1 answer
  • Calculate the molar solubility of mercury (I) bromide, Hg2Br2, in 1.0 M KBr. The Ksp for Hg2Br2 is 5.6 X 10−23. (Hint: How would
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!