A slug takes 4.25 minutes to travel 11.2 centimeters. What is the speed of the slug in minutes per second?

Succinic acid is a substance produced by lichens, Chemical analysis indicates it is composed of 40.68% carbon, 5.08% hydrogen, a

Neporo4naja [7]

Answer:

C4H6O4

Explanation:

First, the empirical formula needs to be calculated as follows

- Divide each element mass by its molar mass to convert to moles

C = 40.68/12 = 3.39moles

H = 5.08/1 = 5.08moles

O = 54.24/16 = 3.39moles

Next, we divide each mole value by the smallest (3.39moles)

C = 3.39/3.39 = 1

H = 5.08/3.39 = 1.5

O = 3.39/3.39 = 1

To get the empirical formula of this molecule, we multiply all by 2 to have:

C = 2

H = 3

O = 2

The empirical formula of C,H,O = 2:3:2

That is, C2H3O2

Next, we find the molecular formula as follows:

(C2H3O2)n = 118.1

{12(2) + 1(3) + 16(2)}n = 118.1

24 + 3 + 32 = 118.1

59n = 118.1

n = 118.1/59

n = 2.001

Therefore, the molecular formula is:

(C2H3O2)2

= C4H6O4

5 0

2 years ago

A paint machine dispenses dye into paint cans to create different shades of paint. The amount of dye dispensed into a can is kno

frosja888 [35]

Answer:

The 9th percentile is 4.464ml

Explanation:

Hello!

Given the variable X: Amount of dye dispensed into a paint can.

With a normal distribution, mean μ= 5ml and standard deviation δ= 0.4ml

You need to calculate the 9th percentile of the distribution.

The percentile is a measure of the position that indicates the number that separates the distribution or data set in a percentage of interest. In this case, the 9th percentile is the value of the distribution that separates the bottom 9% from the top 91%.

Symbolically:

P(X≤x₀)= 0.09

x₀ represents the value of the percentile.

The best way to calculate this value is by using the standard normal distribution since it is already tabulated, and then "translate" the Z-value to a value of the variable.

Under the standard normal distribution you have to look for:

P(Z≤z₀)= 0.09

The value marks the bottom 9% of the distribution, this means that you'll find it in the left tail of it. Remember the mean of the standard normal distribution is zero, so all values under the mean will be negative. Using the left entry of the Z-table you have to look for 0.09 in the body of the table and reach the margins to find the corresponding value:

z₀= -1.34

Now using the formula of the distribution you can "translate" the Z-value in terms of the variable of interest

Z=(X-μ)/ δ ~N(0;1)

z₀=(x₀-μ)/ δ

z₀*δ=x₀-μ

x₀=(z₀*δ)+μ

x₀=(-1.34*0.4)+5

x₀= 4.464

The 9th percentile is 4.464ml

I hope you have a SUPER day!

4 0

2 years ago

In a hospital laboratory, a 10.0 mL sample of gastric juice (predominantly HCl), obtained several hours after a meal, was titrat

LiRa [457]

Answer: 1.14

Explanation:

$HCl+NaOH\rightarrow NaCl+H_2O$

To calculate the molarity of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HCl$

are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=1\\M_1=?\\V_1=10.0mL\\n_2=1\\M_2=0.1M\\V_2=7.2mL$

Putting values in above equation, we get:

$1\times M_1\times 10.0=1\times 0.1\times 7.2\\\\M_1=0.072M$

To calculate pH of gastric juice:

molarity of $H^+$ = 0.072

$pH=-log[H^+]$

$pH=-log(0.072)=1.14$

Thus the pH of the gastric juice is 1.14

3 0

2 years ago

What is the empirical formula of a compound which contains 84.4% c and 15.6% h by mass?

podryga [215]

Answer: The empirical formula for the given compound is $CH_2$

Explanation : Given,

Percentage of C = 84.4 %

Percentage of H = 15.6 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of C = 84.4 g

Mass of H = 15.6 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{84.4g}{12g/mole}=7.03moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{15.6g}{1g/mole}=15.6moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 7.03 moles.

For Carbon = $\frac{7.03}{7.03}=1$

For Hydrogen = $\frac{15.6}{7.03}=2.22\approx 2$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H = 1 : 2

Hence, the empirical formula for the given compound is $C_1H_2=CH_2$

7 0

2 years ago

How many cycles of the synthesis pathway are needed to produce myristic acid, c13h27cooh?

Alenkasestr [34]

The primary cycle of fatty acid synthesis produces a four-carbon acyl group. Every following cycle adds a three-carbon malonyl group, which stretches off one molecule of CO2 (one carbon atom) in a condensation response. Thus, the net number of carbon atoms additional by each following cycle is two. For the reason that the first cycle makes a four-carbon chain, and each added cycle extends the chain by two carbon atoms, the second cycle fallouts in a six-carbon chain, the third cycle fallouts in an eight-carbon chain, and so on. And so, the synthesis of the 14-carbon myristic acid necessitates six repetitions.

7 0

2 years ago