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Arisa [49]
2 years ago
5

Suppose you have a bucket of sand containing 5.5 billion grains of sand ( 5.5×109 grains). Most of the grains of sand are white,

but there are some brown grains mixed evenly throughout.
If the concentration of brown sand is 6.0% , how many grains of brown sand are in the bucket?

brown grains

If the concentration of brown sand is 6.0 ppm, how many grains of brown sand are in the bucket?

brown grains

If the concentration of brown sand is 6.0 ppb, how many grains of brown sand are in the bucket?

brown grains
Chemistry
1 answer:
Ilya [14]2 years ago
5 0

Explanation:

5.5 billion grains of sand ( 5.5×109 grains)

If the concentration of brown sand is 6.0% , how many grains of brown sand are in the bucket?

Number of grains = Concentration of brown side *  Bucket of sand

Brown grains = 0.06 *  5.5×10^9  = 0.33 x 10^9 = 3.3 x 10^8 grains

<em>If the concentration of brown sand is 6.0 ppm, how many grains of brown sand are in the bucket?</em>

Number of grains = Concentration of brown side *  Bucket of sand

6ppm = 6 / 1000000 = 0.000006

Brown grains =  0.000006  *  5.5×10^9  = 3.3 x 10^4 grains

<em>If the concentration of brown sand is 6.0 ppb, how many grains of brown sand are in the bucket?</em>

Number of grains = Concentration of brown side *  Bucket of sand

6ppb = 6 / 1000000000 = 0.000000006

Brown grains =  0.000000006  *  5.5×10^9  = 3.3 x 10^1 = 33 grains

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umka2103 [35]

Complete question from other source attached

Answer:

Explanation:

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7 0
2 years ago
Chandra forms her question: "What is the effect of soda on plant growth?" What would be a good hypothesis for this question?
ratelena [41]

Soda provides nutritional value that helps plants grow.

Explanation:

I just did this question and that’s what was right.

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2 years ago
g You observed the formation of several precipitates in the Reactions in Solution lab exercise. Identify the precipitate in each
RUDIKE [14]

<u>Answer:</u>

<u>For a:</u> Lead iodide is a yellow precipitate.

<u>For b:</u> Barium sulfate is a white precipitate.

<u>For c:</u> Ferric hydroxide is a brown precipitate.

<u>For d:</u> Copper (II) hydroxide is a blue precipitate.

<u>Explanation:</u>

Precipitation reaction is defined as the reaction where a solid precipitate (solid substance) is formed at the end of the reaction. It is insoluble in water.

For the given options:

  • <u>For (a):</u>

The chemical reaction between KI and lead (II) nitrate follows:

2KI(aq)+Pb(NO_3)_2(aq)\rightarrow PbI_2(s)+2KNO_3(aq)

The iodide of lead is generally insoluble in water. Thus, lead iodide is a yellow precipitate.

  • <u>For b:</u>

The chemical reaction between barium chloride and sulfuric acid follows:

BaCl_2(aq)+H_2SO_4(aq)\rightarrow BaSO_4(s)+2HCl(aq)

The sulfate of barium is insoluble in water. Thus, barium sulfate is a white precipitate.

  • <u>For c:</u>

The chemical reaction between NaOH and ferric chloride follows:

3NaOH(aq)+FeCl_3(aq)\rightarrow Fe(OH)_3(s)+3NaCl(aq)

The hydroxide of iron is insoluble in water. Thus, ferric hydroxide is a brown precipitate.

  • <u>For d:</u>

The chemical reaction between NaOH and copper sulfate follows:

CuSO_4+2NaOH\rightarrow Cu(OH)_2+Na_2SO_4

The hydroxide of copper is insoluble in water. Thus, copper (II) hydroxide is a blue precipitate.

6 0
1 year ago
in a mixture of helium and chlorine, occupying a volume of 12.8 l at 605.6 mmhg and 21.6 oc, it is found that the partial pressu
rodikova [14]

Answer:

Mass of sample = 8.483 g

Explanation:

Given data;

Volume of mixture = 12.8 L

Pressure = 605.6 mmHg    ( 605.6 / 760 = 0.797 atm)

Temperature = 21.6 °C   (21.6 + 271.15 = 294.8 K)

Partial pressure of chlorine = 143 mmHg    ( 143/760 = 0.19 atm)

Solution:

First of all we will determine the number of moles of mixture.

PV = nRT

n = PV/RT

n = 0.797atm × 12.8L / 0.0821 atm. dm³ mol⁻¹ K⁻¹ ×294.8 K

n = 10.202 / 24.2031

n = 0.422 mol

partial pressure of chlorine is 0.19 atm so mole fraction is,

mole fraction = 0.19/0.797

mole fraction = 0.24

moles of chlorine = 0.24 × 0.422 = 0.1013 mol

moles of helium = moles of mixture - moles of chlorine

moles of helium = 0.422 - 0.1013

moles of helium = 0.3207 mol

Mass of chlorine = moles × molar mass

Mass of chlorine = 0.1013 mol × 71 g/mol

Mass of chlorine = 7.2 g

Mass of helium = moles × molar mass

Mass of helium = 0.3207 mol × 4 g/mol

Mass of helium = 1.283 g

Mass of sample = mass of chlorine + mass of helium

Mass of sample = 7.2 g + 1.283 g

Mass of sample = 8.483 g

5 0
1 year ago
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givi [52]
Mixture is a combination of two or more substances. The components of the mixture are not chemically reacted and can be separated using physical means.
compound is a combination of two or more substances that are chemically reacted or bound together. The components of the compound cannot be separated except by chemical reactions.

Answer:
<span>(4) consist of two or more substances</span>
5 0
2 years ago
Read 2 more answers
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