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notsponge [240]
2 years ago
7

Arranges the following molecules in order of increasing dipole moment: H2O, H2S, H2Te, H2Se.

Chemistry
1 answer:
erastova [34]2 years ago
7 0

Explanation:

Dipole moment is defined as the measurement of the separation of two opposite electrical charges.

H_{2}O is a bent shaped molecule with a dipole moment of 1.87.

H_{2}S is also a bent shaped molecule with a dipole moment of 1.10.

H_{2}Te is a also a bent shaped molecule and has a negligible dipole moment.

H_{2}Se has a dipole moment of 0.29.

Therefore, given molecules are arranged according to their increasing dipole moment as follows.

        H_{2}Te < H_{2}Se < H_{2}S < H_{2}O

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A vessel contains Ar(g) at a high pressure. Which of the following statements best helps to explain why the measured pressure is
Luda [366]

Answer:

4. The combined volume of the Ar atoms is too large to be negligible compared with the total volume of the container.

Explanation:

Deviations from ideality are due to intermolecular forces and to the nonzero volume of the molecules themselves. At infinite volume, the volume of the molecules themselves is negligible compared with the infinite volume the gas occupies.

However, the volume occupied by the gas molecules must be taken into account. Each <u>molecule does occupy a finite, although small, intrinsic volume.</u>

The non-zero volume of the molecules implies that instead of moving in a given volume V they are limited to doing so in a smaller volume. Thus, the molecules will be closer to each other and repulsive forces will dominate, resulting in greater pressure than the one calculated with the ideal gas law, that means, without considering the volume occupied by the molecules.

5 0
2 years ago
A 0.530 M Ca(OH)2 solution was prepared by dissolving 36.0 grams of Ca(OH)2 in enough water. What is the total volume of the sol
Paladinen [302]

The concentration of a solution is the number of moles of solute per fixed volume of solution.

Concentration (C) = number of moles of solute (n) / volume of the solution (v)

we have to find the volume of the solution when 36.0 g of Ca(OH)₂ is added to water to make a solution of concentration 0.530 M

mass of Ca(OH)₂ added - 36.0 g

number of moles of Ca(OH)₂ - 36.0 g / 74.1 g/mol = 0.486 mol

we know the concentration of the solution prepared and the number of moles of Ca(OH)₂ added, substituting these values in the above equation, we can find the volume of the solution

C = n/v

0.530 mol/L = 0.486 mol / V

V = 0.917 L

answer is 0.917 L

6 0
2 years ago
Read 2 more answers
A medical class is hearing a lecture on vision. The doctor asks them what happens when the eye produces too much fluid, causing
Charra [1.4K]

Answer:

The doctor is discussing an Ocular Hypertension disease.

Explanation:

If we have a small space with a defined volume like in this case an eye, when we fill this space with a liquid, the liquid will occupy the whole volume available, and when it is much liquid or fluid, and the volume of the eye can not expand it will start to generate an internal pressure. This higher pressure is called Hypertension.  

3 0
2 years ago
If a gas has a volume of 750 mL at 25oC, what would the volume of the gas be at 55oC?
blagie [28]

Answer:

The answer to your question is     V2 = 825.5 ml

Explanation:

Data

Volume 1 = 750 ml

Temperature 1 = 25°C

Volume 2= ?

Temperature 2 = 55°C

Process

Use the Charles' law to solve this problem

                V1/T1 = V2/T2

-Solve for V2

                V2 = V1T2 / T1

-Convert temperature to °K

T1 = 25 + 273 = 298°K

T2 = 55 + 273 = 328°K

-Substitution

                V2 = (750 x 328) / 298

-Simplification

                V2 = 246000 / 298

-Result

                V2 = 825.5 ml

             

7 0
2 years ago
Consider the decomposition of the compound C5H6O3 as follows below. C5H6O3(g) → C2H6(g) + 3 CO(g) When a 5.63-g sample of pure C
timofeeve [1]

Answer:

K = 6.5 × 10⁻⁶

Explanation:

C₅H₆O₃ ⇄ C₂H₆ + 3CO

Use PV=nRT to find the initial pressure of C₅H₆O₃

P (2.50) = (0.0493) (0.08206) (473)

P = 0.78atm

C₅H₆O₃ ⇄ C₂H₆ + 3CO

0.78atm      0           0

0.78 - x        x           3x

1.63atm = 0.78 - x + x + 3x

P(total) = 0.288atm

C₅H₆O₃ = 0.78 - 0.288

             = 0.489atm

C₂H₆ = 0.288atm

CO = 0.846atm

K_p = \frac{0.288 * 0.864^3}{0.489}

     = 0.379

K = \frac{K_p}{RT^3}

K = \frac{0.379}{(0.0821 * 473)^3}

   = 6.5 × 10⁻⁶

7 0
2 years ago
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