846.6 g of sodium hydroxide solution
Explanation:
The chemical reaction of butanedioic acid with sodium hydroxide:
HOOC-CH₂-CH₂-COOH + 2 NaOH → NaOOC-CH₂-CH₂-COONa + 2 H₂O
To find the mass of the solute (butanedioic acid) from a solution about which we know that the weight/weight percent concentration, we use the following formula:
concentration / 100 = solute mass / solution mass
solute mass = (concentration × solution mass) / 100
solute mass (butanedioic acid mass) = (5 × 10) / 100 = 0.5 g
number of moles = mass / molar weight
number of moles of butanedioic acid = 0.5 / 118 = 0.04237 moles
Knowing the chemical reaction we devise the following reasoning:
if 1 mole of butanoic acid reacts with 2 moles of sodium hydroxide
then 0.04237 moles of butanoic acid reacts with X moles of sodium hydroxide
X = (0.04237 × 2) / 1 = 0.08474 moles of sodium hydroxide
If the concentration of the titrant, sodium hydroxide solution, is 0.1001 moles / 1000 g of solution the we devise the following reasoning:
if there are 0.1001 moles of sodium hydroxide in 1000 g of solution
then there are 0.08474 moles of sodium hydroxide in Y g of solution
Y = (0.08474 × 1000) / 0.1001 = 846.6 g of solution
Learn more about:
weight/weight percent concentration
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