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rewona [7]
2 years ago
5

The yeast Brettanomyces causes spoilage in wine. Brettanomyces produces 4-ethylphenol, which at high levels gives wine a bad fla

vor (described as \"barnyard\" or \"sweaty animal\"). Diagnostic labs test for the presence of Brettanomyces in wine by testing for 4-ethylphenol. Draw 4-ethylphenol (p-ethylphenol).
Chemistry
1 answer:
Tanya [424]2 years ago
5 0
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Which statement BEST describes how a golf club does "work" on a golf ball?
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Answer:

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It looks pretty reasonable to me

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Explain how the models you developed show that when methane combines with oxygen to form carbon dioxide and water, no atoms are
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1 year ago
A student is given the question: "what is the mass of a gold bar that is 7.379 × 10–4 m3 in volume? the density of gold is 19.3
IRINA_888 [86]

<em>The mass of a gold bar  = 1.424 x 10⁴ gram</em>

<em></em>

<h3><em>Further Explanation</em></h3>

Density is a quantity derived from the mass and volume

density is the ratio of mass per unit volume

With the same mass, the volume of objects that have a high density will be smaller than type

The unit of density can be expressed in g / cm3 or kg / m3

Density formula:

\large{\boxed{{\bold{\rho~=~\frac{m}{V}}}}

ρ = density

m = mass

v = volume

A common example is the water density of 1 gr / cm3

The mass itself is often equated with weight, even though it is different. Mass is the amount of matter in the matter while weight is related to the gravitational force

<em>Known variable</em>

volume gold bar 7.379 × 10⁻⁴ m³

a density of 19.3 g/cm³

<em>Asked</em>

the mass of a gold bar

<em>Answer</em>

volume is known to be 7.379 × 10⁻⁴ m³, then we change it first to units of cm³ adjusting to units of density

7.379 × 10⁻⁴ m³ = 7.379 × 10² cm³

then:

mass = volume x density

mass = 7.379 × 10² cm³ x 19.3 g/cm³

mass = 1.424 x 10⁴ gram

<h3><em>Learn more </em></h3>

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3 0
2 years ago
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What would be the products for the reaction Br2 + KI →? (Just identify the correct products for the reaction. You do not need to
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The given chemical equation follows:

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Hence, the products of the reaction will be I_2\text{ and }KBr

5 0
2 years ago
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