The existence of spectra can help the existence of atoms by expanding and multiplying in the law of London Dispersion
Answer:
The answer to your question is: C₂H₆O₁ = C₂H₆O
Explanation:
Data
CxHyOz
mass = 40 g produced 76.40 g of CO2
46.96 g of H2O
Empirical formula = ?
Process
CxHyOz + O2 ⇒ CO2 + H2O
44g of CO2 -------------------- 12 g of Carbon
76.40 g of CO2 --------------- x
x = 20.84 g of Carbon
12 g of Carbon --------------- 1 mol
20.84 g of C --------------- x
x = (20.84 x 1) / 12
x = 1.74 mol of Carbon
18 g of H2O -------------------- 2 g of H
46.96 g of H2O -------------- x
x = (46.96 x 2) / 18
x = 5.22 g of H
1 g of H ------------------------ 1 mol of H
5.22 g of H ------------------- x
x = 5.22 mol of H
Mass of Oxygen = 40 - 20.84 - 5.22g
= 13.94 g
16 g of Oxygen ---------------- 1 mol
13.94 g of O -------------------- x
x = 0.87 mol of O
Divide by the lowest number of moles
Carbon = 1.74 / 0.87 = 2
Hydrogen = 5.22 / 0.87 = 6
Oxygen = 0.87 / 0.87 = 1
Empirical formula
C₂H₆O₁ = C₂H₆O
Answer:
296.1 day.
Explanation:
- The decay of radioactive elements obeys first-order kinetics.
- For a first-order reaction: k = ln2/(t1/2) = 0.693/(t1/2).
Where, k is the rate constant of the reaction.
t1/2 is the half-life time of the reaction (t1/2 = 1620 years).
∴ k = ln2/(t1/2) = 0.693/(74.0 days) = 9.365 x 10⁻³ day⁻¹.
- For first-order reaction: <em>kt = lna/(a-x).</em>
where, k is the rate constant of the reaction (k = 9.365 x 10⁻³ day⁻¹).
t is the time of the reaction (t = ??? day).
a is the initial concentration of Ir-192 (a = 560.0 dpm).
(a-x) is the remaining concentration of Ir-192 (a -x = 35.0 dpm).
<em>∴ kt = lna/(a-x)</em>
(9.365 x 10⁻³ day⁻¹)(t) = ln(560.0 dpm)/(35.0 dpm).
(9.365 x 10⁻³ day⁻¹)(t) = 2.773.
<em>∴ t </em>= (2.773)/(9.365 x 10⁻³ day⁻¹) =<em> 296.1 day.</em>
Answer:
Mole fraction of methanol will be closest to 4.
Explanation:
Given, Mass of methanol = 128 g
Molar mass of methanol = 32.04 g/mol
The formula for the calculation of moles is shown below:
Thus,
Given, Mass of water = 108 g
Molar mass of water = 18.0153 g/mol
The formula for the calculation of moles is shown below:
Thus,
So, according to definition of mole fraction:
<u>Mole fraction of methanol will be closest to 4.</u>
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