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Hoochie [10]
2 years ago
5

A sample of a substance has a mass of 4.2 grams and a volume of 6 milliliters. The density of this substance is

Chemistry
2 answers:
Gnom [1K]2 years ago
8 0

Answer:

Density of the given substance is 0.7 grams/mL

Explanation:

Density is equal to \frac{mass}{volume}

Here mass of substance is 4.2 grams and volume of substance is 6 mL

So density = \frac{4.2 g}{6 mL}=0.7 g/mL

Here final answer should contain one significant figure.

Tanzania [10]2 years ago
4 0

Hello!

Mass =4.2 g

Volume =6 mL

Therefore:

Density = mass / volume

Density = 4.2 / 6

Density = 0.7 g/mL


Hope that helps!

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In a voltaic cell made of a Ag strip and an Al strip immersed in 1.0 M aqueous AgNO_3 and Al(NO_3)_3 solutions, respectively, wi
Tema [17]

Answer:

When the operation of the voltaic cell, which is formed of an aluminum and silver strip takes place, the atom of aluminum loses three of its electrons and the Al3+ formed moves within the solution. The Al3+ ion gets dissolved within the solution and the electrons lost in the process moves through the wire and get acquired by the ions of silver, which then get reduced to solid Ag resulting in the mass gain of silver strip.

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2 years ago
If you perform the experiment described in investigation #15 by mixing 10 g of glue with 13 g of water and 8 g of sodium borate
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10 g of glue with 13 g of water ,

Mass ratio of the material can be calculated as:    

\frac{Mass of glue}{Mass of glue + Mass of water}  

\frac{10 g}{10 g + 13 g }  

\frac{10 g}{23 g }

8 g of sodium borate suspended in 11 g of water, mass ratio can be calculated as:

\frac{Mass of sodium borate}{Mass of sodium borate + Mass of water}  

\frac{ 8 g}{ 8 g + 11 g }  

\frac{8 g}{19 g }

3 0
2 years ago
Which choice below correctly completes the sentence? _______ reaches the Earth's surface through _______, then turns into ______
blondinia [14]

Answer:

d , before the molten rock becomes lava, it is first magma, and most people know that lava is ejected from volcanoes

4 0
2 years ago
The highest principal enegy level of period 2 elements is 2. Period 3 elements all have six 3p electrons. Period 4 elements have
Dmitrij [34]

Explanation:

The highest principal energy level of period 2 elements is 2. (True)

The highest principle energy level of elements of any period is equal to period number. So the given statement is true.

Period 3 elements all have six 3p electrons – (False)  

For example, sodium and sulfur are period 3 elements but do not contain six 3p electrons. Only Argon of period possesses six p-electrons.

Period 4 elements have an inner electron configuration of [Ar]- (True)

Atomic number of elements belonging to period 4 have atomic number more than 18 (atomic number of Ar). So they must have an inner electron configuration of [Ar]

The valence electrons of group 5A elements are in the 6s subshell – [FALSE]

Elements of group 5A are nitrogen, arsenic, antimony and bismuth. They are p-block elements. Therefore, valence electrons are present in p-subshell.

Group 8A elements have full outer principal s and p subshells –(True)  

Group 8A elements are also known as noble gas element. Octets of noble gases are complete and hence, have full outer principal s and p subshells.

The valence electrons of group 2A elements are in an s subshell – (True)

Elements of group 2A are barium, magnesium, calcium, etc. They belong to s-block elements. Therefore, their valence electrons will be in s-subshell.

The highest principal energy level of period 3 elements is 4 – (False)

The highest principle energy level of elements of any period is equal to period number.

For example, sodium is present in 3rd period, so its principle quantum number will be 3.

Period 5 elements have an inner electron configuration of [Xe] – (False)

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6 0
2 years ago
The metallic radius of a lithium atom is 152 pm. What is the volume of a lithium atom in cubic meters?
Anuta_ua [19.1K]

Answer:

Volume of lithium atom is found to be 1.47 X 10⁻²⁹ m³

Explanation:

Let us consider the volume of atom as a sphere (but it is little complex than that). This volume is mathematically expressed as,

V=\frac{4}{3}\pi  R^{3}----------------------------------------------------------------------------------------(Eq. 1)

Here, R is the radius of lithium atom. The radius is given in picometers, so firstly let us convert it into meters

R=(152pm )(1X10^{-12}\frac{m}{pm})

R = 1.52 X 10^{-10}m

placing this value in Eq.1 the required result is achieved

V=\frac{4}{3}\pi  {1.52X10^{-10}}^{3}

V= 1.47 X 10⁻²⁹ m³

8 0
2 years ago
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