<span>mass B/molar mass A = (rate A/rate B)^2.
we know our unknown gas (A) effuses at .797 times our known gas (B) so
rate A/rate B = .797
so 0.797^2 = 28 / molar mass A
Molar mass A = 28 / 0.635 = 44.09 g / mole
Molar mass is 44.09 g/mol</span>
Answer:
Kindly check the attachment for the diagram representing the cell and showing all necessary components including: anode, cathode, electron flow, cation flow and anion flow.
Explanation:
So, the reaction in the concentration cell is given below as;
Cu2+(1.00 M) → Cu2+(0.0100 M).--(1).
The anode = Cu2+(0.0100 M) because it has lesser Concentration, thus, lesser potential value.
Cathode = Cu2+(1.00 M) because it has higher Concentration, hence higher potential value.
It must be noted that in the digaram depicting the Reaction, the electrons moves from the anode part of the cell to the cathode part of the cell and this is done through an external circuit. The following are the things that happens at each electrode;
At the Anode: in here is where oxidation occurs and Cu^2+ is released into the solution.
At the cathode: in here is where the reduction occur and the Cu^2+ moves in the direction to where the Cu electrode is, thus, causing the deposition of Cu.
Answer:
Amino >Methoxy > Acetamido
Explanation:
Bromination is of aromatic ring is an electrophilic substitution reaction. The attached functional group to the benzene ring activates or deactivate the aromatic ring towards electrophilic substitution reaction.
The functional group which donates electron to the benzene ring through inductive effect or resonance effect activates the ring towards electrophilic substitution reaction.
The functional group which withdraws electron to the benzene ring through inductive effect or resonance effect deactivates the ring towards electrophilic substitution reaction.
Among given, methoxy and amino are electron donating group. Amino group are stronger electron donating group than methoxy group. Acetamido group because of presence of carbonyl group becomes electron withdrawing group.
Therefore, decreasing order will be as follows:
Amino >Methoxy > Acetamido
The only solution you'll need to have for this problem is a periodic table. The columns in the table are called groups, and they are number from the left to the right starting with 1. The rows in the table are called periods which are numbered from the top to bottom starting with 1.
6. Elements that belong to the same group portray similar chemical properties. Therefore, the element in period 4 which is also in group 2 is
<em>Calcium (Ca)</em>.
7. The elements that are striked through with the red slanting lines are the metalloids. All the elements to the left of the metalloids are metals. All the elements to the right are nonmetals. Bromine has a symbol of Br. Since At is a metalloid and located in the same group with Br, the
<em>answer is Astatine (At).</em>8. Tin has the chemical symbol of Sn. The nonmetal that is located in the same group is
<em>Carbon (C)</em>.
9. All the elements in period 6 would have similar properties. The answers could be:
<em>Phosphorus (P), Arsenic (As), Antimony (Sb) and Bismuth (Bi)</em>.
10. Period is row 1 and group 18 is the last column.
<em>The answer is Helium (He).</em>
Answer:
i believe this is a chemical or physical question? well your answer to that is no the element does not change because the gold is still gold it is still physical because you have just cut it into piece it is still gold
Explanation:
lmk if it was helpful :/