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poizon [28]
2 years ago
14

Imagine that you combine lemon juice with baking soda in a glass. You see gas bubbles forming along the sides of the glass. How

are the chemical properties of the gas different from the chemical properties of the baking soda and lemon juice?
Chemistry
2 answers:
olasank [31]2 years ago
6 0
<span>The gas that is formed is a different state of matter from the baking soda and lemon juice. The lemon juice has a different odor or smell than the gas. There is no color in the gas, while the lemon juice is yellow, and the baking soda is white.
^^^^^ hope this helps you! :) </span>
Sunny_sXe [5.5K]2 years ago
6 0

Answer:

Gas released in this process is a totally different chemical substance in comparison to the baking soda and lemon juice. It should be Carbon Dioxide formed during the reaction.

Explanation:

We have a baking soda in a glass: it is composed of water and baking soda (NaHCO3). We have lemon juice, its main component is the citric acid (H3C6H5O7). After that, both liquids are mixed and an acid-base reaction occurs.

The reaction releases gas, which should be carbon dioxide (CO2), according to this reaction:

H3C6H5O7 (aq) + 3 NaHCO3 (aq) → 3 CO2 (g) +3H2O (l) + Na3C6H5O7 (aq)

The products of this reaction are Water (H2O) a Salt and carbon dioxide. As carbon dioxide is in the gas phase, it will be released from the liquid mixture as bubbles.

Finally, we can conclude that Gas released in this process is a totally different chemical substance in comparison to the baking soda and lemon juice. It should be Carbon Dioxide formed during the reaction.  

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A sample of ammonia gas at 75°c and 445 mm hg has a volume of 16.0 l. what volume will it occupy if the pressure rises to 1225 m
ioda
In this kind of exercises, you should  use the "ideal gas" rules: PV = nRT
P should be in Pascal: 
445mmHg = 59328Pa
1225mmHg = 163319Pa

V should be in cubic meter:
16L = 0.016 m3

R = \frac{PV}{nT} = constant
\frac{P1 V1}{n T} = \frac{P2 V2}{n T}
==> P1 * V1 = P2 * V2
V2 = \frac{P1 V1}{P2} = \frac{445 0.016}{1225}
V2 = 0.00581 m3 = 5.81 L


7 0
2 years ago
A metal forms two oxides X and Y when contains 28.9% and 21.0% oxygen respectively.
Likurg_2 [28]

Answer:

here ya go trust

Explanation:

3 0
2 years ago
Los automóviles actuales tienen “parachoques de 5 mi/h (8 km/h)” diseñados para comprimirse y rebotar elásticamente sin ningún d
PilotLPTM [1.2K]

Answer:

k = 23045 N/m

Explanation:

To find the spring constant, you take into account the maximum elastic potential energy that the spring can support. The kinetic energy of the car must be, at least, equal to elastic potential energy of the spring when it is compressed to its limit. Then, you have:

K=U\\\\\frac{1}{2}Mv^2=\frac{1}{2}kx^2    (1)

M: mass of the car = 1050 kg

k: spring constant = ?

v: velocity of the car = 8 km/h

x: maximum compression of the spring = 1.5 cm = 0.015m

You solve the equation (1) for k. But first you convert the velocity v to m/s:

v=8\frac{km}{h}*\frac{1000m}{1km}*\frac{1h}{3600s}=2.222\frac{m}{s}

k=\frac{Mv^2}{x^2}=\frac{(1050kg)(2.222m/s)^2}{(0.015m)^2}=23045\frac{N}{m}

The spring constant is 23045 N/m

3 0
2 years ago
Given: CaC2 + N2 → CaCN2 + C In this chemical reaction, how many grams of N2 must be consumed to produce 265 grams of CaCN2? Exp
weeeeeb [17]

Answer : The grams of N_2 consumed is, 89.6 grams.

Solution : Given,

Mass of CaCN_2 = 265 g

Molar mass of CaCN_2 = 80 g/mole

Molar mass of N_2 = 28 g/mole

First we have to calculate the moles of CaCN_2.

\text{Moles of }CaCN_2=\frac{\text{Mass of }CaCN_2}{\text{Molar mass of }CaCN_2}=\frac{265g}{80g/mole}=3.2moles

The given balanced reaction is,

CaC_2+N_2\rightarrow CaCN_2+C

from the reaction, we conclude that

As, 1 mole of CaCN_2 produces from 1 mole of N_2

So, 3.2 moles of CaCN_2 produces from 3.2 moles of N_2

Now we have to calculate the mass of N_2

\text{Mass of }N_2=\text{Moles of }N_2\times \text{Molar mass of }N_2

\text{Mass of }N_2=(3.2moles)\times (28g/mole)=89.6g

Therefore, the grams of N_2 consumed is, 89.6 grams.

5 0
2 years ago
Read 2 more answers
A 3.5 kg iron shovel is left outside through the winter. The shovel, now orange with rust, is rediscovered in the spring. Its ma
Anton [14]

Answer:

a

Explanation:

8 0
2 years ago
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