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poizon [28]
2 years ago
14

Imagine that you combine lemon juice with baking soda in a glass. You see gas bubbles forming along the sides of the glass. How

are the chemical properties of the gas different from the chemical properties of the baking soda and lemon juice?
Chemistry
2 answers:
olasank [31]2 years ago
6 0
<span>The gas that is formed is a different state of matter from the baking soda and lemon juice. The lemon juice has a different odor or smell than the gas. There is no color in the gas, while the lemon juice is yellow, and the baking soda is white.
^^^^^ hope this helps you! :) </span>
Sunny_sXe [5.5K]2 years ago
6 0

Answer:

Gas released in this process is a totally different chemical substance in comparison to the baking soda and lemon juice. It should be Carbon Dioxide formed during the reaction.

Explanation:

We have a baking soda in a glass: it is composed of water and baking soda (NaHCO3). We have lemon juice, its main component is the citric acid (H3C6H5O7). After that, both liquids are mixed and an acid-base reaction occurs.

The reaction releases gas, which should be carbon dioxide (CO2), according to this reaction:

H3C6H5O7 (aq) + 3 NaHCO3 (aq) → 3 CO2 (g) +3H2O (l) + Na3C6H5O7 (aq)

The products of this reaction are Water (H2O) a Salt and carbon dioxide. As carbon dioxide is in the gas phase, it will be released from the liquid mixture as bubbles.

Finally, we can conclude that Gas released in this process is a totally different chemical substance in comparison to the baking soda and lemon juice. It should be Carbon Dioxide formed during the reaction.  

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From the following list of elements, select the elements that are likely to form a cation. Choose one or more: A. oxygen B. chlo
Sloan [31]

Answer:

(i). The elements that are likely to form a cation

(C). calcium, (D). barium, (E). cesium, (F). rubidium, (G).  lead and (H). scandium

(ii). The elements those that will always form ionic compounds in a 1:2 ratio with the halogens

(B).  lead, (G) barium and (I). calcium

Explanation:

Given that,

The following list of elements,

A. oxygen B. chlorine C. calcium D. barium E. cesium F. rubidium G. lead H. scandium I. phosphorous

We know that,

Cation is defined as, an element which is able to donate electron easily and obtained positive ion.

All metal elements able to form cations.

We need to find the elements that are likely to form a cation

Using given list

(C). calcium

(D). barium

(E). cesium    

(F). rubidium    

(G).  lead

(H). scandium

(II). The following list of elements,

A. phosphorous B. lead C. chlorine D. cesium E. rubidium F. scandium G. barium H. oxygen I. calcium  

We know that,

All given metal ions can form ionic compound with halogens as 1:2 ratio because all given metals can form +2 charge.

We need to calculate the elements those that will always form ionic compounds in a 1:2 ratio with the halogens

Using given list.

(B).  lead

(G) barium

(I). calcium

Hence, (i). The elements that are likely to form a cation

(C). calcium, (D). barium, (E). cesium, (F). rubidium, (G).  lead and (H). scandium

(ii). The elements those that will always form ionic compounds in a 1:2 ratio with the halogens

(B).  lead, (G) barium and (I). calcium

5 0
2 years ago
Suppose that 0.323 g of an unknown sulfate salt is dissolved in 50 mL of water. The solution is acidified with 6M HCl, heated, a
geniusboy [140]

Answer:

1) 41.16 % = 0.182 grams

2) The alkali cation is K+ , to form the salt K2SO4

Explanation:

Step 1: Data given

Mass of unknown sulfate salt = 0.323 grams

Volume of water = 50 mL

Molarity of HCl = 6M

Step 2: The balanced equation

SO4^2- + BaCl2 → BaSO4 + 2Cl-

Step 3: Calculate amount of SO4^2- in BaSO4

The precipitate will be BaSO4

The amount of SO4^2- in BaSO4 = (Molar mass of SO4^2-/Molar mass BaSO4)*100 %

The amount of SO4^2- in BaSO4 = (96.06 /233.38) * 100

= 41.16%

So in 0.443g of BaSO4 there will be 0.443 * 41.16 % = <u>0.182 grams</u>

<u />

<u />

2. If it is assumed that the salt is an alkali sulfate determine the identity of the alkali cation.

The unknown sulphate salt has 0.182g of sulphate. This means the alkali cation has a weight of 0.323-0.182 = 0.141g grams

An alkali cation has a chargoe of +1; sulphate has a charge of -2

The formula will be X2SO4 (with X = the unknown alkali metal).

Calculate moles of sulphate

Moles sulphate = 0.182 grams (32.1 + 4*16)

Moles sulphate = 0.00189 moles

The moles of sulphate = 0.182/(32.1+16*4)

The moles of sulphate = 0.00189 moles

X2SO4 → 2X+ + SO4^2-

For 2 moles cation we have 1 mol anion

For 0.00189 moles anion, we have 2*0.00189 = 0.00378 moles cation

Calculate molar mass

Molar mass = mass / moles

Molar mass = 0.141 grams / 0.00378 grams

Molar mass = 37.3 g/mol

The closest alkali metal is potassium. (K2SO4 )

3 0
2 years ago
Boris is interested in conducting his first "real" scientific research. However, he is a bit overwhelmed with all of the possibl
11111nata11111 [884]

Answer:

Questionnaire

Explanation:

This is an instrument for research usually in the form of questions with multiple choice answers with sole purpose of gathering information from respondents for research.

5 0
2 years ago
Suppose you are titrating vinegar, which is an acetic acid solution of unknown strength, with a sodium hydroxide solution accord
Marina CMI [18]

Answer:

M_{acid}=0.563M

Explanation:

Hello there!

In this case, given the neutralization of the acetic acid as a weak one with sodium hydroxide as a strong base, we can see how the moles of the both of them are the same at the equivalence point; thus, it is possible to write:

M_{acid}V_{acid}=M_{base}V_{base}

Thus, we solve for the molarity of the acid to obtain:

M_{acid}=\frac{M_{base}V_{base}}{V_{acid}} \\\\ M_{acid}=\frac{33.98mL*0.1656M}{10.0mL}\\\\ M_{acid}=0.563M

Regards!

5 0
2 years ago
Consider NH3 and PH3. Electronegativities: P = 2.1, H = 2.1, N=3.0. Which statement is false?
NikAS [45]

Answer:

The P-H bonds are more polar than the N-H bonds.

Explanation:

Phosphine is a polar molecule with non-polar bonds. The phosphorus atom is bonded to three hydrogen atoms and the phosphorus atom has a lone pair of electrons. Since hydrogen and phosphorus are equal in electronegativity, it implies that they attract the shared pairs of electrons the same amount,hence bonding electrons are shared equally making the covalent bonds non-polar.

The lone pair of electrons on phosphorus causes the molecule to be asymmetrical with respect to charge distribution this is why the molecule is polar even though the are non-polar bonds in the molecule.

Looking at the values of electro negativity stated in the question, one can easily see that the difference in electro negativity between nitrogen and hydrogen is 0.9 while the difference in electro negativity between phosphorus and hydrogen is zero. It is clear that NH3 is naturally more polar than PH3 since each individual N-H bond in NH3 is a polar bond while the individual P-H bonds in PH3 are nonpolar.

4 0
2 years ago
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