The substance that can be broken down by chemical means from the choices given is <u>CO (Carbon monoxide).</u>
<u>Carbon monoxide</u> is a compound made up of carbon and oxygen and can therefore be broken by chemical means.
<h2>Further Explanation
</h2><h3> Pure substances </h3>
- Pure substances are substances that have a constant composition and also cannot broken down into simpler substances using physical means.
- Pure substances are classified as either elements or compounds.
<h3>Elements
</h3>
- Elements are a type of pure substances that are made up of one type of atom and cannot be broken down into simpler substances by both chemical and physical means.
- Atoms making up a certain element are similar or identical in properties. Examples of elements are, Oxygen, sodium, calcium, etc. Periodic table shows an arrangement of all known elements.
<h3>Compound </h3>
- A compound is a pure substance that is made up of than one type of atoms of different elements and can be broken down into individual elements making it using chemical means.
- Compounds cannot be broken down into simpler substances by physical means but only using chemical means. Compounds have constant composition and therefore they have a constant ratio of elements. For example the ratio of elements making up carbon dioxide is always 27% Carbon and 73% Oxygen.
- Examples of compounds include, water, Ammonia, calcium sulfate, carbon dioxide, etc.
- In our case, Carbon monoxide, (CO) is a compound made up of a carbon atom and an oxygen atom. Other choices, Ca, Ce, and Cu are all elements.
Keywords: Compound, elements, pure substances
<h3>Learn more about:
</h3>
Level: High school
Subject: Chemistry
Topic: Atoms, elements, compounds and mixtures
Answer:
619.2 °C
Explanation:
Given data:
Initial volume of gas = 736 mL
Initial temperature = 15°C
Final volume = 2.28 L
Final temperature = ?
Solution:
First of all we will convert the temperature into kelvin and mL into L.
Initial temperature = 15°C (15+273 = 288 k)
Initial volume of gas = 736 mL × 1 L/1000 mL = 0.736 L
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
0.736 L / 288 k = 2.28 L / T₂
T₂ = 2.28 L× 288 k/0.736 L
T₂ = 656.64 K /0.736
T₂ = 892.2 K
Kelvin to °C:
892.2 K - 273.15 = 619.2 °C
<span>Answer:
A 1.00 L solution containing 3.00x10^-4 M Cu(NO3)2 and 2.40x10^-3 M ethylenediamine (en).
contains
0.000300 moles of Cu(NO3)2 and 0.00240 moles of ethylenediamine
by the formula Cu(en)2^2+
0.000300 moles of Cu(NO3)2 reacts with twice as many moles of en = 0.000600 mol of en
so, 0.00240 moles of ethylenediamine - 0.000600 mol of en reacted = 0.00180 mol en remains
by the formula Cu(en)2^2+
0.000300 moles of Cu(NO3)2 reacts to form an equal 0.000300 moles of Cu(en)2^2+
Kf for Cu(en)2^2+ is 1x10^20.
so
1 Cu+2 & 2 en --> Cu(en)2^2+
Kf = [Cu(en)2^2+] / [Cu+2] [en]^2
1x10^20. = [0.000300] / [Cu+2] [0.00180 ]^2
[Cu+2] = [0.000300] / (1x10^20) (3.24 e-6)
Cu+2 = 9.26 e-19 Molar
since your Kf has only 1 sig fig, you might be expected to round that off to 9 X 10^-19 Molar Cu+2</span>
The atomic mass of a certain element is summation of the product of the decimal equivalent of the percentage abundance and the given atomic mass of each of the isotope. If we let x be the percentage abundance of the 86 amu-isotope then, the second one is 1-x such that,
x(86) + (1 - x)(90) = 87.08
The value of x from the equation is 0.73. This value is already greater than 0.5. Thus, the isotope with greatest abundance is that which is 86 amu.
Answer:
Akash
Explanation:
it could be a magnet with the same poles facing eachoher
