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Virty [35]
1 year ago
9

The active ingredient in Milk of Magnesia™ is Mg(OH)2. Magnesium hydroxide is insoluble in water, so the product is a mixture of

water, flavoring, and other ingredients to suspend the solid Mg(OH)2. When someone suffering from acid indigestion takes this drug, the Mg(OH)2 reacts with the HCl in the stomach. Classify this chemical reaction and write a balanced equation. (Include states of matter)
Chemistry
1 answer:
Liula [17]1 year ago
8 0

Answer:  This chemical reaction is a neutralization reaction between the Milk of Magnesia and the HCl from the stomach. The balanced equation is Mg(OH)2 (s) + 2 HCl (aq) → MgCl2 (aq) + 2 H2O (l)

Explanation:

The reaction between the HCl and the  Mg(OH)2 is a neutralizacion reaction ,  because the HCl is a strong acid and the  Mg(OH)2 is a weak base, then both react and the pH of the medium will increase, so the stomach trouble will dissapear.

Mg(OH)2 (s) + 2 HCl (aq) → MgCl2 (aq) + 2 H2O (l)

Magnesium hydroxide is a weak base due to its very limited solubility in water. This property is a great advantage when treating the excess of HCl in the stomach, because the Mg(OH)2 molecule does not dissociated  easily until it reacts with the  hydrogen ion, H+ of the HCl. So the effect of the  Mg(OH)2 will last longer until the annoyance dissapear.

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How much energy is required to decompose 612 g of pcl3, according to the reaction below? the molar mass of pcl3 is 137.32 g/mol
Assoli18 [71]
The reaction is:

4 PCl3 (g) ---> P4(s) + 6 Cl2(g).

Now, you need to convert the mass of PCl3 into number of moles, for which you use the molar mass of PCl3 in this way:

number of moles = number of grams / molar mass =>

number of moles of PCl3 = 612 g / 137.32 g/mol = 4.4567 moles of PCl3.

Now use the proportion with the ΔH rxn given.

4 mol PCl3 / 1207 kJ = 4.4567 mol / x => x = 4.4567 mol * 1207 kJ / 4 mol = 1,344.8 kJ = 1.34 * 10^3 kJ.

Answer: 1.34 * 10 ^3 kJ (option d)
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2 years ago
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Which indicator is blue in a solution that has a pH of 5.6?
m_a_m_a [10]
Bromcresol green is the indicator that is blue in a solution that has a Ph of 5.6.
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To construct the galvanic cell illustrated above, the salt bridge was prepared by soaking a piece of cotton in 5.0MNaNO3(aq) bef
dalvyx [7]

Answer:

The cell reaction reaches equilibrium quickly and the cell emf becomes zero.

Explanation:

The purpose of a salt bridge is not to move electrons from the electrolyte, its main function is to maintain charge balance because the electrons are moving from one-half cell to the other.

A solution of a salt that dissociates easily is normally used. Water is ineffective at functioning as a salt bridge. Hence the effect stated in the answer.

4 0
2 years ago
What is the hybridization of the central atom in each of the following? 1. Beryllium chloride 2. Nitrogen dioxide 3. Carbon tetr
Lina20 [59]

Answer :

(1) The hybridization of central atom beryllium in BeCl_2  is, sp

(2) The hybridization of central atom nitrogen in NO_2  is, sp^2

(3) The hybridization of central atom carbon in CCl_4  is, sp^3

(4) The hybridization of central atom xenon in XeF_4  is, sp^3d^2

Explanation :

Formula used  :

\text{Number of electron pair}=\frac{1}{2}[V+N-C+A]

where,

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

Now we have to determine the hybridization of the following molecules.

(1) The given molecule is, BeCl_2

\text{Number of electrons}=\frac{1}{2}\times [2+2]=2

The number of electron pair are 2 that means the hybridization will be sp and the electronic geometry of the molecule will be linear.

(2) The given molecule is, NO_2

\text{Number of electrons}=\frac{1}{2}\times [4]=2

If the sum of the number of sigma bonds, lone pair of electrons and odd electrons present is equal to three then the hybridization will be, sp^2.

In nitrogen dioxide, there are two sigma bonds and one lone electron pair. So, the hybridization will be, sp^2.

(3) The given molecule is, CCl_4

\text{Number of electrons}=\frac{1}{2}\times [4+4]=4

The number of electron pair are 4 that means the hybridization will be sp^3 and the electronic geometry of the molecule will be tetrahedral.

(4) The given molecule is, XeF_4

\text{Number of electrons}=\frac{1}{2}\times [8+4]=6

Bond pair electrons = 4

Lone pair electrons = 6 - 4 = 2

The number of electrons are 6 that means the hybridization will be sp^3d^2 and the electronic geometry of the molecule will be octahedral.

But as there are four atoms around the central xenon atom, the fifth and sixth position will be occupied by lone pair of electrons. The repulsion between lone and bond pair of electrons is more and hence the molecular geometry will be square planar.

3 0
1 year ago
A 12.0 g sample of a metal is heated to 90.0 ◦C. It is then dropped into 25.0 g of water. The temperature of the water rises fro
Liula [17]

Answer:

The specific heat of the metal is 0.335 J/g°C

Explanation:

<u>Step 1:</u> Data given

Mass of the metal = 12.0 grams

Initial temperature of the metal = 90.0 °C

Mass of the water = 25.0 grams

Initial temperature of water = 22.5 °C

Final temperature of water (and metal) = 25.0 °C

The specific heat of water = 4.18 J/g°C

<u>Step 2:</u> Calculate the specific heat of the metal

Qgained  = -Qlost

Qwater = -Qmetal

Q= m*c*ΔT

m(metal) *c(metal)*ΔT(metal) = -m(water)*c(water)*ΔT(water)

⇒ mass of the metal = 12.0 grams

⇒ c(metal) = TO BE DETERMINED

⇒ ΔT(metal) = T2 - T1 = 25.0 - 90.0 °C = -65.0

⇒ mass of the water = 25.0 grams

⇒ c(water) = the specific heat of water = 4.18 J/g°C

⇒ ΔT(water) = T2 - T1 = 25.0 - 22.5 = 2.5°C

12.0 * c(metal) * -65.0 = -25.0 * 4.18 * 2.5

c(metal) = 0.335 J/g°C

The specific heat of the metal is 0.335 J/g°C

6 0
1 year ago
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