Answer:
-250.3kJ
Explanation:
Based in the reactions and using -<em>Hess's law-</em>:
(1) P₄(s) + 6 Cl₂(g) → 4PCl₃(g) ΔH₁ = -4439kJ
(2) 4PCl₅(g) → P₄(s) + 10Cl₂ ΔH₂ = 3438kJ
The sum of (1) + (2) is:
4PCl₅(g) → 4PCl₃(g) + 4 Cl₂ ΔH = -4439kJ + 3438kJ = -1001kJ
Dividing this reaction in 4:
PCl₅(g) → PCl₃(g) + Cl₂ ΔH = -1001kJ / 4 = <em>-250.3kJ</em>
Make sure that you understand what they are asking you from this question, as it can be confusing, but the solution is quite simple. They are stating that they want you to calculate the final concentration of 6.0M HCl once a dilution has been made from 2.0 mL to 500.0 mL. They have given us three values, the initial concentration, initial volume and the final volume. So, we are able to employ the following equation:
C1V1 = C2V2
(6.0M)(2.0mL) = C2(500.0mL)
Therefore, the final concentration, C2 = 0.024M.
<u>Answer:</u> The mass of nitrogen that is present for given amount of aluminium is 566.22 g.
<u>Explanation:
</u>
We are given:
Mass of aluminium = 364 grams
The chemical formula of aluminium nitrate is
Molar mass of nitrogen = 14 g/mol
Molar mass of aluminium = 27 g/mol
In 1 mole of aluminium nitrate, 27 grams of aluminium is combining with 42 grams of nitrogen.
So, 364 grams of aluminium will combine with =
of nitrogen.
Hence, the mass of nitrogen that is present for given amount of aluminium is 566.22 g.
Answer:
C. The species became more resistant to the insecticide.
Explanation:
The more of something you receive, the more immune you are to it. For example, every year, many people get a flu shot. Flu shots contain small amounts of the flu, and it is inserted into your blood stream so that you may become more immune to the disease when it comes around. The same happens for many living things, including insects.
Molecular formula is an integral multiple of the empirical formula