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RoseWind [281]
2 years ago
8

Calculate the volume occupied by 10 kg of n-butane at 50 bar and 60°C using a) Ideal gas b) the Redlich-Kwong equation c) the ge

neralized compressibility.

Chemistry
1 answer:
sladkih [1.3K]2 years ago
4 0

Answer:

a. 95.35 L b. 20.52 L c. 19.07 L

Explanation:

Hello,

In the attached picture, you will find the solution for this exercise.

Take into account that for the Redllich-Kwong volume, a cubic polynomial must be solved to get the roots, thus, two roots are complex and one contains the molar volume which is converted to the volume I am showing.

In the following link you will find the corresponding states graph I used: https://www.slideserve.com/taipa/che-201-introduction-to-chemical-engineering

Best regards.

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Determine the empirical formula for compounds that have the following analyses: a. 66.0% barium and 34.0% chlorine b. 80.38% bis
almond37 [142]

Answer: a) BaCl_2

b)  BiO_3H_3

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

a) Mass of Ba= 66.06 g

Mass of Cl = 34.0 g

Step 1 : convert given masses into moles.

Moles of Ba =\frac{\text{ given mass of ba}}{\text{ molar mass of Ba}}= \frac{66.06g}{137g/mole}=0.48moles

Moles of Cl = \frac{\text{ given mass of Cl}}{\text{ molar mass of Cl}}= \frac{34g}{35.5g/mole}=0.96moles[/tex]

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Ba = \frac{0.48}{0.48}=1

For O =\frac{0.96}{0.48}=2

The ratio of Ba: Cl= 1:2

Hence the empirical formula is BaCl_2

b) Mass of Bi= 80.38 g

Mass of O= 18.46 g

Mass of H = 1.16 g

Step 1 : convert given masses into moles.

Moles of Bi =\frac{\text{ given mass of ba}}{\text{ molar mass of Ba}}= \frac{80.38g}{209g/mole}=0.38moles

Moles of O= \frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{18.46g}{16g/mole}=1.15moles

Moles of H=\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{1.16g}{1g/mole}=1.16moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Bi= \frac{0.38}{0.38}=1

For O =\frac{1.15}{0.38}=3

For H=\frac{1.16}{0.38}=3

The ratio of Bi: O: H= 1:3: 3

Hence the empirical formula is BiO_3H_3

6 0
2 years ago
18) Why are the large oak trees so important for storks? Where are<br> they found?<br> 1
Anon25 [30]

Answer: Storks are found in medium to tall trees that occur in stands located either in swamps or on islands ... also an important feeding habitat for the nesting birds. ... six percent in dead oaks

Explanation: There important because Storks only live in these types of trees

Vote me for brainliest!!!!

8 0
2 years ago
A silver sphere has a mass of 5.492 g and a diameter of 10.0 mm. What is the density of silver metal in grams per cubic centimet
Blizzard [7]

Answer:

Explanat\rho=10.5\frac{g}{cm^3}ion:

Hello,

In this case, considering the given diameter which is related to a radius of 5.0 mm and the formula for the calculation of the volume of the sphere, its volume in cubic centimeters (5.00 mm = 0.5 cm) is then:

V=\frac{4}{3} \pi r^3=\frac{4}{3}*\pi*(0.5cm)^3\\\\V=0.524cm^3

In such a way, the density turns out:

\rho =\frac{m}{V} =\frac{5.492g}{0.048m^3} \\\\\rho=10.5\frac{g}{cm^3}

Best regards.

8 0
1 year ago
Describe an experience you've had making or building something where the amount of each ingredient or building block came in fix
nignag [31]
<span>Baking a cake is an example of making something where the ingredients must be in fixed ratios. Recipes call for specific ratios of ingredients in order to cook properly, and when a recipe for a cake is modified to feed greater or fewer people the ratio remains the same as the original recipe.</span>
4 0
2 years ago
How many milligrams of sodium sulfide are needed to completely react with 25.00 ml of a 0.0100 m aqueous solution of cadmium nit
NARA [144]
Na₂S(aq) + Cd(NO₃)₂(aq) = CdS(s) + 2NaNO₃(aq)

v=25.00 mL
c=0.0100 mmol/mL
M(Na₂S)=78.046 mg/mmol

n(Na₂S)=n{Cd(NO₃)₂}=cv

m(Na₂S)=M(Na₂S)n(Na₂S)=M(Na₂S)cv

m(Na₂S)=78.046*0.0100*25.00≈19.5 mg
5 0
2 years ago
Read 2 more answers
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