Answer : The correct option is, Only Student B
Explanation :
Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.
In the Lewis-dot structure the valance electrons are shown by 'dot'.
The given molecule is, 
As we know that nitrogen has '5' valence electrons and hydrogen has '1' valence electron.
Therefore, the total number of valence electrons in = 5 + 3(1) = 8
According to Lewis-dot structure, there are 6 number of bonding electrons and 2 number of non-bonding electrons.
The Lewis dot structure of student A is wrong because there is a coordinate bond present between the nitrogen and hydrogen is not covalent.
Thus, the correct Lewis-dot structure of is shown by the student B.
Answer:
50 mm
4 ft
36 ft
250 cm
1 L
Explanation:
Centimeter to millimeter:
1 cm is equal to 10 mm.
5cm× 10 mm/1 cm
50 mm
Inches to feet conversion:
1 foot is equal to 12 inches.
48 inch × 1 feet /12 inch
4 feet
Yard to Feet conversion:
1 yard is equal to 3 feet.
12 yd × 3 ft / 1 yd
36 ft
Meter to centimeter:
One meter is equal to 100 cm.
2.5 m × 100 cm / 1m
250 cm
Milliliter to Liter:
One L is equal to 1000 mL.
1000 mL = 1 L
Answer:
748 torr
Explanation:
mmHg and torr are equivalent so, you'll have 748 torr.
Answer : The exit temperature of the product is, 
Explanation :
Total heat = Heat lost by liquid + Latent heat of fusion + Heat lost by frozen
where,
Q = Total heat = 6000 kJ
m = mass of product = 15 kg
= specific heat of liquid = 
= latent heat of fusion = 
= specific heat of frozen = 
= initial temperature of liquid = 
= final temperature of liquid = 
= initial temperature of frozen = ?
= final temperature of frozen =
Now put all the given value in the above expression, we get:
![6000kJ=[15kg\times 4kJ/kg^oC\times (10-2)^oC]+[15kg\times 275kJ/kg]+[15kg\times 2.5kJ/kg^oC\times (2-T_3)^oC]](https://tex.z-dn.net/?f=6000kJ%3D%5B15kg%5Ctimes%204kJ%2Fkg%5EoC%5Ctimes%20%2810-2%29%5EoC%5D%2B%5B15kg%5Ctimes%20275kJ%2Fkg%5D%2B%5B15kg%5Ctimes%202.5kJ%2Fkg%5EoC%5Ctimes%20%282-T_3%29%5EoC%5D)
Thus, the exit temperature of the product is,
