Answer: Pine trees, strawberry plants, and cacti are all plants. Name and describe three or more characteristics that you think scientists could use to separate these members of the Plantae kingdom into smaller groups.
Answer:
Explanation: Pine trees, strawberry plants, and cacti are all plants. Name and describe three or more characteristics that you think scientists could use to separate these members of the Plantae kingdom into smaller groups.
Answer:
Pine trees, straw Pine trees, strawberry plants, and cacti are all plants. Name and describe three or more characteristics that you think scientists could use to separate these members of the Plantae kingdom into smaller groups.
Answer:
erry plants, and cacti are all plants. Name and describe three or more characteristics that you think scientists could use to separate the Pine trees, strawberry plants, and cacti are all plants. Name and describe three or more characteristics that you think scientists could use to separate these members of the Plantae kingdom into smaller groups.
Answer:
se members of the Plantae kingdom into smaller groups.
Answer:
Pine trees, strawberry plants, and cacti are all plants. Name and describe three or more characteristics that you think scientists could use to separate these members of the Plantae kingdom into smaller groups.
Answer:
Answer : The final temperature of the solution in the calorimeter is, 
Explanation :
First we have to calculate the heat produced.
where,
= enthalpy change = -44.5 kJ/mol
q = heat released = ?
m = mass of 
= 1.52 g
Molar mass of = 40 g/mol
Now put all the given values in the above formula, we get:
Now we have to calculate the final temperature of solution in the calorimeter.
where,
q = heat produced = 1.691 kJ = 1691 J
m = mass of solution = 1.52 + 35.5 = 37.02 g
c = specific heat capacity of water = 
= initial temperature = 
= final temperature = ?
Now put all the given values in the above formula, we get:
Thus, the final temperature of the solution in the calorimeter is,
Answer:
Explanation:
Entropy change in the system : --
ΔG = −54 kJ⋅mol−1 (−13 kcal⋅mol−1) = −54 kJ⋅mol−1 (−13 x 4.2 kJ⋅mol−1)
= - 108.6 KJ / mol
ΔH = -251 kJ/mol (-60 kcal/mol) = -251 kJ/mol (-60 x 4.2 kJ/mol)
= - 503 KJ / mol
ΔG = ΔH - TΔS
ΔS = ( ΔH - ΔG ) / T
= - 503 + 108.6 / ( 273 + 25 ) KJ / mol k⁻¹
= - 1323.48 J / mol k⁻¹
Entropy change in the surrounding
+ 1323.48 J / mol k⁻¹
1) chromium(III) nitrate is acidic, because it is the salt of weak base (chromium(III) hydroxide Cr(OH)₃) and strong acid (nitric acid HNO₃).
2) sodium hydrosulfide is basic, because it is the salt of strong base (sodium hydroxide MaOH) and weak acid (hydrogen sulfide H₂S).
3) zinc acetate is little basic, because zinc hydroxide (Zn(OH)₂) is stronger base than acetic acid (CH₃COOH).
