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Luden [163]
2 years ago
15

Larisa pumps up a soccer ball until it has a gauge pressure of 61 kilopascals. The volume of the ball is 5.2 liters. The air tem

perature is 32°C, and the outside air is at standard pressure. How many moles of air are in the ball?
A.
0.13 mol
B.
0.33 mol
C.
1.2 mol
D.
3.2 mol
Chemistry
1 answer:
Nuetrik [128]2 years ago
4 0
<h3>Answer:</h3>

B.  0.33 mol

<h3>Explanation:</h3>

We are given;

Gauge pressure, P = 61 kPa (but 1 atm = 101.325 kPa)

                               = 0.602 atm

Volume, V = 5.2 liters

Temperature, T = 32°C, but K = °C + 273.15

thus, T = 305.15 K

We are required to determine the number of moles of air.

We are going to use the concept of ideal gas equation.

  • According to the ideal gas equation, PV = nRT, where P is the pressure, V is the volume, R is the ideal gas constant, (0.082057 L.atm mol.K, n is the number of moles and T is the absolute temperature.
  • Therefore, to find the number of moles we replace the variables in the equation.
  • Note that the total ball pressure will be given by the sum of atmospheric pressure and the gauge
  • Therefore;
  • Total pressure = Atmospheric pressure + Gauge pressure  

       We know atmospheric pressure is 101.325 kPa or 1 atm

Total ball pressure = 1 atm + 0.602 atm

                               = 1.602 atm

That is;

PV = nRT

n = PV ÷ RT

therefore;

n = (1.602 atm× 5.2 L) ÷ (0.082057 × 305.15 K)

  = 0.3326 moles

  = 0.33 moles

Therefore, there are 0.33 moles of air in the ball.

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Assuming that the change of volumen was done at constant pressure and the quantity of gas did not change, you use Charles' Law of gases, which is valid for ideal gases:

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71. Included drawing attached

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Answer : The grams of N_2 consumed is, 89.6 grams.

Solution : Given,

Mass of CaCN_2 = 265 g

Molar mass of CaCN_2 = 80 g/mole

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First we have to calculate the moles of CaCN_2.

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