Answer:
The answer to your question is C₂H₆O
Explanation:
Data
Molecular formula = C₆H₁₈O₃
Empirical formula = ?
Empirical formula is defined as the simplest ratio of the elements that form part of a molecule.
Process
To find the empirical formula find the greatest common factor of the subscripts.
6 18 3 2
3 9 3 3
1 3 1 3
1
The GCF is 3, so factor 3 of the molecular formula
3 ( C₂H₆O)
The result is the empirical formula C₂H₆O
POH is defined as the negative log base ten of the concentration of base. You have the concentration.
Answer : Option 'D' is correct.
= 
Explanation 1) : 1 m = 100 cm
or 
= 
= = 
Explanation 2) : 1 m = 1000 mm
= 
= =
Option 'D' is right.
Predict what will be observed in each experiment below. Rock candy is formed when excess sugar is dissolved in hot water followed by crystallization. A student wants to make two batches of rock candy. He finds an unopened box of "cane sugar" in the pantry. He starts preparing batch A by dissolving sugar in 500 mL of hot water (70 degree C). He keeps adding sugar until no more sugar dissolves in the hot water. He cools the solution to room temperature. He prepares batch B by dissolving sugar in 500 mL of water at room temperature until no more sugar is dissolved. He lets the solution sit at room temperature
a. It is likely that more rock candy will be formed in batch A.
b. It is likely that less rock candy will be formed in batch A.
c. It is likely that no rock candy will be formed in either batch.
d. I need more information to predict which batch is more likely to form rock candy.
Answer: Option A
Explanation:
More rock candy will be formed in the batch A because it is dissolved in hot water and less rock candy will be formed in batch B because the water is not hot.
Formation of the candies require hot water as the solubility of sugar is more in hot water as compared to normal water.
The sugar will be dissolved in water until the time all the space is filled sugar molecules.
Hence, the correct answer is Option A.
Mass percentage composition of carbon in the compound is the composition of carbon in the compound. This can be calculated by finding out the mass of carbon in the compound and the mass of the whole compound .
The compound formula is C2H5Cl
Mass of 1 mol of compound -64.5 g
Mass of carbon - 24 g
Mass percentage = 24/64.5 x100
Therefore mass composition percentage of carbon = 37.2%
