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2 years ago

Annalise observes a streak of light in the sky and says she is seeing a shooting star. What is she most likely observing?

Chemistry

2 answers:

Katena32 [7]2 years ago

7 0

Answer: A Meteor

Explanation:

Phoenix [80]2 years ago

5 0

Answes:

c) a meteor

Explanation:

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Which contain covalent bonds?

Ilia_Sergeevich [38]

The only compound that contains covalent bonds would be A. BCl4-.

3 0

2 years ago

When iron pyrite (FeS2) is heated in air, the process known as "roasting" forms sulfur dioxide and iron(III) oxide. When the equ

Ronch [10]

Answer:

The coefficient of O2 is 11

Explanation:

Step 1:

The equation for the reaction:

FeS2 + O2 → SO2 + Fe2O3

Step 2:

Balancing the equation. The equation can be balance as follow:

FeS2 + O2 → SO2 + Fe2O3

There are 2 atoms of Fe on the right side and 1 atom on the left. It can be balance by putting 2 in front of FeS2 as shown below:

2FeS2 + O2 → SO2 + Fe2O3

There are 4 atoms of S on the left side and 1 atom on the right side. It can be balance by putting 4 in front of SO2 as shown below:

2FeS2 + O2 → 4SO2 + Fe2O3

Now, there are a total of 11 atoms of O on the right side and 2 atoms on the left side. It can be balance by putting 11/2 in front of O2 as shown below:

2FeS2 + 11/2O2 → 4SO2 + Fe2O3

Multiply through by 2 to clear the fraction as shown below:

4FeS2 + 11O2 → 8SO2 + 2Fe2O3

Now the equation is balanced.

The coefficient of O2 is 11

8 0

2 years ago

Which substance absorbs 58.16 kJ of energy when 3.11 mol vaporizes? a)CH4 b)H2S c)CO2 d)NaCl

schepotkina [342]

Answer:

$H_2S$

Explanation:

Given the amount of heat absorbed and the amount of substance in moles, we may calculate the heat of vaporization. Heat of vaporization is defined as the amount of heat per 1 mole of substance required to evaporate that specific substance.

Based on the value of heat of vaporization, we will identify the substance. Firstly, let's calculate the heat of vaporization:

$\Delta H^o = \frac{58.16 kJ}{3.11 mol} = 18.7 kJ/mol$

Secondly, let's use any table for heat of vaporization values for substances. We identify that the heat of vaporization of $H_2S$ is 18.7 kJ/mol

8 0

2 years ago

If it takes one second to count two rice grains,calculate the time in years required to count a mole of rice grainrg.

Anuta_ua [19.1K]

Mole is 6,022*10^23

6,022 * 10^23 /2 (here are seconds) then /60 (minutes), then /60 (hours) /24 (days), then /365 (year) equals 9547818366311516,9965 years

every 4 years there's one day more in a year, so 9547818366311516,9965 /4 ( here are days) then / 365 = 6539601620761,31 years less.

the answer is 9547818366311516,9965 - 6539601620761,31 = 9541278764690755,6865 years to calculate the rice

5 0

2 years ago

Which of the following chemical equations does not correspond to a standard molar enthalpy of formation? a. Mg(s) + C(s) + 3/2 O

goblinko [34]

Answer:

N₂ $_{s}$ + O₂ $_{g}$ → 2NO $_{g}$

Explanation:

The given equations are:

Mg $_{s}$ + C $_{s}$ + $\frac{3}{2}$ O $_{g}$ → MgCO₃ $_{s}$

C $_{s}$ + $\frac{1}{2}$ O₂ $_{g}$ → CO $_{g}$

N₂ $_{s}$ + O₂ $_{g}$ → 2NO $_{g}$

N₂ $_{s}$ + 2O₂ $_{g}$ → N₂O $_{g}$

H₂ $_{g}$ + $\frac{1}{2}$ O $_{g}$ → HO $_{l}$

From the given equations only N₂ $_{s}$ + O₂ $_{g}$ → 2NO $_{g}$ does not correspond to an expression of the standard molar enthalpy of formation.

The heat of formation is the heat liberated or absorbed when one mole of a compound is formed from its constituent elements under standard conditions.

The equation must result in the formation of only one mole of the compound.

It could have been properly written as

$\frac{1}{2}$ N₂ $_{s}$ + $\frac{1}{2}$ O₂ $_{g}$ → NO $_{g}$

5 0

2 years ago