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nexus9112 [7]
2 years ago
13

How many atoms of oxygen are contained in 160 grams of N2O3?

Chemistry
2 answers:
musickatia [10]2 years ago
6 0
3.80 × 1024 grams containing
Nadusha1986 [10]2 years ago
6 0

The number  of oxygen  atoms that are contained  in 160 grams of N2O3  are 3.80   x10^24  atoms  ( answer C)

<u><em>Explanation</em></u>

Step 1: calculate  the moles  of N2O3

moles= mass  N2O3 /molar mass N2O3

molar mass of N2O3 = (14  x2) +( 16 x3) =76 g/mol

moles of  N2O3  = 160 g/ 76 g/mol = 2.105  moles


Step 2:  from the  moles of N2O3 find the moles of Oxygen

=moles of N2O3   x number of oxygen atoms in N2O3( 3)

= 3 x 2.105  =6.315 moles


Step 3:use  the Avogadro's  law to calculate the atoms of oxygen

that is according to Avogadro's  law  1 mole =   6.02 x10 ^23 atoms

                                                               6.315 moles= ? atoms

={ (6.315 moles x 6.02 x10 ^23 atoms) / 1 mole}  =3.80  x10^24 atoms





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OverLord2011 [107]

Answer : The number of moles of oxygen present in a sample are 11.3 moles.

Explanation :

The given compound is, Ni(CO)_4

By the stoichiometry we can say that, 1 mole of of Ni(CO)_4 has 4 moles of CO.

Or we can say that, 1 mole of of Ni(CO)_4 has 1 mole of nickel (Ni), 4 moles of carbon (C) and 4 moles of oxygen.

That means,

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7 0
2 years ago
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snow_tiger [21]

Answer:

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In order to describe the formation of the pi bond, first we must talk about the hybridization process, as this is involved in some important links.

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In this sense, the formation of pi bonds occurs thanks to the overlapping of a pair of lobes belonging to an atomic orbital over another pair of lobes that are in an orbital that is part of another atom.

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