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d1i1m1o1n [39]
2 years ago
11

As photosynthesis occurs in chloroplasts, O2 is produced from _____ via a series of reactions associated with _____. View Availa

ble Hint(s) As photosynthesis occurs in chloroplasts, O2 is produced from _____ via a series of reactions associated with _____. H2O … photosystem I CO2 … Calvin cycle CO2 … photosystem II H2O … photosystem II
Chemistry
1 answer:
Monica [59]2 years ago
6 0

Answer:

H₂O, Photosystem II

Explanation:

  • Photosynthesis is the process that enables autotrophs such as green plants and algae to generate food using water, carbon dioxide and energy from the sun.
  • It occurs in two phases, that is, the light-dependent phase and the light-independent phase.
  • During photosystem II energy from the sun is used to break-down water molecules to yield oxygen and hydrogen ions. Oxygen is released away to the atmosphere while hydrogen ions are used in the next phase to generate ATP molecules.

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If you perform the experiment described in investigation #15 by mixing 10 g of glue with 13 g of water and 8 g of sodium borate
Phantasy [73]

10 g of glue with 13 g of water ,

Mass ratio of the material can be calculated as:    

\frac{Mass of glue}{Mass of glue + Mass of water}  

\frac{10 g}{10 g + 13 g }  

\frac{10 g}{23 g }

8 g of sodium borate suspended in 11 g of water, mass ratio can be calculated as:

\frac{Mass of sodium borate}{Mass of sodium borate + Mass of water}  

\frac{ 8 g}{ 8 g + 11 g }  

\frac{8 g}{19 g }

3 0
2 years ago
Explain one way the water cycle affects climate. Use complete sentences.
ladessa [460]

Answer:

The water cycle will affect the climate by causing rain and snow.

Explanation:

if tempatures increase more rain fall will occur because more water evaporates in the air.

4 0
1 year ago
The concentration of ozone in a sample of air that has a partial pressure of O3 of 0.33 torr and a total pressure of air of 695
Goryan [66]

Answer:

0.047 %

Explanation:

Step 1: Given data

  • Partial pressure of ozone (pO₃): 0.33 torr
  • Total pressure of air (P): 695 torr

Step 2: Calculate the %v/v of ozone in the air

Air is a mixture of gases. We can find the %v/v of ozone (a component) in the air (mixture) using the following expression.

<em>%v/v = pO₃/P × 100%</em>

%v/v = 0.33 torr/695 torr × 100%

%v/v = 0.047 %

8 0
2 years ago
The piece of iron that miguel measured had a mass of 51.1 g and a volume of 6.63 cm 3 . what did miguel calculate to be the dens
likoan [24]
Given:
Mass, m = 51.1 g
Volume, V = 6.63 cm³

By definition, 
Density = Mass/Volume
              = (51.1 g)/(6.63 cm³)
              = 7.7074 g/cm³

In SI units,
Density = (7.7074 g/cm³)*(10⁻³ kg/g)*(10² cm/m)³
              = 7707.4 kg/m³

Answer: 7.707 g/cm³ or 7707.4 kg/m³

4 0
2 years ago
he first-order rate constant for the gas-phase decomposition of dimethyl ether, (CH3)2O → CH4 + H2 + CO is 3.2 ✕ 10−4 s−1 at 450
seropon [69]

Answer:

0.290 atm is the pressure of the system after 7.7min

Explanation:

The general first-order rate constant is:

ln [A] = -kt + ln [A]₀

<em>Where [A] is concentration of A in time t,</em>

<em>K is rate constant, 3.2x10⁻⁴s⁻¹</em>

<em>[A]₀ is initial concentration = 0.336atm.</em>

<em />

7.7 min are:

7.7min * (60s / 1min) = 462s

Solving:

ln [A] = -kt + ln [A]₀

ln [A] = -<em>3.2x10⁻⁴s⁻¹*462s</em> + ln [0.336atm]

ln [A] = -1.238

[A] =

<h3>0.290 atm is the pressure of the system after 7.7min</h3>

<em />

6 0
2 years ago
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