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crimeas [40]
2 years ago
10

This is the chemical formula for nickel tetracarbonyl (a powerfully poisonous liquid used in nickel refining) Ni(CO)4 A chemical

engineer has determined by measurements that there are 11.3 moles of carbon in a sample of nickel tetracarbonyl. How many moles of oxygen ar in the sample?
Chemistry
1 answer:
OverLord2011 [107]2 years ago
7 0

Answer : The number of moles of oxygen present in a sample are 11.3 moles.

Explanation :

The given compound is, Ni(CO)_4

By the stoichiometry we can say that, 1 mole of of Ni(CO)_4 has 4 moles of CO.

Or we can say that, 1 mole of of Ni(CO)_4 has 1 mole of nickel (Ni), 4 moles of carbon (C) and 4 moles of oxygen.

That means,

Number of moles of carbon = Number of moles of oxygen

As we are given that:

Number of moles of carbon = 11.3 moles

So, number of moles of oxygen = number of moles of carbon = 11.3 moles

Therefore, the number of moles of oxygen present in a sample are 11.3 moles.

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What mass of carbon dioxide could be made from 100 tonnes of calcium carbonate?
MA_775_DIABLO [31]
Total mass of CaCO3 = 40 amu of Ca + 12amu of C + 16×3 amu of oxygen = 100amu of CaCO3




i.e 100 tonnes of CaCO3 .


mass of CO2 = 12amu of C + 2× 16amu of O = 44 amu of CO2




mass % of CO2 in CaCO3 = (44/100)×100 =44%


i.e
44% of 100 tonnes is CO2.
=44 tonnes of CO2.

therefore, 44% of CO2 is present in CaCO3.








3 0
1 year ago
175 mL of Cl2 gas is held in a flexible vessel at
Gnoma [55]

Answer:

V₂ = 15.6 L

Explanation:

Given data:

Initial volume = 175 mL  (0.175 L)

Initial pressure = 1 atm

Initial temperature = 273 K

Final temperature = -5°C (-5+273 = 268 K)

Final volume = ?

Final pressure = 1.16 kpa (1.16/101=0.011 atm)

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 1 atm × 0.175 L × 268 K / 273 K × 0.011 atm

V₂ = 46.9 L / 3.003

V₂ = 15.6 L

7 0
2 years ago
Read 2 more answers
The volume of blood plasma in adults is 3.1 L. it's density is 1.03 g/cm3. Approximately how many pounds of blood plasma are the
e-lub [12.9K]
The important thing in this question is the unit. The mass equals density * volume. 3.1 L = 3.1 * 10^3 cm3. So the mass is 3.193*10^3 g. 1 pound = 453.95 g. So the answer is 7.04 pounds.
3 0
2 years ago
Read 2 more answers
How are NGC 1427A and U different? How are they the same?
agasfer [191]

Answer:

that looks pretty and also well NGC 1427A has no general shape, so it is an irregular galaxy. U has a bulge in the center and arms, so it is a spiral galaxy. They are similar in the both certain plenty of dust and gas. Both also have active star-forming sites.

3 0
1 year ago
Read 2 more answers
Why does 4.03/0.0000035 = 1.2 x 106, instead of a different number of significant figures?
jasenka [17]

Explanations:- As per the significant figures rule, In multiplication and division, we go with least number of sig figs.

4.03 has three sig figs where as 0.0000035 has two sig figs only, The zeros in this number are not sig figs as they are just holding the place values. As the least number of sig figs here is two, the answer needs to be reported with two sig figs only.

\frac{4.03}{0.0000035}=1.2*10^6



4 0
2 years ago
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