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Vikentia [17]
2 years ago
9

What is the poh of an aqueous solution at 25.0 °c that contains 1.35 × 10-8 m hydroxide ion?

Chemistry
1 answer:
ohaa [14]2 years ago
8 0
POH is defined as the negative log base ten of the concentration of base. You have the concentration.
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Select all true statements about hybridization, of a second-row element, changing from sp2 to sp3. (max of 3 choices) a. The ato
Neko [114]

Answer:

a. The atom will go from a two-dimensional configuration to a three dimensional configuration.

d. The bond angle will increase.

f. The number of unhybridized p orbitals will decrease.

Explanation:

Sp2 is the atomic bond in which orbitals mixes with only two orbitals. These orbitals form three sp2. When two carbon atoms are overlapped they form sigma bond by overlapping of sp2 bonds. Sp3 bond is created when there is one lone molecule available for combination. When the bonding is updated from sp2 to sp3 then unhybridized orbitals will decrease causing the bond angle to increase.

8 0
2 years ago
For a pure substance, the liquid and gaseous phases can only coexist for a single value of the pressure at a given temperature.
anastassius [24]

Answer:

No, it is not.

Explanation:

Most solutions do not behave ideally. Designating two volatile  substances as A and B, we can consider the following two cases:

Case 1: If the intermolecular forces between A and B molecules are weaker than  those between A molecules and between B molecules, then there is a greater tendency  for these molecules to leave the solution than in the case of an ideal solution. Consequently,  the vapor pressure of the solution is greater than the sum of the vapor  pressures as predicted by Raoult’s law for the same concentration. This behavior gives  rise to the positive deviation.

Case 2: If A molecules attract B molecules more strongly than they do their own  kind, the vapor pressure of the solution is less than the sum of the vapor pressures as  predicted by Raoult’s law. Here we have a negative deviation.

The benzene/toluene system is an exception, since that solution behaves ideally.

8 0
2 years ago
One mole of h2s gas escapes from a container by effusion in 77 seconds how long would it take one mole of nh3 gas to escape from
gizmo_the_mogwai [7]
The molar masses of H2S and NH3 are 34 and 17 g/mol, respectively. The equation that would best represent the given is,
                                  Rate A/Rate B = √(molar mass B/molar mass A)
Substituting,
                               x/77 = √(17 /34 )
                                 x = 54.4
Thus, it will take 54.4 seconds for NH3 to travel through the container. 
3 0
2 years ago
Read 2 more answers
A student mixed 20.00 grams of calcium nitrate, 10.00 grams of sodium nitrate, and 50.00 grams of aluminum nitrate in a 5.00 Lit
My name is Ann [436]

Answer:

M=0.213M

Explanation:

Hello,

In this case, for each nitrate-based salt, we compute the nitrate moles as shown below:

n_{NO_3^-}=20.00gCa(NO_3)_2*\frac{1molCa(NO_3)_2}{164.088 gCa(NO_3)_2} *\frac{2molNO_3^-}{1molCa(NO_3)_2} =0.244molNO_3^-

n_{NO_3^-}=10.00gNaNO_3*\frac{1molNaNO_3}{84.9947 gNaNO_3} *\frac{1molNO_3^-}{1molNaNO_3} =0.118molNO_3^-

n_{NO_3^-}=50.00gAl(NO_3)_3*\frac{1molAl(NO_3)_3}{212.996gAl(NO_3)_3} *\frac{3molNO_3^-}{1molAl(NO_3)_3} =0.704molNO_3^-

We notice calcium nitrate has two moles of nitrate ion, sodium nitrate has one and aluminium nitrate has three. Hence we add the moles to obtain the total moles nitrate ion:

n_{NO_3^-}^{Tot}=0.244+0.118+0.704=1.066molNO_3^-

Finally, we compute the molarity:

M=\frac{1.066molNO_3^-}{5.00L} \\\\M=0.213M

Regards.

6 0
2 years ago
ANSWER ASAP! WILL GIVE BRAINLIEST! A pan containing 20.0 grams of water was allowed to cook from a temperature of 95.0 degrees C
vodka [1.7K]

Answer:

C. 81 degrees Celsius

Explanation:

  • To solve this problem, we can use the relation:

<em>Q = m.c.ΔT,</em>

where, Q is the amount of heat released from water (Q = - 1200 J).

m is the mass of the water (m = 20.0 g).

c is the specific heat capacity of water (c of water = 4.186 J/g.°C).

ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = final T - 95.0°C).

<em>∵ Q = m.c.ΔT</em>

∴ (- 1200 J) = (20.0 g)(4.186 J/g.°C)(final T - 95.0°C ).

(- 1200 J) = 83.72 final T - 7953.

∴ final T = (- 1200 J + 7953)/83.72 = 80.67 °C ≅ 81.0 °C.

<em>So, the right choice is: C. 81 degrees Celsius </em>

<em></em>

3 0
2 years ago
Read 2 more answers
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