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lord [1]
2 years ago
8

A 25.0-g sample of ice at -6.5oC is removed from the freezer and allowed to warm until it melts. Given the data below, select al

l the options that correctly reflect the calculations needed to determine the total heat change for this process.
Melting point at 1 atm = 0,0°C; -2.09 J/g.°C; Cloud -4.21J/g °C, AH -6,02 kJ/mol
Check all that apply.

A. q for the temperature change from -6,5°C to 0.0°C is glven by 25.0 x 6.02 = 151 kJ
B. q for the phase change is given by 1.39 x 6.02 = 8.37 kJ
C. There are 3 separate heat change stages in this process.
D. The total heat change for the process is equal to +8.71 kJ
E. The total heat change for the process is equal to +350 kJ
Chemistry
1 answer:
alukav5142 [94]2 years ago
7 0

Answer:

B, D

Explanation:

The strategy here is to realize that the ice will be taken from -6.5 ºC to OºC where it will melt.

Lets call q₁ the heat required to bring the ice to 0ºc, q₂ the heat required to bring the phase change from solid to liquid.

q₁ is calculated from the expression

q₁ = s x m x ΔT where m is the mass, s the specific heat of ice ( 2.09 J/gºC ) and ΔT  the change in temperature.

q₂ the fusion enthalpy change   is calculated from the expression:

q₂ = C x ΔT

where C is the specific heat for the phase change , in this case named AH  given in kJ/mol.

We are given all the data needed to calculate q₁, q₂ and qtotal ( q₁ + q₂ )

q₁ = 25.0 g x ( 2.09 J/gºC) x ( 0 - ( -6.5 ºC ) )

q₁ = 339.6 J = 0.339 kJ

q₂ = (25 g/ 18 g/mol) x 6.02 kJ/mol = 1.39 x 6.02 kJ = 8.36 kJ

qtotal = 0.339 kJ + 8.36 kJ = 8.70 kJ

with these calculations, we can now proceed to answer the question:

(a) False AH is theheat capacity for the melting.

(b) True as we determined above

(c) False we only have one phase change, from solid (ice) to liquid

(d) True as calculated above

(e) False as determined in our calculations

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From the options provided for each element below, choose the properties that it may have based on its location in the periodic t
Mashutka [201]

<u>Answer: </u>The correct answer is Option A.

<u>Explanation:</u>

Fluorine is the 9th element in the periodic table which belongs to group 17 and period 2. It is a non-metal because it requires an electron to gain its stable electronic configuration.

The electronic configuration of this elements is: 1s^22s^22p^5

This element requires 1 electron to attain stable configuration. It is an insulator  and is not lustrous.

This element easily gains an electron and hence, is considered as a highly reactive non-metal.

Hence, the correct answer is Option A.

4 0
2 years ago
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A newly discovered element has two isotopes. one has an atomic weight of 120.9038 amu with 57.25% abundance. the other has an at
-Dominant- [34]
Atomic weight of the element = atomic weight of isotope 1 * abundance of isotope 1 +  atomic weight of isotope 2 * abundance of isotope 2

Atomic weight of the element = 120.9038 amu * 57.25% + 122.8831 amu * (1 - 57.25%)

Atomic weight of the element = 69.2174255 + 52.53252525 = 121.74995075

=> ~ 121.7500 <--------- answer
4 0
2 years ago
Read 2 more answers
A student obtained an unknown metal sample that weighed 65.3 g and at a temperature of 99.8oC, he placed it in a calorimeter con
lawyer [7]

Answer:

0.377 J/gºC

Explanation:

From the question given above, the following data were obtained:

Mass of metal (Mₘ) = 65.3 g

Initial temperature of metal (Tₘ) = 99.8 °C

Mass of water (Mᵥᵥ) = 43.7 g

Initial temperature of water (Tᵥᵥ) = 25.7 °C

Equilibrium temperature (Tₑ) = 34.5 °C

Specific heat capacity of water (Cᵥᵥ) = 4.18 J/gºC

Specific heat capacity of metal (Cₘ) =?

The specific heat capacity of metal can be obtained as illustrated below:

Heat lost by metal = heat gained by water.

MₘCₘ(Tₘ – Tₑ) = MᵥᵥCᵥᵥ(Tₑ – Cᵥᵥ)

65.3 × Cₘ (99.8 – 34.5) = 43.7 × 4.18 (34.5 – 25.7)

65.3Cₘ × 65.3 = 182.666 × 8.8

4264.09Cₘ = 1607.4608

Divide both side by 4264.09

Cₘ = 1607.4608 / 4264.09

Cₘ = 0.377 J/gºC

Therefore the specific heat capacity of the metal is 0.377 J/gºC

3 0
2 years ago
What is the molarity and molality of a solution that is 10.00 % by mass potassium hydrogen carbonate (KHCO3, 100.11 g/mol) and h
maksim [4K]

Answer: The molarity and molality of a solution is 1.06 M and 1.11 m respectively.

Explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

Molality=\frac{n\times 1000}{W_s}

where,

n = moles of solute  =

W_s = weight of solvent in g

10.00 g of potassium hydrogen carbonate in 100 g of solution

mass of solvent = mass of solution - mass of solute = (100.0-10.00) = 90.0 g

Molality=\frac{0.09985\times 1000}{90.0}=1.11m

2. Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n= moles of solute  = 0.09985

V_s = volume of solution in ml

Density of solution = 1036.5 g/L

Volume of solution =\frac{\text {mass of solution}}{\text {Density of solution}}=\frac{100.0g}{1.0650g/ml}=93.90ml

Molality= \frac{0.09985\times 1000}{93.90ml}=1.06M

4 0
2 years ago
Which reactants would lead to a spontaneous reaction?
balandron [24]

Answer: Option (b) is the correct answer.

Explanation:

The elements which have excess or deficiency of electrons will react readily.

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Atomic number of Cr is 24 and electronic configuration of Cr is [Ar]4s^{1}3d^{5}. This configuration is not stable.

Atomic number of Fe is 26 and electronic configuration of Fe is [Ar]4s^{2}3d^{6}. This configuration is stable.

Atomic number of Cu is 29 and electronic configuration of Cu^{2+} is [Ar]4s^{0}3d^{9}. This configuration is not stable.

Atomic number of Al is 13 and electronic configuration of Al is 1s^{2}2s^{2}2p^{6}3s^{2}3p^{1}. This configuration is not stable.

Atomic number of Ba is 56 and electronic configuration of Ba^{2+} is [Kr]4d^{10}5s^{2}5p^{6}. This configuration is stable.

Atomic number of Mg is 12 and electronic configuration of Mg^{2+} is 1s^{2}2s^{2}2p^{6}. This configuration is stable.

Atomic number of Sn is 50 and electronic configuration of Sn is [Kr]4d^{10}5s^{2}5p^{2}. This configuration is stable.

Thus, we can conclude that out of the given options, only Fe and Cu^{2+} reactants would lead to a spontaneous reaction as they have incomplete sub-shells. Therefore, in order to gain stability they will readily react.


8 0
2 years ago
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