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ArbitrLikvidat [17]
2 years ago
11

When the valve between the two containers is opened and the gases allowed to mix, how does the volume occupied by the n2 gas cha

nge? express your answer using two significant figures?

Chemistry
2 answers:
schepotkina [342]2 years ago
4 0
Missing question: 
Nitrogen: <span>2.0 L; </span>1.0 atm; 25°<span>C.
Oxygen: 3</span>.0 L; 2.0 atm; 25°C.
<span>When the valve between the two containers is opened, nitrogen gas moves from one container to another container and gases are mixed together, total volume of nitrogen is than:
V(nitrogen) = 2,0 L + 3,0 L = 5,0 L.</span>
sertanlavr [38]2 years ago
3 0

The volume occupied by the N₂ gas change : <u>5 L</u>

<h3>Further explanation </h3>

There are several gas equations in various processes:

  • 1. The ideal ideal gas equation
<h3>PV = nRT </h3>

PV = NkT

N =number of gas particles

n = number of moles

R = gas constant (8,31.10 ^ 3 J / kmole K

k = Boltzmann constant (1,38.10 ^ -23)

n = = N / No

n = m / m

n = mole

No = Avogadro number (6.02.10 ^ 23)

m = mass

M = relative molecular mass

  • 2. Avogadro's hypothesis

In the same temperature and pressure, in the same volume conditions, the gas contains the same number of molecules

So it applies: the ratio of gas volume will be equal to the ratio of gas moles

<h3> V1: V2 = n1: n2 </h3>

  • 3. Boyle's Law

At a fixed temperature, the gas volume is inversely proportional to the pressure applied

<h3> p1.V1 = p2.V2 </h3>

  • 3. Charles's Law

When the gas pressure is kept constant, the gas volume is proportional to the temperature

<h3> V1 / T1 = V2 / T2 </h3>

  • 4. Gay Lussac's Law

When the volume is not changed, the gas pressure in the tube is proportional to its absolute temperature

<h3> P1 / T1 = P2 / T2 </h3>

  • 5. Law of Boyle-Gay-Lussac

Combined with Boyle's law and Gay Lussac's law

P1.V1 / T1 = P2.V2 / T2

P1 = initial gas pressure (N / m2 or Pa)

V1 = initial gas volume (m3)

P2 = gas end pressure

V2 = the final volume of gas

T1 = initial gas temperature (K)

T2 = gas end temperature

From the attached picture, it shows that if the stopvalve is opened then the two gas systems / containers will be interconnected (almost the same as the related vessel system). So that the total volume filled by the two gases (O₂ and N₂) becomes:

total volume = O₂ container volume + N₂ container volume

total volume = 3 L + 2 L

total volume = 5 L

<h3>Learn more </h3>

a description of Charles’s law

brainly.com/question/5056208

Charles's law

brainly.com/question/9510865

State Boyle's, Charles's, and Gay-Lussac's laws

brainly.com/question/980439

Keywords: containers, valve, O₂, N₂, volume, gas

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4 0
2 years ago
The incomplete table below shows selected characteristics of gas laws.
Elenna [48]

Explanation :

In the given case different law related to gas is given. The attached figure shows the required solution.

Boyle's law states that the pressure is inversely proportional to the volume of the gas i.e.

P\propto \dfrac{1}{V}

PV=k

k is a constant.

Charle's law states that the volume of directly proportional to the temperature of the gas.

V\propto T

V=kT

Combined gas law is the combination of the pressure, volume and the temperature of the gas i.e.

\dfrac{PV}{T}=k

Hence, this is the required solution.

6 0
2 years ago
Read 2 more answers
If the symbol X represents a central atom, Y represents outer atoms, and Z represents lone pairs on the central atom, the struct
MA_775_DIABLO [31]

Answer:

1. sp  = XY₂

2. sp²  = XY₂Z, XY₃

3. sp3³ = XY₄, XY₂Z₂, XY₃Z

4. sp³d  = XY₅, XY₂Z₃, XY₃Z₂, XY₄Z

5. sp³d² = XY₆, XY₄Z₂, XY₅Z

Explanation:

this is quite dicey, so it should be looked into carefully.

we would classify each of the abbreviation according to their  hybridization and it electron domain.

⇒ sp hybridization = XY₂

in this, we can see that the central atom X is bonded to two outer atoms Y.

this makes the no of hybrid orbitals and the no of sigma bonds both 2.

electron domain = 2.

⇒ sp² hybridization = XY₂Z, XY₃

Here we can see the central atom X bonded with three outer atoms Y in XY₂Z and in XY₃. For XY₂Z molecule, the no of sigma bonds is 2 and the no of hybrid orbitals is 3. While for XY₃ molecule, the no of sigma bonds is 3 while the no of hybrid orbital is 3.

electron domain = 3.

⇒ sp³ hybridization = XY₄, XY₂Z₂, XY₃Z

for XY₄ molecule, the central atom X is bonded with four outer atoms Y. It has 4 numbers of both the sigma and orbital atoms.

In XY₂Z₂, the central atom X is bonded to 2 outer atoms Y, and has 2 lone pairs Z. From this, the no of hybrid orbitals is 4 and the no of sigma bonds is 2, with 2 lone pairs causing the sp³ hybridization.

⇒ sp³d hybridization = XY₅, XY₂Z₃, XY₃Z₂, XY₄Z

for all the molecules listed above, the sum of both the lone pairs and the outer atoms both give a total of 5, hence have the sp³d structure, viz;

XY₂Z₃:

total electron domain = 2+3 = 5  

XY₃Z₂:

total electron domain = 2+3 = 5

XY₄Z:

total electron domain = 1+4 = 5

⇒ sp³d² hybridization = XY₆, XY₄Z₂, XY₅Z

Same thing goes for the above molecule, where the sum of both the outer atoms and the lone pairs gives a total of 6 as can be seen in the example below.

XY4Z2:

total electron domain = 2+4 = 6

cheers, i hope this helps.

5 0
2 years ago
A 15.00g solid mixture containing Ca(OH)2, among other non-basic components, was neutralized with 0.2000g of HCl. What was the m
azamat

Answer:

1.373 wt% Ca(OH)₂

Explanation:

Sample mix = 15.0g

Ca(OH)₂(aq) + 2HCl(aq) => CaCl₂(aq) + 2H₂O(l)

moles HCl = 0.2000g / 36 g·mol⁻¹ 0.0056 mol

moles Ca(OH)₂ = 1/2(moles HCl) = 1/2(0.0056 mol) = 0.0028 mol

mass Ca(OH)₂ = 0.0028 mol ( 74 g/mol ) = 0.206 g

mass % Ca(OH)₂ = (0.206/15.0)100% = 1.373 wt%

3 0
2 years ago
Using periodic trends, place the following bonds in order of increasing ionic character. Si-P Si-Cl Si-S Using periodic trends,
mars1129 [50]

Answer: Option (5) is the correct answer.

Explanation:

An ionic bond is formed by transfer of electrons between the two chemically combining atoms. Whereas a covalent bond is defined as the bond formed by sharing of electrons between the two chemically combining atoms.

When electronegativity difference is from 0.0 to 0.4 then bond formed between the two atoms is non-polar covalent in nature.

When electronegativity difference is greater than 0.4 and less than 1.7 then bond between the two atoms is a polar covalent bond.

When electronegativity difference is 1.7 or greater than the bond formed is ionic in nature.

Therefore, electronegativity difference of the given species is as follows.

Si-P = 2.1 - 1.8 = 0.3

Si-Cl = 3.0 - 1.8 = 1.2

Si-S = 2.5 - 1.8 = 0.7

Thus, we can conclude that given bonds are placed in order of increasing ionic character as follows.

                           Si-P < Si-S < Si-Cl

6 0
2 years ago
Read 2 more answers
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