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olga55 [171]
2 years ago
12

1, Recall all the models you described in task 1. Think about the results each model would predict for the experiment with hydro

gen gas. Which models of the atom does the experimental evidence support? Explain why these models are compatible with the experimental results. 2. Which models of the atom in task 1 are not supported by the results of the hydrogen gas experiment? For each of these models, explain the experimental results that the model would predict. models are daltons, thomsons, rutherfords and bohrs
Chemistry
2 answers:
maksim [4K]2 years ago
7 0

Answer:

Do you have a picture of the models?

Explanation:

I can not answer if there is no pictures

Papessa [141]2 years ago
3 0

Answer:

The models in task 1 had been dalton's, Thomson's, Ruthordord's, and Bohr's.

A gas discharge tube consists of a gas-filled tube equipped with a metal electrode at every end. In this case, the gas used is hydrogen. An electric current is passed through the tube. The electrons in the hydrogen soak up energy from the electric current and get excited to a higher energy level. As the electrons return to their original energy state, known as the ground state, they emit light of a specific color. The shade of the light relies upon on the amount of energy that it carries. This energy is the difference in energy of the excited state and the ground state. Particles of different gases emit light carrying unique amounts of energy and, as a result, different colors. Hydrogen emits four visible colorations of light.

Explanation:

I have the same class, this is just the answer i came up with, hope it helps.

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Old photographic flashbulbs burn magnesium metal in a reaction that causes a flash of brilliant white light. A photographer woul
OLga [1]

Answer is: A. Chemical energy to electromagnetic energy and thermal energy.  

Balanced chemical reaction: 2Mg(s) + O₂(g) → 2MgO(s) + energy.

This is chemical change (chemical reaction), because new substance (magnesium oxide MgO) is formed, the atoms are rearranged and the reaction is followed by an energy change (exothermic reaction because energy is released).

Chemical changes (chemical synthesis) is when a substance combines with another (in this example magnesium and oxygen) to form a new substance.


5 0
2 years ago
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If the actual yield of the reaction was 75% instead of 100%, how many molecules of no would be present after the reaction was ov
artcher [175]
To be able to answer this equations, we must set given information. Suppose the reaction to yield NO is:

N₂ + O₂ → 2 NO

Next, suppose you have 1 g of each of the reactants. Determine first which is the limiting reactant.

1 g N₂ (1 mol N₂/ 28 g)(2 mol NO/1 mol N₂)= 0.07154 mol NO present

Number of molecules = 0.07154 mol NO(6.022×10²³ molecules/mol)
<em>Number of molecules = 4.3×10²² molecules NO present</em>
8 0
2 years ago
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Compound a on ozonolysis yields acetophenone and propanal. what is the structure of compound a? 1-phenyl-1-hexene 1-phenyl-2-pen
astra-53 [7]
Answer:
            2-Phenyl-2-Penetene on ozonolysis <span>yields acetophenone and propanal.

Explanation:
                   The tricky way to solve such questions is to simply break the double bond in alkene and place oxygen atom at each broken half double bond making it carbonyl group. The reaction of given statement is as follow,</span>

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2 years ago
Why a slow growing forest can have a very low NPP and yet store a massive amount of biomass.
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Net Primary Productivity ... the amount of biomass present in an ecosystem at a particular time .... Explain why a slow growing forest can have a very low NPP and yet store a massive amount of biomass.
8 0
2 years ago
A 40.0 mL sample of 0.25 M KOH is added to 60.0 mL of 0.15 M Ba(OH)2. What is the molar concentration of OH-(aq) in the resultin
solmaris [256]

Answer:

C) 0.28 M

Explanation:

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Moles =Molarity \times {Volume\ of\ the\ solution}

Potassium hydroxide will furnish hydroxide ions as:

KOH\rightarrow K^{+}+OH^-

Given :

<u>For Potassium hydroxide : </u>

Molarity = 0.25 M

Volume = 40.0 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 40.0×10⁻³ L

Thus, moles of hydroxide ions furnished by Potassium hydroxide is same as the moles of Potassium hydroxide as shown below:

Moles =0.25 \times {40.0\times 10^{-3}}\ moles

Moles of hydroxide ions by Potassium hydroxide = 0.01 moles

Barium hydroxide will furnish hydroxide ions as:

Ba(OH)_2\rightarrow Ba^{2+}+2OH^-

Given :

<u>For Barium hydroxide : </u>

Molarity = 0.15 M

Volume = 60.0 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 60.0×10⁻³ L

Thus, moles of hydroxide ions furnished by Barium hydroxide is twice the moles of Barium hydroxide as shown below:

Moles =2\times 0.15 \times {60.0\times 10^{-3}}\ moles

Moles of hydroxide ions by Barium hydroxide = 0.018 moles

Total moles = 0.01 moles + 0.018 moles = 0.028 moles

Total volume = 40.0×10⁻³ L + 60.0×10⁻³ L = 100×10⁻³ L

Concentration of hydroxide ions is:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity_{OH^-}=\frac{0.028 }{100\times 10^{-3}}

<u> The final concentration of hydroxide ion = 0.28 M</u>

5 0
2 years ago
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