Answer:
The formula of the conjugate base anion would be CH₃CH₂CH₂CH₂CH₂COO⁻.
Kindly see the attachment for the reaction.
Explanation:
Hexanoic acid on reaction with water gets deprotonated and leads to the formation of carboxylate anion.
Hexanoic acid is a proton donor when water abstracts proton from hexanoic acid. Also water accepts a proton donated by hexanoic acid so water is a proton acceptor.
The bronsted -lowry acid base concepts states that any substance that donates a proton or has the capacity is a bronsted acid and any substance which has the capacity to accept proton is a bronsted base.
So here in this case Hexanoic acid is a proton donor as it is donating its acidic proton and water is acting as a bronsted base as it is accepting the proton.
As soon as an acid is deprotonated it generates its conjugate base anion.
As soon as an base is protonated it generates a its conjugate acid .
In this reaction :
CH₃CH₂CH₂CH₂CH₂COOH +H₂O→CH₃CH₂CH₂CH₂CH₂COO⁻+H₃O⁺
In left hand side hexanoic acid is a bronsted acid and H₂O is the bronste base.
In right hand side the CH₃CH₂CH₂CH₂CH₂COO⁻ acts a bronsted base and H₃O⁺ acts as a bronsted acid.
The model would look something like the image below.
There would be a <em>central nucleus</em> containing <em>20 protons</em> and <em>20 neutrons</em>.
Surrounding the nucleus would be four concentric rings (energy levels) containing <em>20 electron</em>s.
Going out from the nucleus, the number of electrons in each ring would
be <em>2, 8, 8, 2</em>.
<u>Answer:</u> The mass percent of hydrogen in methyl acetate is 8 %
<u>Explanation:</u>
The given chemical formula of methyl acetate is
To calculate the mass percentage of hydrogen in methyl acetate, we use the equation:
Mass of hydrogen = (6 × 1) = 6 g
Mass of methyl acetate = [(3 × 12) + (6 × 1) + (2 × 16)] = 74 g
Putting values in above equation, we get:
Hence, the mass percent of hydrogen in methyl acetate is 8 %