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pshichka [43]
2 years ago
13

One of the substances that give wet goats and dirty gym socks their characteristic odors is hexanoic acid, CH3CH2CH2CH2CH2CO2H,

which is a monoprotic weak acid. Write the formula for the conjugate base of this acid. Write the equation for the reaction between this acid and water, and indicate the BrønstedLowry acid and base for the forward reaction. (The acidic hydrogen atom is on the right side of the formula.)

Chemistry
1 answer:
lilavasa [31]2 years ago
9 0

Answer:

The formula of the conjugate base anion would be CH₃CH₂CH₂CH₂CH₂COO⁻.

Kindly see the attachment for the reaction.

Explanation:

Hexanoic acid on reaction with water gets deprotonated and leads to the formation of carboxylate anion.

Hexanoic acid is a proton donor when water abstracts proton from hexanoic acid. Also water accepts a proton donated by hexanoic acid so water is a proton acceptor.

The bronsted -lowry acid base concepts states that any substance that donates a proton or has the capacity is a bronsted acid and any substance which has the capacity to accept proton is a bronsted base.

So here in this case Hexanoic acid is a proton donor as it is donating its acidic proton and water is acting as a bronsted base as it is accepting the proton.

As soon as an acid is deprotonated it generates its conjugate base anion.

As soon as an base is protonated it generates a  its conjugate acid .

In this reaction :

CH₃CH₂CH₂CH₂CH₂COOH +H₂O→CH₃CH₂CH₂CH₂CH₂COO⁻+H₃O⁺

In left hand side hexanoic acid is a bronsted acid and H₂O is the bronste base.

In right hand side the CH₃CH₂CH₂CH₂CH₂COO⁻ acts a bronsted base and H₃O⁺ acts as a bronsted acid.

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A sample of an alloy of aluminum contains 0.0898 mol Al and 0.0381 mol Mg. What are the mass percentages of Al and Mg in the all
blondinia [14]

Answer:

Al 72.61%

Mg 27.39%

Explanation:

To obtain the mass percentages, we need to place the individual masses over the total mass and multiply by 100%.

If we observe clearly, we can see that the parameters given are the moles. We need to convert the moles to mass.

To do this ,we need to multiply the moles by the atomic masses. The atomic mass of aluminum is 27 while that of magnesium is 24.

Now, the mass of aluminum is thus = 27 * 0.0898 = 2.4246g

The mass of magnesium is 0.0381 * 24 = 0.9144g

We can now calculate the mass percentage.

The total mass is 0.9144 + 2.4246 = 3.339g

% mass of Al = 2.4246/3.339 * 100 = 72.61%

% mass of Mg = 0.9144/3.39 * 100 = 27.39%

7 0
2 years ago
Read 2 more answers
Cherylanne mixes together Chemical A and Chemical B in a test tube, forming Chemical C. The mixture instantly turns cool to the
Anarel [89]

Answer:

Chemicals A and B form an endothermic reaction, and chemicals C and D form an exothermic reaction.

Explanation:

The reaction that produced chemical C is an endothermic reaction whereas, the reaction between C and D is an exothermic one.

An exothermic change is one in which heat is liberated to the surroundings. So the surrounding becomes hotter at the end of the reaction.

An endothermic reaction is a change in which heat is absorbed from the surrounding and hence the surrounding colder at the end of the change.

  • We can see that the first reaction is endothermic.
  • The second reaction is exothermic.
7 0
1 year ago
Read 2 more answers
2. A quantity of 1.922g of methanol (CH3OH) was burned in a constant-volume
Cerrena [4.2K]
Mass of methanol (CH3OH) = 1.922 g
Change in Temperature (t) = 4.20°C
Heat capacity of the bomb plus water = 10.4 KJ/oC
The heat absorbed by the bomb and water is equal to the product of the heat capacity and the temperature change.
Let’s assume that no heat is lost to the surroundings. First, let’s calculate the heat changes in the calorimeter. This is calculated using the formula shown below:
qcal = Ccalt
Where, qcal = heat of reaction
Ccal = heat capacity of calorimeter
t = change in temperature of the sample
Now, let’s calculate qcal:
qcal = (10.4 kJ/°C)(4.20°C)
= 43.68 kJ
Always qsys = qcal + qrxn = 0,
qrxn = -43.68 kJ
The heat change of the reaction is - 43.68 kJ which is the heat released by the combustion of 1.922 g of CH3OH. Therefore, the conversion factor is:
5 0
1 year ago
6. What is the molarity of 1.35 mol H2So4 in 245<br><br> mL of solution?
vovikov84 [41]

Answer:

5.51mol/L

Explanation:

Number of moles = 1.35moles

Volume of the solution = 245mL = 245*10^-3L = 0.245L

Molarity of a solution is the defined as the number of moles of a solute dissolved in 1L of the solution.

1.35 moles = 0.245L

X moles = 1L

X = (1.35 * 1) / 0.245

X = 5.51mol/L

The molarity of the solution is 5.51mol/L

7 0
2 years ago
in a mixture of helium and chlorine, occupying a volume of 12.8 l at 605.6 mmhg and 21.6 oc, it is found that the partial pressu
rodikova [14]

Answer:

Mass of sample = 8.483 g

Explanation:

Given data;

Volume of mixture = 12.8 L

Pressure = 605.6 mmHg    ( 605.6 / 760 = 0.797 atm)

Temperature = 21.6 °C   (21.6 + 271.15 = 294.8 K)

Partial pressure of chlorine = 143 mmHg    ( 143/760 = 0.19 atm)

Solution:

First of all we will determine the number of moles of mixture.

PV = nRT

n = PV/RT

n = 0.797atm × 12.8L / 0.0821 atm. dm³ mol⁻¹ K⁻¹ ×294.8 K

n = 10.202 / 24.2031

n = 0.422 mol

partial pressure of chlorine is 0.19 atm so mole fraction is,

mole fraction = 0.19/0.797

mole fraction = 0.24

moles of chlorine = 0.24 × 0.422 = 0.1013 mol

moles of helium = moles of mixture - moles of chlorine

moles of helium = 0.422 - 0.1013

moles of helium = 0.3207 mol

Mass of chlorine = moles × molar mass

Mass of chlorine = 0.1013 mol × 71 g/mol

Mass of chlorine = 7.2 g

Mass of helium = moles × molar mass

Mass of helium = 0.3207 mol × 4 g/mol

Mass of helium = 1.283 g

Mass of sample = mass of chlorine + mass of helium

Mass of sample = 7.2 g + 1.283 g

Mass of sample = 8.483 g

5 0
2 years ago
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