A mutation occurs in a cell. Which sequence best represents the correct order of the events involved for this mutation to affect
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Answer:
The chemical engineer should report average volume of 15.34 L.
Explanation:
Volume of Macon = 0.519 L
Volume of Allegheny = 44.67 L
Volume of Doheny = 0.826 L
Average of the volume of the pollutants:
The rule apply for the addition and subtraction is :
The least precise number present after the decimal point determines the number of significant figures in the answer.
Here the 44.67 has two significant digit after decimal point.So the answer will be reported as in with 2 significant figures after decimal point.
The chemical engineer should report average volume of 15.34 L.
Answer:- Mole fraction of methane in the original gas mixture is 0.854.
Solution:- From given volume, pressure and temperature, we could calculate the total moles of the gaseous mixture of methane and propane using ideal gas law as:
PV = nRT
V = 2.50 L
P = 1.45 atm
T = 20 + 273 = 293 K
Let's plug in the values in the equation:
n = 0.151
Let's say the solution has X moles of methane. Then moles of propane would be = (0.151 - X)
The combustion equations of methane and propane are:
From methane balanced equation, there is 1:1 mol ratio between methane and carbon dioxide. So, X moles of methane would produce X moles of carbon dioxide.
From balanced equation of propane, there is 1:3 mol ratio between propane and carbon dioxide. So, (0.151 - X) moles of propane would give 3(0.151 - X) moles of carbon dioxide.
So, total moles of carbon dioxide that we would get from methane and propane combustion are:
X + 3(0.151 - X)
From given data, 8.60 g of carbon dioxide are formed by the combustion of gas mixture.
moles of Carbon dioxide =
moles of carbon dioxide = 0.195 mol
Hence, 0.195 = X + 3(0.151 - X)
Let's solve this for X as:
0.195 = X + 0.453 - 3X
0.195 = 0.453 - 2X
2X = 0.453 - 0.195
2X = 0.258
X = 0.129
So, there are 0.129 moles of methane in the mixture.
moles of propane = 0.151 - 0.129 = 0.022
mole fraction of methane =
mole fraction of methane =
mole fraction of methane = 0.854
Hence, the mole fraction of methane gas in the original gas mixture is 0.854.