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Zigmanuir [339]
1 year ago
10

The nucleoside adenosine exists in a protonated form with a pKa of 3.8. The percentage of the protonated form at pH 4.8 is close

st to:
Chemistry
1 answer:
Natasha_Volkova [10]1 year ago
6 0

Answer:

Ok:

Explanation:

So, you can use the Henderson-Hasselbalch equation for this:

pH = pKa + log(A^-/HA) where A- is the conjugate base of the acid. In other words, A- is the deprotonated form and HA is the protonated.

We can solve that

1 = log(A^-/HA\\) and so 10 = A^-/HA or 10HA = A-.  For every 1 protonated form of adenosine (HA), there are 10 A-. So, the percent in the protonated form will be 1(1+10) or 1/11 which is close to 9 percent.

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How many pints of a 30% sugar solution must be added to a 5 pint of a 5% sugar solution to obtain a 20% sugar solution?
ser-zykov [4K]

You must add 7.5 pt of the 30 % sugar to the 5 % sugar to get a 20 % solution.

You can use a modified dilution formula to calculate the volume of 30 % sugar.

<em>V</em>_1×<em>C</em>_1 + <em>V</em>_2×<em>C</em>_2 = <em>V</em>_3×<em>C</em>_3

Let the volume of 30 % sugar = <em>x</em> pt. Then the volume of the final 20 % sugar = (5 + <em>x</em> ) pt

(<em>x</em> pt×30 % sugar) + (5 pt×5 % sugar) = (<em>x</em> + 5) pt × 20 % sugar

30<em>x</em> + 25 = 20x + 100

10<em>x</em> = 75

<em>x</em> = 75/10 = 7.5

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For the nitrogen fixation reaction, 3h2(g) + n2(g) 2nh3(g), kc = 6.0 × 10–2 at 500°c. if 0.250 m h2 and 0.050 m nh3 are present
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The maximum number of electrons that are possible at a given energy level depends on the number of ____ at the energy level.
VMariaS [17]

Answer:

  • <u><em>     orbitals      </em></u>

Explanation:

Each orbital may contain a maximum of two electrons.

The energy level is the principal quantum number: 1, 2, 3, 4, 5, 6, 7.

The principal quantum number limits the kind of orbital (ℓ ) and the number of orbitals (mℓ ).

I. Principal quantum number, n = 1

  Angular or orbital quantum number : ℓ = 0 ⇒ ortibal s

  Magnetic quantum number:  mℓ = 0

                                 ⇒ number of orbitals 1 ⇒ number of electrons: 2

                         

II. Principal quantun number, n = 2

  Angular or orbital quantum number : ℓ = 0 and 1 ⇒ ortibal s and p

  Magnetic quantum number:  

                                            for ℓ:  mℓ = 0: 1 s ortibal

                                            for ℓ = 1: mℓ = -1, 0, and +1:  3 p ortitals

                                 ⇒ number of orbitals 4 ⇒ number of electrons: 8

III. Principal quantun number, n = 3

    Angular or orbital quantum number : ℓ = 0, 1, and 2 ⇒ ortibal s, p and d

    Magnetic quantum number:  

                                            for ℓ:  mℓ = 0: 1 s ortibal

                                            for ℓ = 1: mℓ = -1, 0, and +1:  3 p ortitals

                                            for ℓ = 2: mℓ = -2, -1, 0, +1, and +2:  5 d ortitals

                                 ⇒ number of orbitals 9 ⇒ number of electrons: 18

IV. Principal quantun number, n = 4

    Angular or orbital quantum number : ℓ = 0, 1, 2, and 3 ⇒ ortibal s, p, d and f

    Magnetic quantum number:  

                                            for ℓ:  mℓ = 0: 1 s ortibal

                                            for ℓ = 1: mℓ = -1, 0, and +1:  3 p ortitals

                                            for ℓ = 2: mℓ = -2, -1, 0, +1, and +2:  5 d ortitals

                                            for ℓ = 3: mℓ = ±3, ±2, ±1, and 0: 7 f ortitals

                                 ⇒ number of orbitals 16 ⇒ number of electrons: 32.

Thus, you have:

energy level, n    maximum number of     maximum number of

                             orbitals                           electrons

      1                           1                                      2

      2                          4                                     8

      3                          9                                    18

      4                          16                                   32

Those numbers follow a rule: n² and 2n². You can verify that the previous numbers are in accordance with those formulas.

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2 years ago
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