Explain why you hear a “whoosh” sound when you open a can containing a carbonated drink. Which gas law applies?

2 answers:

6 0

Carbonated drinks have the air under pressure so that carbon bubbles are forced into the drink, keeping it carbonated. So when you open a can, the air under pressure in the can comes out of the can at a high speed, making a "whooshing" sound. The gas law that applies to this concept is the Boyle's Law (PV=k or P1V1=P2V2).

Ad libitum [116K]1 year ago

3 0

Answer:

sorry the other one is a very bad answer i just took the test so this should. good luck

Explanation:

The carbon dioxide in the head space above the liquid is at higher pressure than atmospheric pressure outside the can.

The gas is at a lower volume initially but suddenly has a larger volume available when the can is opened.

The change in pressure as the gas rapidly moves to become dispersed through its new volume causes the “whoosh” sound.

The gas law that applies is Boyle’s law.

You might be interested in

Consider the following equilibrium system: 3O2(g) 2O3(g); Keq = 1 Which equation compares the concentration of oxygen and ozone

Rashid [163]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

3O2(g) <--> 2O3(g);

Keq = 1 = [O3]^2/[O2]^3

So [O2]^3 = [O3]^2

Thus A) is correct

7 0

1 year ago

Read 2 more answers

Which liquid materials have strong odor and weak odor?

densk [106]

Odor refers to the fragrance caused by one or more volatilized chemical compounds. It can be strong or weak. 
Strong odor have: Sodium Hypochlorite, Muriatic Acid, Sulphuric Acid, Ammunlom Sulfide. Butyl ,Butyric Acid, Pyridine

Weak Odors have Spray Glue, Dry Erase Markers, Paint cleaners. Water.

5 0

1 year ago

Coal gasification is a multistep process to convert coal into cleaner-burning fuels. In one step, a coal sample reacts with supe

ddd [48]

Answer :

The enthalpy of reaction is, -187.6 kJ/mol

The total heat will be, -2251 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

(a) The formation of $CH_4$ will be,