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Oxana [17]
2 years ago
13

Which equation represents the total ionic equation for the reaction of HNO3 and NaOH? Upper H superscript plus, plus upper O upp

er H superscript minus right arrow upper H subscript 2 upper O. Upper H upper N upper O subscript 3 plus upper N a upper O upper H right arrow upper N a upper N upper O subscript 3 plus upper H subscript 2 upper O. Upper H superscript plus, plus upper N upper O subscript 3 superscript minus plus upper N a superscript plus, plus upper O upper H superscript minus right arrow upper N a superscript plus, plus upper N upper O subscript 3 superscript minus, plus upper H subscript 2 upper O. Upper H superscript plus, plus upper N upper O subscript 3 superscript minus, plus upper O upper H superscript minus right arrow upper N upper O subscript 3 superscript minus, plus upper H subscript 2 upper O.
Chemistry
2 answers:
DIA [1.3K]2 years ago
6 0

Answer:

Total Ionic equation:

H⁺(aq) + NO₃⁻ (aq) + Na⁺(aq) + OH⁻(aq) → H₂O(l) + Na⁺(aq) + NO₃⁻ (aq)

Explanation:

Chemical equation:

HNO₃ + NaOH →  NaNO₃ + H₂O

Balanced chemical equation:

HNO₃(aq) + NaOH(aq) →  NaNO₃(aq) + H₂O(l)

Total Ionic equation:

H⁺(aq) + NO₃⁻ (aq) + Na⁺(aq) + OH⁻(aq) → H₂O(l) + Na⁺(aq) + NO₃⁻ (aq)

Net ionic equation:

H⁺(aq) + OH⁻(aq) → H₂O(l)  

The NO₃⁻ (aq)  and Na⁺ (aq) are spectator ions that's why these are not written in net ionic equation. The water can not be splitted into ions because it is present in liquid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation

Nonamiya [84]2 years ago
3 0

Answer:

Its C on edge2020

Explanation:

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Mass Fraction= \frac{mass 1 Proton}{mass H atom} = \frac{1,007276 u}{1,007825}=0,9995

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When adjusted for any changes in ΔHΔH and ΔSΔS with temperature, the standard free energy change ΔG∘TΔGT∘Delta G_{T}^{\circ} at
STALIN [3.7K]

The equilibrium constant is 0.0022.

Explanation:

The values given in the problem is

ΔG° = 1.22 ×10⁵ J/mol

T = 2400 K.

R = 8.314 J mol⁻¹ K⁻¹

The Gibbs free energy should be minimum for a spontaneous reaction and equilibrium state of any reaction is spontaneous reaction. So on simplification, the thermodynamic properties of the equilibrium constant can be obtained as related to Gibbs free energy change at constant temperature.

The relation between Gibbs free energy change with equilibrium constant is ΔG° = -RT ln K

So, here K is the equilibrium constant. Now, substitute all the given values in the corresponding parameters of the above equation.

We get,

1.22 * 10^{5} = - 8.314* 2400 * ln K

\\ 1.22 * 10^{5} = -19953.6 * ln K

ln K = \frac{-1.22*10^{5} }{19953.6} =-6.114\\\\k =e^{-6.114}=0.0022

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2 years ago
State whether each of the following will be more soluble in water or hexane i. Butane ii. Ch3cooh iii. K2so4
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Explanation:

Solubility is determined by the principle , "like dissolves like" .

i.e. , if a compound is polar then it will dissolve in a polar compound only , and

if a compound is non - polar then it will dissolve in a non - polar compound only .

Hence , from the question ,

Water is a polar molecule , and hence it will dissolve only the polar molecule , i.e. , from the given options the polar molecule is , iii. K₂SO₄

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2 years ago
Each day, the stomach produces 2.0 L of gastric juice that contains 0.10 M HCl. Phillips Milk of Magnesia is a white-colored, aq
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Answer:

It would take 72.9 mL of milk of magnesia.

Explanation:

First of all we have to think how the compounds react with each other and what are the products formed. In this case, the hydrochloric acid reacts with magnesium hydroxide to generate magnesium chloride and water as a subproduct. Having said that, we have to state the balanced chemical reaction to know the associated stoichiometry:

2 HCl + Mg(OH)2 → MgCl2 + 2 H2O

According to the balanced equation we know that 2 mol of HCl reacts with 1 mol of Mg(OH)2.

Now we calculate the quantity of moles of HCl that we have present in 2.0 lts of 0.10 M solution:

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This 0.2 moles of acid, as we stated before, will react with 0.1 moles of Mg(OH)2, so we need to calculate the amount of milk of magnesia that has this required quantity of moles.

With the molar mass of Mg(OH)2 we calculate the weight of the compound that represents the 0.1 moles needed to react with all the HCl present in solution:

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0.1 mol = 5.832 g

Now we need to determine what volume of the milk of magnesia solution has 5.832 g of Mg(OH)2 to react with the acid:

The concentration of milk of magnesia is 8 % (w/v). This means that we have 8 gr of Mg(OH)2 per 100 ml of solution.

8 gr Mg(OH)2 per 100 mL Solution

5.832 gr Mg(OH)2 = 72.9 mL of Milk of Magnesia

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2 years ago
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