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9966 [12]
2 years ago
12

A solid metal oxide crystallizes in a cubic unit cell. In the unit cell there are metal (M) ions on every corner and in the cent

er of every face. Oxide ions (O) are found in half of the tetrahedral holes. What is the empirical formula of this metal oxide?
Chemistry
1 answer:
kotegsom [21]2 years ago
8 0

Answer:

The empirical formula of the solid metal oxide is : MO

Explanation:

M atom is present in the every corner and in the center of every face.

Number of m atoms :

\frac{1}{8}\times 8+\frac{1}{2}\times 6=4

Number of tetrahedral voids in F.C.C = 2n = 2 × 4 = 8

Oxide ion is present in the half of the tetrahedral void

Number oxide ions = \frac{8}{2}=4

The molecular formula of the solid metal oxide is : M_4O_4=MO

The empirical formula represent the lowest number of atoms present in a compound.

The empirical formula of the solid metal oxide is : MO

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How much heat is absorbed/released when 25.00 g of NH3(g) reacts in the presence of excess O2(g) to produce NO(g) and H2O(l) acc
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429.4 kJ are absorbed in the endothermic reaction.

Explanation:

The balanced chemical equation tells us that 1168 kJ of heat are absorbed in the reaction when 4 mol of NH₃ (g) react with 5 mol O₂ (g).

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Which of the following chemical equations does not correspond to a standard molar enthalpy of formation? a. Mg(s) + C(s) + 3/2 O
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Answer:

N₂_{s}  + O₂_{g}   →  2NO_{g}

Explanation:

  The given equations are:

      Mg_{s} + C_{s} + \frac{3}{2}O_{g}   →     MgCO₃_{s}

   

      C_{s} +  \frac{1}{2}O₂_{g}    →   CO_{g}

      N₂_{s}  + O₂_{g}   →  2NO_{g}

     

      N₂_{s}  + 2O₂_{g}    →  N₂O_{g}

      H₂_{g} + \frac{1}{2}O_{g}    →    HO_{l}

From the given equations only N₂_{s}  + O₂_{g}   →  2NO_{g} does not correspond to an expression of the standard molar enthalpy of formation.

  • The heat of formation is the heat liberated or absorbed when one mole of a compound is formed from its constituent elements under standard conditions.

 The equation must result in the formation of only one mole of the compound.

It could have been properly written as

   \frac{1}{2}N₂_{s}  +  \frac{1}{2}O₂_{g}   →  NO_{g}

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2 years ago
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