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9966 [12]
1 year ago
12

A solid metal oxide crystallizes in a cubic unit cell. In the unit cell there are metal (M) ions on every corner and in the cent

er of every face. Oxide ions (O) are found in half of the tetrahedral holes. What is the empirical formula of this metal oxide?
Chemistry
1 answer:
kotegsom [21]1 year ago
8 0

Answer:

The empirical formula of the solid metal oxide is : MO

Explanation:

M atom is present in the every corner and in the center of every face.

Number of m atoms :

\frac{1}{8}\times 8+\frac{1}{2}\times 6=4

Number of tetrahedral voids in F.C.C = 2n = 2 × 4 = 8

Oxide ion is present in the half of the tetrahedral void

Number oxide ions = \frac{8}{2}=4

The molecular formula of the solid metal oxide is : M_4O_4=MO

The empirical formula represent the lowest number of atoms present in a compound.

The empirical formula of the solid metal oxide is : MO

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Answer:

Two non bonded electron pairs and four bonded electron pairs

Explanation:

An image of the compound as obtained from chemlibretext is attached to this answer.

The ion ICl4- ion, is an AX4E2 ion. This implies that there are four bond pairs and two lone pairs of electrons. As expected, the shape of the ion is square planar since the lone pairs are found above and below the plane of the square. This is clear from the image attached.

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Los automóviles actuales tienen “parachoques de 5 mi/h (8 km/h)” diseñados para comprimirse y rebotar elásticamente sin ningún d
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Answer:

k = 23045 N/m

Explanation:

To find the spring constant, you take into account the maximum elastic potential energy that the spring can support. The kinetic energy of the car must be, at least, equal to elastic potential energy of the spring when it is compressed to its limit. Then, you have:

K=U\\\\\frac{1}{2}Mv^2=\frac{1}{2}kx^2    (1)

M: mass of the car = 1050 kg

k: spring constant = ?

v: velocity of the car = 8 km/h

x: maximum compression of the spring = 1.5 cm = 0.015m

You solve the equation (1) for k. But first you convert the velocity v to m/s:

v=8\frac{km}{h}*\frac{1000m}{1km}*\frac{1h}{3600s}=2.222\frac{m}{s}

k=\frac{Mv^2}{x^2}=\frac{(1050kg)(2.222m/s)^2}{(0.015m)^2}=23045\frac{N}{m}

The spring constant is 23045 N/m

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1 year ago
The greatest amount of energy released per gram of reactants occurs during a(1) redox reaction
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The greatest amount of energy released per gram of reactants occurs during a (1) redox reaction, although it should be noted that there are exceptions depending on environment. 
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the half-life of a certain radioactive element is 1250 years. what percent of the atom remains after 7500 years?
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2 years ago
For each pair below, select the sample that contains the largest number of moles. Pair A 2.50 g O2 2.50 g N2
raketka [301]

Answer:

Explanation:

Pair  2.50g of O₂ and 2.50g of  N₂

The atoms sample with the largest number of moles since the masses are the same would be the one with lowest molar mass according the the equation below:

Number of moles = \frac{mass }{molarmass}

Atomic mass of O = 16g and N = 14g

Molar mass of O₂ = 16 x 2 = 32gmol⁻¹

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We see that N₂ has the largest number of moles

4 0
1 year ago
Read 2 more answers
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