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2 years ago

An Olympic sized swimming pool has a volume of 660,000 gallons. What is the volume in megaliters?

Chemistry

1 answer:

svet-max [94.6K]2 years ago

4 0

Answer:

2.5 ML

Explanation:

1. Convert gallons to litres

There are 3.785 L in 1 US gal.

$\text{No. of litres} = \text{660 000 gal} \times \dfrac{\text{3.785 L}}{\text{1 gal}} = \text{2 500 000 L}$

2. Convert litres to megalitres

$\text{No. of megalitres} = \text{2 500 000 L} \times \dfrac{\text{1 ML}}{\text{1 000 000 L}} = \textbf{2.5 ML}$

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Write an equation that shows the formation of a strontium ion from a neutral strontium atom

Pepsi [2]

Answer:

See explanation

Explanation:

Sr(s) + 2HCl(aq) -----> SrCl2(aq) + H2(g)

Ionically;

Sr(s) + 2Cl^-(aq) ----> SrCl2(aq)

If we look at the reaction above, strontium atom was dissolved in hydrochloric acid. The strontium atom is now oxidized by the acid to give Sr^2+ ion according to the equation shown above.

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2 years ago

(g) On the graph in part (d) , carefully draw a curve that shows the results of the second titration, in which the student titra

atroni [7]

Answer:

Here's what I get

Explanation:

(g) Titration curves

I can't draw two curves on the same graph, but I can draw two separate curves for you.

The graph in part (d) had an equivalence point at 20 mL.

In the second titration, the NaOH was twice as concentrated, so the volume to equivalence point would be half as much — 10 mL.

The two titration curves are below.

(h) Evidence of reaction

HCl and NaOH are both colourless.

They don't evolve a gas or form a precipitate when they react.

The student probably noticed that the Erlenmeyer flask warmed up — a sign of a chemical change.

4 0

2 years ago

What is the pH of a solution made by mixing 15.00 mL of 0.100 M HCl with 50.00 mL of 0.100 M KOH? Assume that the volumes of the

denis23 [38]

Answer:

The correct answer is: pH = 12.73

Explanation:

The <em>neutralization reaction</em> between HCl and KOH is given by the following chemical equation:

HCl + KOH ⇒ KCl + H₂O

Since HCl is a strong acid and KOH is a strong base, HCl is completely dissociated into H⁺ and Cl⁻ ions, whereas KOH is dissociated completely into K⁺ and OH⁻ ions.

For acids, the number of equivalents is given by the moles of H⁺ ions (in this case: 1 equivalent per mol of HCl). For bases, the number of equivalents is given by the moles of OH⁻ ions (in this case: 1 equivalent per mol of KOH).

The H⁺ ions from HCl will react with OH⁻ ions of KOH to give H₂O. The pH is calculated from the difference between the equivalents of H⁺ and OH⁻:

equivalents of H⁺= volume HCl x Molarity HCl

= (15.0 mL x 1 L/1000 mL) x 0.100 mol/L

= 1.5 x 10⁻³ eq H⁺

equivalents of OH⁻= volume KOH x Molarity KOH

= (50.0 mL x 1 L/1000 mL) X 0.100 mol/L

= 5 x 10⁻³ eq OH⁻

There are more OH⁻ ions than H⁺ ions. The excess of OH⁻ (that did not react with H⁺ ions) is calculated as follows:

OH⁻ ions= (5 x 10⁻³ eq OH⁻) - (1.5 x 10⁻³ eq H⁺) = 3.5 x 10⁻³ eq OH⁻= 3.5 x 10⁻³ moles OH⁻

As the volumes of the solutions are additive, the total volume of the solution is:

V= 15.0 mL + 50.0 mL = 65.0 mL= 0.065 L

So, the concentration of OH⁻ ions in the solution is given by:

[OH⁻] = moles OH⁻/V= (3.5 x 10⁻³ moles OH⁻)/0.065 L = 0.054 mol/L = 0.054 M

From [OH⁻], we can calculate pOH:

pOH = -log [OH⁻] = -log (0.054) = 1.27

Finally, we know that pH + pOH= 14; so we calculate pH:

pH= 14 - pOH = 14 - 1,27 = 12.73

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3 years ago

If you perform the experiment described in investigation #15 by mixing 10 g of glue with 13 g of water and 8 g of sodium borate

Phantasy [73]

10 g of glue with 13 g of water ,

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$\frac{Mass of glue}{Mass of glue + Mass of water}$

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8 g of sodium borate suspended in 11 g of water, mass ratio can be calculated as:

$\frac{Mass of sodium borate}{Mass of sodium borate + Mass of water}$

$\frac{ 8 g}{ 8 g + 11 g }$

$\frac{8 g}{19 g }$

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2 years ago

What is the predicted order of first ionization energies from highest to lowest for beryllium, calcium, magnesium, and strontium

Svetach [21]

We can predict the order of the elements given above according from the highest to lowest first ionization energies by using the trends in a periodic table. For elements in a family, the ionization energy decreases as it goes down. Therefore, the correct order would be Be, Mg, Ca, Sr.

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2 years ago

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