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White raven [17]
2 years ago
15

The balloon Spirit of Freedom, flown around the world by American Steve Fossett in 2002, contained 550,000 cubic feet of helium.

How much PΔV work was done by the balloon on the surrounding atmosphere, assuming atmospheric pressure was 1.00 atm while the balloon was being inflated?
Chemistry
1 answer:
Elodia [21]2 years ago
3 0
Assuming the balloon initially has volume of 0 when deflated, the total P(deltaV) = (1.00 atm)(550,000 ft^3) = 550,000 atm-ft^3. To convert into work units, we can first convert ft^3 to L:
(550,000 atm-ft^3)(1 m/3.28 ft)^3
= (15,586.2 atm-m^3)
Then we convert to L:
(15,586.2 atm-m^3)(1000 L/m^3)
= 15,586,200 atm-L
Then we convert to J:
(15,586,200 atm-L)(101.325 J / 1 atm-L)
= 1.579 x 10^9 J
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At 10°c one volume of water dissolves 3.10 volumes of chlorine gas at 1.00 atm pressure. what is the henry's law constant of cl2
s344n2d4d5 [400]
Answer is:  0,133 mol/ l· atm.
T(chlorine) = 10°C = 283K.
p(chlorine) = 1 atm.
V(chlorine) = 3,10 l.
R - gas constant, R = 0.0821 atm·l/mol·K. 
Ideal gas law: p·V = n·R·T
n(chlorine) = p·V ÷ R·T.
n(chlorine) = 1atm · 3,10l ÷ 0,0821 atm·l/mol·K · 283K = 0,133mol.
Henry's law: c = p·k.
k - <span>Henry's law constant.
</span>c - solubility of a gas at a fixed temperature in a particular solvent.
c = 0,133 mol/l.
k = 0,133 mol/l ÷ 1 atm = 0,133 mol/ l· atm.

4 0
2 years ago
Samples of three different compounds were analyzed and the masses of each element were determined. Compound Mass N (g) Mass O (g
schepotkina [342]

Answer is: c. N2O, N2O4, N2O5.

Law of multiple proportions or Dalton's Law said that the ratios of the masses of the second element which combine with a fixed mass of the first element will be ratios of small whole numbers.

1) NO; m(N) : m(O) = 14 : 16 = 7 : 8.

2) N₂O; m(N) : m(O) = 2·14 : 16 = 7 : 4.

3) NO₂; m(N) : m(O) = 14 : 2·16 = 7 : 16.

4) N₂O₅; m(N) : m(O) = (2·14) : (5·16) = 7 : 20.

5) NO₄; m(N) : m(O) = 14 : (4·16) = 7 : 32.

6) N₂O₄; m(N) : m(O) = (2·14) : (4·16) = 7 : 16.

A) m(N) : m(O) = 5.6 g : 3.2 g /÷3.2

m(N) : m(O) = 1.75 : 1 /×4.

m(N) : m(O) = 7 : 4.

B)  m(N) : m(O) = 3.5 g : 8.0 g /÷3.5

m(N) : m(O) = 1 : 2.285/ ×7.

m(N) : m(O) = 7 : 16.

C)  m(N) : m(O) = 1.4 g : 4.0 g / ÷ 1.4.

m(N) : m(O) = 1 : 2857/ ×7.

m(N) : m(O) = 7 : 20.

6 0
1 year ago
Read 2 more answers
A solid sample of a compound and a liquid sample of the same compound are each tested for electrical conductivity. which test co
marshall27 [118]
If these are you choices: 
(1)  Both the solid and the liquid are good conductors.

(2)  Both the solid and the liquid are poor conductors.

(3)  The solid is a good conductor, and the liquid is a poor conductor.

(4)  The solid is a poor conductor, and the liquid is a good conductor. 

 Then the answer is number 4. This is because ionic compound conducts electricity when it is dissolved in water.

8 0
2 years ago
Please hurry!!! True or false? In a chemical reaction, energy may be gained or lost but the atoms stay the same
Lina20 [59]

Answer:

true

Explanation:

because the atoms make up the elements which forms the compound

8 0
2 years ago
Two students made the Lewis dot diagrams of NH3. The diagrams are as shown.
BigorU [14]

Answer :  The correct option is, Only Student B

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, NH_3

As we know that nitrogen has '5' valence electrons and hydrogen has '1' valence electron.

Therefore, the total number of valence electrons in NH_3 = 5 + 3(1) = 8

According to Lewis-dot structure, there are 6 number of bonding electrons and 2 number of non-bonding electrons.

The Lewis dot structure of student A is wrong because there is a coordinate bond present between the nitrogen and hydrogen is not covalent.

Thus, the correct Lewis-dot structure of NH_3 is shown by the student B.

4 0
1 year ago
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