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Illusion [34]
2 years ago
6

Monochlorination of propane yields two constitutional isomers, and dichlorination yields four. Trichlorination yields five const

itutional isomers. Draw all five trichloropropane isomers.

Chemistry
2 answers:
RSB [31]2 years ago
8 0

Answer:

The trichloro isomers are [figure attached for structures]

a) 1,1,1-trichloropropane

b) 1,1,2-trichloropropane

c) 1,1,3-trichloropropane

d) 1,2,2-trichloropropane

e) 1,2,3-trichloropropane

Explanation:

Constitutional isomers are the compounds with same molecule formula but different arrangements of atoms on the chain.

The monochloro propane isomers are :

a) 1-chloropropane

b) 2-chloropropane

The dichloro isomers are :

a) 1,2-dichloropropane

b) 1,3-dichloropropane

c) 1,1-dichloropropane

d) 2,2-dichloropropane

The trichloro isomers are [figure attached for structures]

a) 1,1,1-trichloropropane

b) 1,1,2-trichloropropane

c) 1,1,3-trichloropropane

d) 1,2,2-trichloropropane

e) 1,2,3-trichloropropane

GaryK [48]2 years ago
6 0
By Tri chlorination, three chlorine atoms can replace the 3 hydrogen atoms in propane molecule to give tri-chlorinated products according to the attached picture.

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zalisa [80]

Answer:

ΔU=-369.2 kJ/mol.

Explanation:

We start from the equation:

Δ(H)=ΔU+Δ(PV), which is an extension of the well known relation: H=U+PV.

If Δ(PV) were calculated by ideal gas law,

PV=nRT

Δ(PV)=RTΔn.

Where Δn is the change of moles due to the reaction; but, this reaction does not give a moles change (Four moles of HCl produced from 4 moles of reactants), so Δ(PV)=0.

So, for this case, ΔH=ΔU.

The enthalpy of reaction given is for one mole of reactant, so the enthalpy of reaction for the reaction of interest must be multiplied by two:

2 reactant moles*\frac{-184.6kJ}{mol}

ΔU=-369.2 kJ/mol.

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2 years ago
Which gas tank will empty first? acetylene (C2H2) oxygen (O2)
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A vessel of capacity 400 cc filled with chlorine under 80 cm is connected by a narrow tube and stopcock with another vessel of c
guapka [62]

Answer:

The pressure when the stopcock is opened is opened is 87.783 cm

Explanation:

The given parameters of the question are;

The volume of the vessel of chlorine = 400 cc

The pressure of the vessel of chlorine = 80 cm

The volume of the vessel of chlorine = 250 cc

The pressure of the vessel of chlorine = 100 cm

Daltons law of Partial Pressures states that the total pressure exerted by a volume of a mixture of gases is equal to the partial pressures exerted by the individual gases in the mixture with respect to the given volume

Therefore;

The total volume of the mixture = 400 cc + 250 cc = 650 cc

The partial pressure exerted by the chlorine gas in the total volume is given by Boyles law as follows;

P₁·V₁ = P₂·V₂

P₂ = P₁·V₁/V₂

Where;

P₁ = 80 cm = The pressure in volume V₁ = 400 cc

P₂ₓ = The partial pressure of chlorine in volume V₂ = 650 cc

Substituting, we have;

P₂ₓ = 80 × 400/650 ≈ 49.321 cm

Similarly, the partial pressure exerted by the nitrogen gas in the total volume is given by Boyles Law as follows;

P₂ₐ = P₁·V₁/V₂

Where;

P₁ = 100 cm = The pressure in volume V₁ = 250 cc

P₂ₐ = The partial pressure of nitrogen in volume V₂ = 650 cc

Substituting, we have;

P₂ₐ = 100× 250/650 ≈ 38.462 cm

The pressure of the combined gas, P, when the stopcock is opened is opened is given by Dalstons Law of partial pressure as P = P₂ₐ + P₂ₓ

Therefore, the pressure, P when the stopcock is opened is opened = 49.321 cm + 38.462 cm = 87.783 cm

3 0
1 year ago
The interior of a refrigerator has a volume of 0.600 m3. the temperature inside the refrigerator in 282 k, and the pressure is 1
Dafna11 [192]
In this instance we can use the ideal gas law equation to find the number of moles of gas inside the refrigerator 
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where 
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V - volume - 0.600 m³
n - number of moles
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T - temperature - 282 K
substituting these values in the equation 
101 000 Pa x 0.600 m³ = n x  8.314 J/mol.K x 282 K
n = 25.8 mol
there are 25.8 mol of the gas
to find the mass of gas
mass of gas = number of moles x molar mass of gas
mass = 25.8 mol x 29 g/mol  = 748.2 g
mass of gas present is 748.2 g 
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If a pharmacist dissolves 1.2 grams of a medicinal agent in 60 ml of a cough syrup having a specific gravity of 1.20, what is th
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New mass = 72 + 1.2 = 73.2  

Specific gravity = mass /  volume = 73.2 / 60.2 = 1.22 g/mL

7 0
1 year ago
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