2.22x10^-3 would be the answer to the question
please mark as brainliest answer
Barfoed's test is a concoction test utilized for identifying the nearness of monosaccharides. It depends on the diminishment of copper(II) acetic acid derivation to copper(I) oxide (Cu2O), which frames a block red hasten.
Barfoed's reagent comprises of a 0.33 molar arrangement of unbiased copper acetic acid derivation in 1% acidic corrosive arrangement. The reagent does not keep well and it is, thusly, fitting to make it up when it is really required. May store uncertainly as per a few MSDS's.
Answer:p-hydroxybenzaldehyde is stronger acid to phenol
para-cyanophenol is stronger acid to meta-cyanophenol
o-fluorophenol is stronger acid to p-fluorophenol.
Explanation:
The PKa tool relative to Ph are used to contrast the pairs.
The pKa of phenol is 10. The pKa of p-hydroxybenzaldehyde is 9.24
The pKa for meta-cyanophenol is 8.61 and the pKa for para-cyanophenol is 7.95.
The pKa value of o-fluorophenol is 8.7, while that of the p-fluorophenol is 9.9. It's obvious that the inductive effect is more dominant at ortho-position, which results in a more acidic nature
The pKa is the pH value at which a chemical species will accept or donate a proton. The lower the pKa, the stronger the acid and the greater the ability to donate a proton in aqueous solution.
Answer:
Volume at STP = 0.1401 L
Explanation:
We are given:
Vapor pressure of water = 20 torr
Total vapor pressure = 753 torr
Vapor pressure of gas = Total vapor pressure - Vapor pressure of water = 753 torr - 20 torr = 733 torr
Using
where,
P = pressure of the gas = 733 torr
V = Volume of the gas = 157 mL= 0.157 L
T = Temperature of the gas =
R = Gas constant =
n = number of moles of gas = ?
Putting values in above equation, we get:
At STP, one mole of the gas occupies a volume of 22.4 L
So, 0.006255 mole of the gas occupies a volume of 22.4*0.006255 L
<u>Volume at STP = 0.1401 L</u>
The classification of it being a metal, nonmetal, or metalliod will be useful in the process of elimination to determine what it is. Then for the second test, meauring the atomin radius will narrow it down quicker to the mystery elemet's name.
Since you determined what part of the periodic table it's on, then when measuring the atomic radius, you should be able to pinpoint what the element is more surely.