Question

Boron - 10 emits alpha particles and cesium - 137 emits beta particles. Write balanced nuclear

Answer 1

Answer:

B10  5N +5P= Li6 3N +3P

Cs 137 82N+55P = I 133  80N + 53P

Explanation:

Answer 2

Explanation:

Alpha decay: In this process, alpha particles is emitted when a heavier nuclei decays into lighter nuclei. The alpha particle released has a charge of +2 units.

$_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}+_2^4\alpha$

$_5^{10}\textrm{B}\rightarrow _{3}^{6}Li+_2^4\alpha$

Beta-decay: In this process, a neutron gets converted into a proton and an electron releasing a beta-particle. The beta particle released carries a charge of -1 units.

$_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta$

$_{55}^{133}\textrm{Cs}\rightarrow _{56}^{133}\textrm{Ba}+_{-1}^0\beta$