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tino4ka555 [31]
1 year ago
12

Roundup, an herbicide manufactured by Monsanto, has the formula C3H8NO5P. How many moles of molecules are there in a 669.1-g sam

ple of Roundup?
Chemistry
1 answer:
Vedmedyk [2.9K]1 year ago
7 0

Answer:

2.4 ×10^24 molecules of the herbicide.

Explanation:

We must first obtain the molar mass of the compound as follows;

C3H8NO5P= [3(12) + 8(1) + 14 +5(16) +31] = [36 + 8 + 14 + 80 + 31]= 169 gmol-1

We know that one mole of a compound contains the Avogadro's number of molecules.

Hence;

169 g of the herbicide contains 6.02×10^23 molecules

Therefore 669.1 g of the herbicide contains 669.1 × 6.02×10^23/ 169 = 2.4 ×10^24 molecules of the herbicide.

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Which statement correctly describes the location and charge of the electrons in an atom?
maxonik [38]

Answer:

D

Explanation:

The electrons revolve around the nucleus and they contain negative charge

3 0
1 year ago
Arranges the following molecules in order of increasing dipole moment: <br> H2O, H2S, H2Te, H2Se.
erastova [34]

Explanation:

Dipole moment is defined as the measurement of the separation of two opposite electrical charges.

H_{2}O is a bent shaped molecule with a dipole moment of 1.87.

H_{2}S is also a bent shaped molecule with a dipole moment of 1.10.

H_{2}Te is a also a bent shaped molecule and has a negligible dipole moment.

H_{2}Se has a dipole moment of 0.29.

Therefore, given molecules are arranged according to their increasing dipole moment as follows.

        H_{2}Te < H_{2}Se < H_{2}S < H_{2}O

7 0
2 years ago
A scientist is wondering why a certain region in the ocean doesn't have maximum phytoplankton growth, despite having plenty of n
Advocard [28]

Answer:

C The water had adequate nitrogen and phosphorus, so it is likely iron limited.

Explanation:

Phytoplankton are single- cell organisms that live in oceans.

They require nitrogen, phosphorus and trace amount of iron to survive.

From the scientist's results after testing the water for nitrogen and phosphorus,there are reasonable amount of these elements.

Therefore insufficient iron in the water is the reason why he could find plenty phytoplankton in the ocean.

8 0
2 years ago
You mix 500.0 mL of 0.250 M iron(III) chloride solution with 425.0 mL of 0.350 M barium chloride solution. Assuming the volumes
12345 [234]

Answer:

M=0.727M

Explanation:

Hello,

In this case, since iron (III) chloride (FeCl3) and barium chloride (BaCl2) are both chloride-containing compounds, we can compute the moles of chloride from each salt, considering the concentration and volume of the given solutions, and using the mole ratio that is 1:3 and 1:2 for the compound to chlorine:

n_{Cl^-}=0.50L*0.250\frac{molFeCl_3}{L}*\frac{3molCl^-}{1molFeCl_3}=0.375molCl^-  \\\\n_{Cl^-}=0.425L*0.350\frac{molBaCl_2}{L}*\frac{2molCl^-}{1molBaCl_2}=0.2975molCl^-

So the total mole of chloride ions:

N_{Cl^-}=0.2975mol+0.375mol=0.6725molCl^-

And the total volume by adding the volume of each solution in L:

V=0.500L+0.425L=0.925L

Finally, the molarity turns out:

M=\frac{0.6725molCl^-}{0.925L}\\ \\M=0.727M

Best regards.

5 0
2 years ago
When 200g of AgNO3 solution mixes with 150 g of NaI solution, 2.93 g of AgI precipitates, and the temperature of the solution ri
gizmo_the_mogwai [7]

Answer:

\Delta H=1962.3J

Explanation:

Hello,

In this case, we can compute the change in the solution enthalpy by using the following formula:

\Delta H=mC\Delta T

Whereas the mass of the solution is 350 g, the specific heat capacity is 4.184 J/g °C and the change in the temperature is 1.34 °C, therefore, we obtain:

\Delta H=350g*4.184\frac{J}{g\°C} *1.34\°C\\\\\Delta H=1962.3J

It is important to notice that the mass is just 350 g that is the reacting amount and by means of the law of the conservation of mass, the total mass will remain constant, for that reason we compute the change in the enthalpy as shown above, which is positive due to the temperature raise.

Best regards.

8 0
2 years ago
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