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2 years ago

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Is the atom indicated with an arrow nucleophilic, electrophilic, acidic, more than one of these choices, or none of these choice

s? (For purposes of this question, acidic is defined as pKa ≤ 25.)

1 answer:

9966 [12]2 years ago

7 0

Answer:

Acidic

Explanation:

Please kindly check attachment for the detailed step by step solution of the given problem.

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In a system with 4 atoms and 1 lone pair, predict whether the lone pair will be in a B site or an A site? Explain.

Maslowich

Answer:

B

Explanation:

The compound corresponds to a molecule AX4E where A is the Central atom, X are the other atoms present and E is the lone pair of electrons.

The shape of this molecule is based on a trigonal bipyramid since the molecule contains five electron domains.

Since there are four bond pairs and one lone pair, the molecular geometry is see-saw with equatorial bond angle <120° and axial bond angle <90°.

For AX4E (five electron pairs), the lone pair should occupy an equatorial position instead of an axial position since the equatorial position has two neighboring electron pairs that are positioned at about 90° apart from each other and two other neighboring electron pairs that are positioned at 120° from each other. The axial position has 3 neighboring electron pairs positioned at 90° from each other and another neighboring electron pair positioned at 120°. Hence the equatorial position experiences lesser repulsion compared to the axial position.

Hence in the structure pictured in the question, position B is a preferred position for the lone pair instead of position A.

8 0

2 years ago

How many ml of a 14.0 m nh3 stock solution are needed to prepare 200 ml of a 4.20 m dilute nh3 solution? hints how many ml of a

Fudgin [204]

To solve this we use the equation,

M1V1 = M2V2

where M1 is the concentration of the stock solution, V1 is the volume of the stock solution, M2 is the concentration of the new solution and V2 is its volume.

14 M x V1 = 4.20 M x 200 mL

V1 = 60 mL needed of the concentrated solution

5 0

2 years ago

1. Suppose 0.7542 g of magnesium reacts with excess oxygen to form magnesium oxide as the only product, what would be the theore

Alina [70]

Answer :

(1) The theoretical yield of product, $MgO$ is, 1.257 grams.

(2) The percent yield of $MgO$ is, 64.13 %

(3) If the percent yield is calculated to be over 100% then there might be some impurity present in the desired product.

Solution : Given,

Mass of Mg = 0.7542 g

Molar mass of Mg = 24 g/mole

Molar mass of MgO = 40 g/mole

First we have to calculate the moles of Mg.

$\text{ Moles of }Mg=\frac{\text{ Mass of }Mg}{\text{ Molar mass of }Mg}=\frac{0.7542g}{24g/mole}=0.03142moles$

Now we have to calculate the moles of $MgO$

The balanced chemical reaction is,

$2Mg(s)+O_2(g)\rightarrow 2MgO(s)$

From the reaction, we conclude that

As, 2 mole of $Mg$ react to give 2 mole of $MgO$

So, 0.03142 moles of $Mg$ react to give 0.03142 moles of $MgO$

Now we have to calculate the mass of $MgO$

$\text{ Mass of }MgO=\text{ Moles of }MgO\times \text{ Molar mass of }MgO$

$\text{ Mass of }MgO=(0.03142moles)\times (40g/mole)=1.257g$

Theoretical yield of $MgO$ = 1.257 g

Experimental yield of $MgO$ = 0.8922 g

Now we have to calculate the percent yield of $MgO$

$\% \text{ yield of }MgO=\frac{\text{ Experimental yield of }MgO}{\text{ Theretical yield of }MgO}\times 100$

$\% \text{ yield of }MgO=\frac{0.8922g}{1.257g}\times 100=70.97\%$

Therefore, the percent yield of $MgO$ is, 70.97 %

If the percent yield is calculated to be over 100% then the product would be greater than 1.257 g which indicates that there might be some impurity present in the desired product.

4 0

2 years ago

Barium sulfate, BaSO4, is a white crystalline solid that is insoluble in water. It is used by doctors to diagnose problems with

pshichka [43]

Answer:2

Explanation:

Ba(OH)2 contains two oxygen atoms

BaSO4 contains four oxygen atoms.

This means that barium sulphate contains two more oxygen atoms than barium hydroxide in its formula. This is clearly seen from the two formulae shown above.

5 0

1 year ago

Type in the correct values to correctly represent the valence electron configuration of oxygen: AsB2pC

valkas [14]

Answer:

2s²2p⁴

Explanation:

Oxygen is an element on the periodic table with a total of 8 electrons. It's electronic configuration is given as 2,6.

Using the orbital notation we write as 1s²2s²2p⁴

Also, the valence electrons are the electrons in the outermost shell of an atom. These electrons mostly determine the chemical properties of an atom.

Oxygen has a total of 6 electrons in its outermost shell and it is given as 2s²2p⁴

7 0

2 years ago

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