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GaryK [48]
2 years ago
13

a) (1 point) Build anthracene, optimize its geometry and examine its structure. Describe its shape. b) (1 point) Measure the C-C

bond lengths in anthracene. How do the bond lengths compare to typical C−C or C=C bond distances? c) (1 point) Build N-maleimide, optimize the geometry and examine the structure. Is the molecule flat?
Chemistry
1 answer:
oksano4ka [1.4K]2 years ago
8 0

Answer:

a) The structure of anthracene is planar with all the pi electrons delocalized in the structure to maintain aromaticity.

b) The C-C bond length in anthracene is about 140 pm with all the bond lengths being similar to each other.

The standard C-C bond length is 154 pm while standard C=C bond is about 134 pm. Therefore the bond length in anthracene is smaller than standard C-C bond length and longer than standard C=C bond length. This can be explained from the fact that the C-C bonds in anthracene has be mixed characteristics of single and double bond because of the delocalization of pi electrons over the whole structure. As a result, they are neither fully single nor fully double bond in nature. Hence the observed bond lengths.

c) This molecule is not flat. The N-atom is sp3 hybridized here and the H-atom attached to N will remain out of plane.

Explanation:

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Dinitrogen monoxide or laughing gas (N2O) is used as a dental anesthetic and as an aerosol propellant. How many moles of N2O are
Rudiy27

Answer:

In 12.6g of N_{2}O there are 0.29 moles of N_{2}O and 1.7*10^{23} molecules of N_{2}O

Explanation:

First you should find the molar mass of the N_{2}O:

N_{2}O=2(14.01\frac{g}{mol})+16.00\frac{g}{mol}

N_{2}O=44.02\frac{g}{mol}

Then you should write the conversion factor using the molar mass:

12.6gN_{2}O*\frac{1molN_{2}O}{44.02gN_{2}O}=0.29molesofN_{2}O

So, there are 0.29 moles of N_{2}O in 12.6g of N_{2}O.

Finally to find the number of molecules, you should use the Avogadro´s number:

0.29molesN_{2}O*\frac{6.022*10^{23}}{1molN_{2}O}=N_{2}O

There are 1.7*10^{23} moles of N_{2}O in 12.6g of N_{2}O

7 0
1 year ago
In thionyl chloride, cl2so (s is the central atom), the formal charge on sulfur and number of lone pairs on sulfur are, respecti
zimovet [89]

Sulfur in the thionyl compound will have the formal charge or +1 and has two lone electrons or one lone pair.

<h2>Further Explanation</h2><h3>Lewis Structures</h3>

In order to determine the formal charge and number of lone pairs, it is imperative to draw the Lewis structure first. The steps in drawing the lone pairs are:

  1. Get the total number of valence electrons by adding the number of valence electrons of each atom in the compound.
  2. Determine the central atom.
  3. Place the other atoms around the central atom and connect each to the central atom by a single bond. For every single bond, 2 electrons from the total valence electrons are shared.
  4. Distribute the remaining valence electrons to the terminal atoms. Start by distributing to one terminal atom until the atom has an octet then move to the next terminal atom. If all terminal atoms have an octet, the remaining electrons will be placed in the central atom.

For thionyl chloride, the central atom is sulfur and the total number of valence electrons is:

Cl = 7 × 2 = 14

S = 6

O = 6

Total Valence Electrons = 14 + 6 + 6 = 26 electrons.  Following the steps above, the resulting Lewis structure is shown in the attachment.

Once the Lewis structure is known, the number of lone pairs in the central atom can be known. For thionyl chloride, it can be seen that there are two unshared electrons in S. Therefore, S has one lone pair.

<h3>Formal Charges</h3>

The relative distribution of electrons in a molecule can be described through the formal charges of each atom. The formal charge describes how many electrons there are in an atom compared to how many electrons it has if it were not bonded. For a molecule to have a stable structure, the formal charges of all the atoms must be at the lowest possible values.

The formula to determine the formal charge is:

Formal Charge = # valence electron for the isolated atom - (# bonds + non-bonding electrons)

For the thionyl compound, the formal charge of S is determined using the following equation and by looking at the Lewis Structure:

  • Valence Electrons of a Sulfur atom = 6
  • Number of bonds around Sulfur = 3
  • Number of non-bonding electrons on Sulfur = 2

Formal Charge of S = 6 - (3+2)

Formal Charge of S = +1

This means that sulfur has less electrons around it in the molecule than it has as an isolated atom.

<h3>Learn More</h3>
  1. Lewis Structure brainly.com/question/2323095
  2. Valence Electrons brainly.com/question/2376134

<em>Keywords: formal charge, lone pairs</em>

5 0
2 years ago
Read 2 more answers
If 10.0 liters of h2(g) at STP is heated to a temperature of 546 K, pressure remaining constant, the new volume of the gas will
Effectus [21]

Answer:

20L

Explanation:

The following data were obtained from the question:

Initial volume (V1) = 10L

Initial Temperature (T1) = stp = 273K

Final temperature (T2) = 546K

Final volume (V2) =..?

The new volume of the gas can be obtained by using the Charles' law equation as shown below:

V1/T1 = V2/T2

10/273 = V2/546

Cross multiply to express in linear form

273 x V2 = 10 x 546

Divide both side by 273

V2 = (10 x 546) / 273

V2 = 20L

Therefore, the new volume of the gas is 20L.

3 0
2 years ago
How many chloride ions are in a 220 grams of calcium chloride?
fomenos
The Ions present in CaCl₂ are,

                                                 Ca²⁺    Cl⁻     Cl⁻

Means 1 formula unit contains 1 Ca²⁺ ion and 2 Cl⁻ ions.

Also, 1 mole of CaCl₂ contains 6.022 × 10²³ formula units.

So, 1 mole formula units of CaCl₂ contain,

                                            2 × 6.022 × 10²³  =  1.20 × 10²⁴ Cl⁻ Ions

Now, Calculating number of moles contained by 220 g of CaCl₂,
As,
                               110.98 g of CaCl₂  =  1 mole
Then, 
                                    220 g of CaCl₂  =  X moles
Solving for X,
                                                 X  =  (220 g × 1 mol) ÷ 110.98 g

                                                 X  =  1.98 moles
As,
                           1 mole contained  =  1.20 × 10²⁴ Cl⁻ Ions
Then,
                    1.98 mole will contain  =  X Cl⁻ Ions
Solving for X,
                                                  X  =  (1.98 mol × 1.20 × 10²⁴ Ions) ÷ 1mol

                                                  X  =  2.38 × 10²⁴ Cl⁻ Ions
6 0
1 year ago
Read 2 more answers
Why is a ylid a stable nucleophile? Select all that apply. Group of answer choices The proximity of the positively charged phosp
pogonyaev

Answer:

1)The proximity of the positively charged phosphorous and negatively charged carbon stabilizes the charges.

2) Inductive effects and resonance stabilize the negative charge

Explanation:

both atoms have full octets of electrons( I.e Carbon and say phosphorus). The result can be viewed as a structure in which two adjacent atoms are connected by both a covalent and an ionic bond; normally written X+–Y−. Ylides are thus 1,2-dipolar compounds, and a subclass of zwitterions

6 0
1 year ago
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