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2 years ago

Which of the following is a disadvantage of using hydropower? (2 points)

Chemistry

2 answers:

frutty [35]2 years ago

7 0

D.) Land can be flooded, displacing people and wildlife.

anygoal [31]2 years ago

4 0

Answer : The disadvantage of using hydropower is Land can be flooded, displacing people and wildlife

Explanation :

Hydropower is a renewable source of energy. In hydropower, electricity is generated using the mechanical energy of moving water.

Since the kinetic energy is necessary to move the turbines, it is essential that the hydropower plant is present near a water source which has moving water.

It is the most efficient way of harnessing the energy from naturally available energy sources. It does not produce any waste. It does not pollute water or air.

Since hydropower needs kinetic energy of moving water, there is always a possibility of nearby land getting flooded. This would affect the people and wildlife of nearby areas.

Therefore the disadvantage of using hydropower is that land can be flooded, displacing people and wildlife

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Assuming equal concentrations of conjugate base and acid, which one of the following mixtures is suitable for making a buffer so

BartSMP [9]

Answer:

NH₃/NH₄Cl

Explanation:

We can calculate the pH of a buffer using the Henderson-Hasselbalch's equation.

$pH=pKa+log\frac{[base]}{[acid]}$

If the concentration of the acid is equal to that of the base, the pH will be equal to the pKa of the buffer. The optimum range of work of pH is pKa ± 1.

Let's consider the following buffers and their pKa.

CH₃COONa/CH3COOH (pKa = 4.74)

NH₃/NH₄Cl (pKa = 9.25)

NaOCl/HOCl (pKa = 7.49)

NaNO₂/HNO₂ (pKa = 3.35)

NaCl/HCl Not a buffer

The optimum buffer is NH₃/NH₄Cl.

4 0

1 year ago

a) (1 point) Build anthracene, optimize its geometry and examine its structure. Describe its shape. b) (1 point) Measure the C-C

oksano4ka [1.4K]

Answer:

a) The structure of anthracene is planar with all the pi electrons delocalized in the structure to maintain aromaticity.

b) The C-C bond length in anthracene is about 140 pm with all the bond lengths being similar to each other.

The standard C-C bond length is 154 pm while standard C=C bond is about 134 pm. Therefore the bond length in anthracene is smaller than standard C-C bond length and longer than standard C=C bond length. This can be explained from the fact that the C-C bonds in anthracene has be mixed characteristics of single and double bond because of the delocalization of pi electrons over the whole structure. As a result, they are neither fully single nor fully double bond in nature. Hence the observed bond lengths.

c) This molecule is not flat. The N-atom is sp3 hybridized here and the H-atom attached to N will remain out of plane.

Explanation:

8 0

2 years ago

A farmer had an accident and spilled a chemical into his pond. Several days later, he notices many dead frogs around the pond. T

andrezito [222]

B. the frogs are a limiting factor for the gnats
the frogs limit the reproduction of the gnats, and therefore with less frogs the gnat population can increase

3 0

2 years ago

Read 2 more answers

What is the mass of 0.921 moles of sulfur dioxide gas (SO2)?

Serhud [2]

Answer:

mass = 58.944 g

Explanation:

Given data:

Number of moles of SO₂ = 0.921 mol

Mass of SO₂ = ?

Solution:

Formula:

Number of moles = mass/ molar mass

First of all we will calculate the molar mass.

SO₂ = 32 + 16×2 = 64 g/mol

Now we will put the values in formula.

Number of moles = mass/ molar mass

0.921 mol = mass /64 g/mol

mass = 0.921 mol × 64 g/mol

mass = 58.944 g

8 0

1 year ago

The decomposition of nitramide, O 2 NNH 2 , O2NNH2, in water has the chemical equation and rate law O 2 NNH 2 ( aq ) ⟶ N 2 O ( g

valkas [14]

Answer:

Explanation:

The given overall reaction is as follows:

O 2 N N H ₂( a q ) k → N ₂O ( g ) + H ₂ O( l )

The reaction mechanism for this reaction is as follows:

O ₂ N N H ₂ ⇌ k 1 k − 1 O ₂N N H ⁻ + H ⁺ ( f a s t e q u i l i b r i u m )

O ₂ N N H − k ₂→ N ₂ O + O H ⁻ ( s l ow )

H ⁺ + O H − k ₃→ H ₂ O ( f a s t )

The rate law of the reaction is given as follows:

k = [ O ₂ N N H ₂ ] / [ H ⁺ ]

The rate law can be determined by the slow step of the mechanism.

r a t e = k ₂ [ O ₂ N N H ⁻ ] . . . ( 1 )

Since, from the equilibrium reaction

k e q = [ O ₂ N N H ⁻ ] [ H ⁺ ] /[ O ₂ N N H ₂ ] = k ₁ /k − 1

[ O ₂ N N H ⁻] = k ₁ /k − 1 × [ O ₂ N N H ₂ ] /[ H ⁺ ]. . . . ( 2 )

Substitituting the value of equation (2) in equation (1) we get.

r a t e = k ₂ k ₁/ k − 1 × [ O ₂ N N H ₂ ] /[ H ⁺ ]

Therefore, the overall rate constant is

k = k₂k₁/k-1

5 0

1 year ago