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jasenka [17]
2 years ago
13

Which of the following is a disadvantage of using hydropower? (2 points)

Chemistry
2 answers:
frutty [35]2 years ago
7 0
D.) Land can be flooded, displacing people and wildlife.
anygoal [31]2 years ago
4 0

Answer : The disadvantage of using hydropower is Land can be flooded, displacing people and wildlife

Explanation :

Hydropower is a renewable source of energy. In hydropower, electricity is generated using the mechanical energy of moving water.

Since the kinetic energy is necessary to move the turbines, it is essential that the hydropower plant is present near a water source which has moving water.

It is the most efficient way of harnessing the energy from naturally available energy sources. It does not produce any waste. It does not pollute water or air.

Since hydropower needs kinetic energy of moving water, there is always a possibility of nearby land getting flooded. This would affect the people and wildlife of nearby areas.

Therefore the disadvantage of using hydropower is that land can be flooded, displacing people and wildlife


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Electrons in __________ bonds remain localized between two atoms. electrons in __________ bonds can become delocalized between m
dsp73

Electrons in sigma <span>bonds remain localized between two atoms. Sigma </span><span>bond results from the formation of </span><span>a molecular orbital </span><span>by the end to </span><span>end overlap of atomic </span>orbitals. Electrons<span> in pi</span> bonds can become delocalized between more than two atoms. Pi bonds result from the formation of molecular orbital by side to side overlap of atomic orbitals. 

 

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7 0
2 years ago
What volume of 0.500 M HNO₃(aq) must completely react to neutralize 100.0 milliliters of 0.100 M KOH(aq)?
USPshnik [31]

Answer:

v = 500 milliliters

Explanation:

HNO_{3}  ⇒  H^{+}  + NO^{3-}

KOH  ⇒  K^{+}  + OH^{-}

1 H^{+} to 1 OH^{-}

\frac{0,5}{V}  = \frac{0,1}{100} \\\\v * 0,1 = 50\\v = 500 milliliters

4 0
2 years ago
A piece of iron metal is heated to 155 degrees C and placed into a calorimeter that contains 50.0 mL of water at 18.7 degrees C.
Korvikt [17]

Answer:

D = 28.2g

Explanation:

Initial temperature of metal (T1) = 155°C

Initial Temperature of calorimeter (T2) = 18.7°C

Final temperature of solution (T3) = 26.4°C

Specific heat capacity of water (C2) = 4.184J/g°C

Specific heat capacity of metal (C1) = 0.444J/g°C

Volume of water = 50.0mL

Assuming no heat loss

Heat energy lost by metal = heat energy gain by water + calorimeter

Heat energy (Q) = MC∇T

M = mass

C = specific heat capacity

∇T = change in temperature

Mass of metal = M1

Mass of water = M2

Density = mass / volume

Mass = density * volume

Density of water = 1g/mL

Mass(M2) = 1 * 50

Mass = 50g

Heat loss by the metal = heat gain by water + calorimeter

M1C1(T1 - T3) = M2C2(T3 - T2)

M1 * 0.444 * (155 - 26.4) = 50 * 4.184 * (26.4 - 18.7)

0.444M1 * 128.6 = 209.2 * 7.7

57.0984M1 = 1610.84

M1 = 1610.84 / 57.0984

M1 = 28.21g

The mass of the metal is 28.21g

3 0
2 years ago
How many milliliters of 0.02 M HCl are needed to react completely with 100 mL of 0.01 M NaOH?
serious [3.7K]
The reaction of HCl and NaOH is HCl + NaOH = NaCl + H2O. So the mole number of HCl and NaOH is equal. So the volume of HCl =0.01*0.1/0.02=0.05 L =50 ml. So the answer is D).
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2 years ago
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