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professor190 [17]
1 year ago
15

A chef makes a marinade by mixing red pepper flakes, dried onion flakes, and a ground ginger with soy sauce. He sets the marinad

e on the counter for a few minutes. When he returns, he must stir the marinade because the spices have settled to the bottom of the container.
answer: the mixture is a suspension
Chemistry
2 answers:
Sophie [7]1 year ago
6 0

Answer:

Explanation: suspension is the answer

Alisiya [41]1 year ago
3 0

Answer:

Suspension

Explanation:

This mixture is a simple suspension.

A suspension is a mixture of small insoluble particles of a solid in a liquid or gas. Here, it is insoluble particles in liquid.

  • Suspensions are settle on standing this is why they have to be mixed again.
  • The particles do not pass through ordinary filter paper.
  • They are usually cloudy and have an opaque color.
  • The marinade is simply a suspension.
  • It is not a solution because they do not settle on standing.
  • Also, colloids do not settle on standing.
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2) You are trying to determine a TLC solvent system which will separate the compounds X, Y, and Z. You ran the compounds on a TLC plate using hexanes/ethyl acetate 95:5 as the eluting solvent and obtained the chromatogram below. How could you change the solvent system to give better separation of these three compounds?

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Back to TLC

Original content © University of Colorado at Boulder, Department of Chemistry and Biochemistry.
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A 1.0 g sample of a cashew was burned in a calorimeter containing 1000. g of water, and the temperature of the water changed fro
Savatey [412]

Answer:

The correct answer is option C.

Explanation:

1.0 g sample of a cashew :

Heat released on  combustion of 1.0 gram of cashew = -Q

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Specific heat of water = c = 4.184 J/g°C

ΔT = 30°C - 25°C = 5°C

Heat absorbed by the water :  Q

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Heat released on  combustion of 1.0 gram of cashew is -20,920 J.

3.0 g sample of a marshmallows  :

Heat released on  combustion of 3.0 g sample of a marshmallows = -Q'

We have mass of water = m = 2000 g

Specific heat of water = c = 4.184 J/g°C

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Heat released on 1.0 g sample of a marshmallows : q

q =\frac{-Q'}{3} = \frac{-41,840 J}{3}=-13,946.67 J

Heat released on  combustion of 1.0 gram of marshmallows -13,946.67 J.

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The combustion of 1.0 g of cashew releases more energy than the combustion of 1.0 g of marshmallow.

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