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creativ13 [48]
1 year ago
12

A student has 7.05 g of zinc powder, 1.60 L of a 3.40 M calcium nitrate solution, and 1.50 L of a 1.60 M lead(II) nitrate soluti

on. Which of these two solutions will react with the zinc powder?
1) calcium nitrate
2) lead(II) nitrate

Chemistry
1 answer:
trapecia [35]1 year ago
6 0

<u>Answer:</u> Zinc will react with lead (II) nitrate solution.

<u>Explanation:</u>

Single displacement reaction is defined as the reaction in which more reactive element displaces a less reactive element from its chemical reaction.

The reactivity of metal is determined by a series known as reactivity series. The metals lying above in the series are more reactive than the metals which lie below in the series.

General equation for single displacement reaction follows:

A+BC\rightarrow AC+B

When zinc is reacted with calcium nitrate, the reaction does not take place as zinc is less reactive than calcium. Zinc lies below in the series than calcium.

Zn+Ca(NO_3)_2\rightarrow \text{No reaction}

But, when zinc is reacted with lead (II) nitrate, the reaction do take place as zinc is more reactive than lead. Zinc lies above in the series than lead.

The chemical equation for the reaction of zinc and lead (II) nitrate follows:

Zn+Pb(NO_3)_2\rightarrow Zn(NO_3)_2+Pb

Hence, zinc will react with lead (II) nitrate solution.

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Answer:

The empiricial formula of the compound is BaO2

Explanation:

<u>Step 1:</u> Data given

Barium and oxygen dissolved in hydrochloric acid gives a solution of barium ion. This was precipitated with an excess of potassium chromate and gives barium chromate.

The original compound weighs 1.345g and gives 2.012g of BaCrO4

<u>Step 2: </u>Calculate moles of BaCrO4

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<u>Step 3</u>: Calculate moles of Ba

Mole ratio for Ba and BaCrO4 is 1:1 so this means for 0.0079 moles of BaCrO4, there are 0.0079 moles of Ba-ion

<u>Step 4:</u> Calculate mass of Ba-ion

Mass of Ba = Moles of Ba / Molar mass of Ba

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Since the original compound has barium and oxygen, the mass of oxygen is the difference between the original mass and the mass of the Ba-ion

1.345 g - (1.085 g Ba) = 0.260 g O

<u>Step 6:</u> Calculate moles of Oxygen

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