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katrin2010 [14]
2 years ago
14

What are the relative numbers of h3o+ and oh- ions in an acidic and alkaline and a neutral solution?

Chemistry
2 answers:
Kryger [21]2 years ago
7 0

Explanation:

  • When a solution is acidic in nature then it means its pH range is from 1 to 6.9. And, in an acidic solution there are more number of hydrogen (H^{+}) or hydronium (H_{3}O^{+}) ions as compared to hydroxide ions (OH^{-}).

    For acidic solutions,    [H^{+}] or [H_{3}O^{+}] > [OH^{-}]

  • Whereas if a solution is neutral in nature then its pH will be equal to 7. This means that concentration of hydrogen ions will be equal to concentration of hydroxide ions.

    For neutral solutions,    [H^{+}] or [H_{3}O^{+}] = [OH^{-}]

  • If a solution is basic in nature then its pH will be greater than 7. This means that in a basic solution concentration of hydroxide ions is more than the concentration of hydrogen ions.

    For basic solutions,   [H^{+}] or [H_{3}O^{+}]  < [OH^{-}]

lana [24]2 years ago
3 0
Acid more H3O+ than OH-
Base less H3O+ than OH-
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In the reaction MgCl2 + 2KOH Mg(OH)2 + 2KCl, if 3 moles MgCl2 are added to 4 moles KOH, what determines how much Mg(OH)2 is made
LenKa [72]
The correct option is C. The amount of MgCl2. we know this because <span>no matter how much you increase KOH, if you dont increase Mgcl2, the amount of Mg(OH)2 remains the same. Hope this works for you</span>
8 0
2 years ago
Now explain your diagnosis. Start your argument by writing something like this: "My group believes that Elisa has/does not have
likoan [24]

Answer:

Explanation:I would need more info to understand this question but explaining molecules is pretty easy tho

4 0
1 year ago
A 0.500 g sample of C7H5N2O6 is burned in a calorimeter containing 600. g of water at 20.0∘C. If the heat capacity of the bomb c
Nata [24]

Answer:

22.7

Explanation:

First, find the energy released by the mass of the sample. The heat of combustion is the heat per mole of the fuel:

ΔHC=qrxnn

We can rearrange the equation to solve for qrxn, remembering to convert the mass of sample into moles:

qrxn=ΔHrxn×n=−3374 kJ/mol×(0.500 g×1 mol213.125 g)=−7.916 kJ=−7916 J

The heat released by the reaction must be equal to the sum of the heat absorbed by the water and the calorimeter itself:

qrxn=−(qwater+qbomb)

The heat absorbed by the water can be calculated using the specific heat of water:

qwater=mcΔT

The heat absorbed by the calorimeter can be calculated from the heat capacity of the calorimeter:

qbomb=CΔT

Combine both equations into the first equation and substitute the known values, with ΔT=Tfinal−20.0∘C:

−7916 J=−[(4.184 Jg ∘C)(600. g)(Tfinal–20.0∘C)+(420. J∘C)(Tfinal–20.0∘C)]

Distribute the terms of each multiplication and simplify:

−7916 J=−[(2510.4 J∘C×Tfinal)–(2510.4 J∘C×20.0∘C)+(420. J∘C×Tfinal)–(420. J∘C×20.0∘C)]=−[(2510.4 J∘C×Tfinal)–50208 J+(420. J∘C×Tfinal)–8400 J]

Add the like terms and simplify:

−7916 J=−2930.4 J∘C×Tfinal+58608 J

Finally, solve for Tfinal:

−66524 J=−2930.4 J∘C×Tfinal

Tfinal=22.701∘C

The answer should have three significant figures, so round to 22.7∘C.

8 0
2 years ago
In which 1.0 gram sample are particles arranged in a rystal structure?
lilavasa [31]
The Options are as follow,

<span>                               (1) CaCl</span>₂<span> (s)     (3) CH</span>₃<span>OH (l)</span>

<span>                               (2) C</span>₂<span>H</span>₆<span> (g)      (4) Cal</span>₂<span> (aq)</span>

Answer:

            Option-1 is the correct answer.

Explanation:

                  As we know crystal formation is the property of solids. Therefore, in given options we are given with four different states of matter. 

                  Option A, CaCl₂ is in a solid state , so it can exist in crystal form.

                  Option 2, C₂H₆ (Ethane) is in gas form, so it cannot form crystals.

                  Option 3, CH₃OH (Methanol) is present in liquid form, so it fails to form crystals.

                  Option 4, CaI₂, it is dissolved in water, Hence, it is in aqueous state, Therefore it also lacks crystal structure.

5 0
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a_sh-v [17]
<span>Electrons in a nitrogen-phosphorus covalent bond are not shared equally because nitrogen and phosphorus do not have the same electronegativity. The atoms spend more time around the most electronegative atom nitrogen.</span>
6 0
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