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andreyandreev [35.5K]
2 years ago
8

In the unit 2 lab, what combination produced a brown bubbly liquid that looks like root-beer? (Select the two parts of the combi

nation)
Chalk


NaCl


KCl


Baking Soda


Sugar


Vinegar


Water


Citric Acid


Vegetable Oil


NaOH

Helpppppppp right now please
Chemistry
1 answer:
LekaFEV [45]2 years ago
6 0
Baking soda and chalk
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Which element from this portion of the table chemically reacts in a way similar to the way the element chlorine (Cl) reacts? (1)
mina [271]
D. I or Iodine

This is because they are both in the same periodic family (the halogens) and thus the number of valence electrons are the same
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2 years ago
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The percentage of silver in a solid sample is determined gravimetrically by converting the silver to Ag+ (aq) and precipitating
Wittaler [7]

Answer:

D

Explanation:

I - You should account the mass of the weighing paper to reduce it from the total mass at the end of the process, having only the mass of the Silver Chloride.

II - The precipitation of the silve chloride will occur independently of the temperature, because the Kps of this salt is very low (Ksp = [Ag+] .[Cl-]).

III - Washing the precipitate will secure the purity of the final product, it won't allow any other contaminant to be in your precipitante which could change your final mass.

IV - You should heat you AgCl precipitate so it will be dry, because of that the mass you will obtain is only the mass of the weighing paper and the silver chloride and nothing else.

8 0
1 year ago
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36g of KOH dissolved in 800mL of water. What is the molality of the solution?
Bad White [126]

Answer:

0.80m of KOH

Explanation:

Molality is an unit of concentration defined as the ratio between moles of solute and kg of solvent.

In the problem, the solute is KOH and solvent is water.

Moles of 36g KOH -Molar mass: 56.1g/mol- are:

36g KOH × (1mol / 56.1g) = <em>0.642 moles of KOH</em>

<em></em>

Now, as density of water is 1g/mL, mass of 800mL of water is:

800mL × (1g / mL) × (1kg / 1000g) = <em>0.800kg of water</em>

<em></em>

Thus, molality is:

0.642moles of KOH / 0.800kg = <em>0.80m of KOH</em>

5 0
2 years ago
What orbitals are used to form the 10 sigma bonds in propane (ch3ch2ch3)? Label each atom with the appropriate hybridization. Dr
SVETLANKA909090 [29]

Mixing of pure orbitals having nearly equal energy to form equal number of completely new orbitals is said to be hybridization.

For the compound, CH_3CH_2CH_3 the electronic configuration of the atoms, carbon and hydrogen are:

Carbon (atomic number=6): In ground state= 1s^{2}2s^{2}2p^{2}

In excited state: 1s^{2}2s^{1}2p^{3}

Hydrogen (atomic number=1): 1s^{1}

All the bonds in the compound is single bond(\sigma-bond) that is they are formed by head on collision of the orbitals.

The structure of the compound is shown in the image.

The Carbon-Hydrogen bond is formed by overlapping of s-orbital of hydrogen to p-orbital of carbon.

In order to complete the octet the required number of electrons for carbon is 4 and for hydrogen is 1. So, the electron in 1s^{1} of hydrogen will overlap to the 2p^{3}-orbital of carbon.

Thus, the hybridization of Hydrogen is s-hybridization and the hybridization of Carbon is sp^{3}-hybridization.

The hybridization of each atom is shown in the image.

3 0
2 years ago
Ammonia (nh3(g), hf = –46.19 kj/mol) reacts with hydrogen chloride (hcl(g), hf = –92.30 kj/mol) to form ammonium chloride (nh4cl
steposvetlana [31]

Answer: The \Delta H_{rxn} for the given chemical reaction is -175.51 kJ/mol

Explanation: Enthalpy change of the reaction is defined as the amount of heat released or absorbed in a given chemical reaction.

Mathematically,

\Delta H_{rxn}=\Delta H_f_{(products)}-\Delta H_f_{(reactants)}

We are given a chemical reaction. The reaction follows:

NH_3(g)+HCl(g)\rightarrow NH_4Cl(s)

H_f_{(NH_3)}=-46.19kJ/mol

H_f_{(HCl)}=-92.30kJ/mol

H_f_{(NH_4Cl)}=-314.4kJ/mol

Enthalpy change for the reaction of he given chemical reaction is given by:

\Delta H_{rxn}=H_f_{(NH_4Cl)}-(H_f_{(NH_3)}+H_f_{(HCl)})

Putting the values in above equation, we get

\Delta H_{rxn}=-314.4-(-92.30-46.19)kJ/mol

\Delta H_{rxn}=-175.51kJ/mol

8 0
2 years ago
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