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Maslowich
2 years ago
13

Which element from this portion of the table chemically reacts in a way similar to the way the element chlorine (Cl) reacts? (1)

Si (3) Xe (2) O (4) I ?
Chemistry
2 answers:
mina [271]2 years ago
4 0
D. I or Iodine

This is because they are both in the same periodic family (the halogens) and thus the number of valence electrons are the same
Anarel [89]2 years ago
3 0

Answer: (4) I (iodine)

Explanation:

Reactivity of elements follow a trend in such a manner that elements in the same group have similar chemical properties since they react in similar ways during chemical reaction. This similarity is as a result of the same number of valence electrons they have in their respective outer shell. This particular similarity is what classifies them into groups.

In this question, Chlorine is in the same group with Iodine and they're referred to as "halogens" and all halogen have similar chemical reactions. Example, they seek one valence electron to be stable. Easy formation of salts with metals etc

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What is the net ionic equation of the reaction of BeCl2 with NaOH
NNADVOKAT [17]
Net ionic equation:
Be(2+) + 2OH(-) ----> Be(OH)2

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8 0
2 years ago
Which image exclusively represents the principle of radiation? A) IV B) III C) II D) I
arsen [322]

The principle of radiation protection is to trigger deterministic and stochastic effect.

Explanation:

The main aim of principle of radiation is to prevent the deterministic effects of radiation and reduce the risks of stochastic effects.

There are three general principals of radiation used for dealing with ionising radiation are Justification, Dose limitation and Optimization.

The three basic radiation principles are time, distance and shielding.

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4 0
2 years ago
Read 2 more answers
Calculate the specific heat capacity for a 22.7-g sample of lead that absorbs 237 J when its temperature increases from 29.8 °C
soldier1979 [14.2K]

Answer:

\boxed {\boxed {\sf c\approx 0.159 \ J/ g \textdegree C}}

Explanation:

We are asked to find the specific heat capacity of a sample of lead. The formula for calculating the specific heat capacity is:

c= \frac{Q}{m \times \Delta T}

The heat absorbed (Q) is 237 Joules. The mass of the lead sample (m) is 22.7 grams. The change in temperature (ΔT) is the difference between the final temperature and the initial temperature. The temperature increases <em>from</em> 29.8 °C <em>to </em>95.6 °C.

  • ΔT = final temperature -inital temperature
  • ΔT= 95.6 °C - 29.8 °C = 65.8 °C

Now we know all three variables and can substitute them into the formula.

  • Q= 237 J
  • m= 22.7 g
  • ΔT = 65.8 °C

c= \frac {237 \ J}{22.7 \ g  \ \times  \ 65.8 \textdegree C}

Solve the denominator.

  • 22.7 g * 65.8 °C = 1493.66 g °C

c= \frac {237 \  J}{1493.66 \ g \textdegree C}

Divide.

c= 0.1586706479 J /g \textdegree C

The original values of heat, temperature, and mass all have 3 significant figures, so our answer must have the same. For the number we found that is the thousandth place. The 6 in the ten-thousandth place tells us to round the 8 up to a 9.

c \approx 0.159 \ J/g \textdegree C

The specific heat capacity of lead is approximately <u>0.159 Joules per gram degree Celsius.</u>

3 0
1 year ago
Suppose you are titrating vinegar, which is an acetic acid solution of unknown strength, with a sodium hydroxide solution accord
Marina CMI [18]

Answer:

M_{acid}=0.563M

Explanation:

Hello there!

In this case, given the neutralization of the acetic acid as a weak one with sodium hydroxide as a strong base, we can see how the moles of the both of them are the same at the equivalence point; thus, it is possible to write:

M_{acid}V_{acid}=M_{base}V_{base}

Thus, we solve for the molarity of the acid to obtain:

M_{acid}=\frac{M_{base}V_{base}}{V_{acid}} \\\\ M_{acid}=\frac{33.98mL*0.1656M}{10.0mL}\\\\ M_{acid}=0.563M

Regards!

5 0
2 years ago
2N2H4(l) + N2O4(l) → 3N2(g) + 4H2O(g) [balanced] How many moles of N2H4 is required to produce 28.3 g of N2? Assume that all rea
JulijaS [17]

Answer: 0.67 moles of N_2H_4

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles of nitrogen}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{28.3}{28.02}=1mole

2N_2H_4(l)+N_2O_4(l)\rightarrow 3N_2(g)+4H_2O(g)

According to stoichiometry:

3 moles of N_2 is produced by 2 moles of N_2H_4

Thus 1 mole of N_2 is produced by= \frac{2}{3}\times 1=0.67moles of N_2H_4

Thus 0.67 moles of N_2H_4 are required to produce 28.3 g of N_2

6 0
2 years ago
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