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Nonamiya [84]
2 years ago
5

In what type of environment would you most likely find Fish Species 1? Explain your answer.

Chemistry
2 answers:
KengaRu [80]2 years ago
5 0

Answer:

Fish are more likely to hold a soft bait longer. ... Signs of small fish activity can lead you to fishing hot spots. ... Cover can be loosely defined as anything that will hide or protect the fish.

Explanation:

Fishes live in virtually all aquatic habitats. Different species of fish are adapted for different habitats: rocky shores, coral reefs, kelp forests, rivers and streams, lakes and ponds, under sea ice, the deep sea, and other environments of fresh, salt, and brackish water.

VikaD [51]2 years ago
4 0
Most fishes live in aquatic environments such as the seas , rivers, and oceans
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A liquid has a volume of 34.6 ml and a mass of 46.0 g. what is the density of the liquid?
Minchanka [31]

The density of a substance can simply be calculated by dividing the mass by the volume:

density = mass / volume

 

Therefore calculating for the density since mass and volume are given:

density = 46.0 g / 34.6 mL

density = 1.33 g / mL

5 0
2 years ago
In an ionic bond:
inna [77]
Correct answer is 
<span>D. One atom accepts electrons from another.</span>
8 0
2 years ago
Read 2 more answers
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vredina [299]

Answer:

volume in L = 0.25 L

Explanation:

Given data:

Mass of Cu(NO₃)₂ = 2.43 g

Volume of KI = ?

Solution:

Balanced chemical equation:

2Cu(NO₃)₂  + 4KI    →    2CuI + I₂ + 4KNO₃

Moles of Cu(NO₃)₂:

Number of moles = mass/ molar mass

Number of moles = 2.43 g/ 187.56 g/mol

Number of moles = 0.013 mol

Now we will compare the moles of Cu(NO₃)₂ with KI.

                        Cu(NO₃)₂       :              KI    

                              2              :               4

                            0.013          :            4 × 0.013=0.052 mol

Volume of KI:

<em>Molarity = moles of solute / volume in L</em>

volume in L = moles of solute /Molarity

volume in L =  0.052 mol / 0.209 mol/L

volume in L = 0.25 L

6 0
2 years ago
A 63.5 g sample of an unidentified metal absorbs 355 ) of heat when its temperature changes
insens350 [35]

0.208 is the specific heat capacity of the metal.

Explanation:

Given:

mass (m)  = 63.5 grams 0R 0.0635 kg

Heat absorbed (q) = 355 Joules

Δ T (change in temperature) = 4.56 degrees or 273.15+4.56 = 268.59 K

cp (specific heat capacity) = ?

the formula used for heat absorbed  and to calculate specific heat capacity of a substance will be calculated by using the equation:

q = mc Δ T

c = \frac{q}{mΔ T}

c = \frac{355}{63.5X 268.59}

 = 0.208 J/gm K

specific heat capacity of 0.208 J/gm K

The specific heat capacity is defined as  the heat required to raise the temperature of a substance which is 1 gram. The temperature is in Kelvin and energy required is in joules.

 

5 0
2 years ago
As the pressure on a gas confined above a liquid increases, the solubility of the gas in the liquid
Gelneren [198K]
As the pressure on the on a gas cofined above a liquid increases, the solubility of the gas will increase

this also happen when we lower the temperature
4 0
2 years ago
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