-OH is elctron donating -C=-N is electron withdrawing -O-CO-CH3 is electron withdrawing -N(CH3)2 is electron donating -C(CH3)3 is electron donating -CO-O-CH3 is electron withdrawing -CH(CH3)2 is electron donating -NO2 is electrong withdrawing -CH2
<span>NaCH3COO (s) + HCl (aq) ---> HCH3COO (aq) + NaCl (s)</span>
Answer:
Explanation:
Given the moles, we are asked to find the mass of a sample.
We know that the molar mass of methanol is 32.0 grams per mole. We can use this number as a fraction or ratio.
Multiply by the given number of moles, which is 2.0
The moles of methanol will cancel each other out.
The denominator of 1 can be ignored.
Multiply.
There are 64 grams of methanol in the sample.
This question could be answered easily if the results of the abundance of the other elements are given. You will just have to subtract the sum of all their abundances to 100. Since it's not given, the solution would just be:
Na = 23 g/mol* 1 = 23 g
H = 1 g/mol * 1 = 1 g
C = 12 g/mol * 1 = 12 g
O = 16 g/mol * 3 = 48 g
Total = 84 g
% O = 48/84 * 100 = <em>57.14%</em>
Answer:
Density: Physical Property
Flammability: Chemical Property
Solubility In Water: Physical Property
Reactivity With Water: Chemical Property
Melting Pot: Physical Property
Color: Physical Property
Odor: Physical Property
Explanation:
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