<span>
• </span>Volume of the marshmallow:
V = 2.75 in^3 (but, 1 in^3 = 16.39 cm^3)
V = 2.75 × 16.39 cm^3
V = 2.75 × 16.39 cm^3
V = 45.0725 cm^3
• Density:
d = 0.242 g/cm^3
<span>• </span>Mass:
m = d × V
m = (0.242 g/cm^3) × (45.0725 cm^3)
m = (0.242 g/cm^3) × (45.0725 cm^3)
m = 10.907545 g
m ≈ 10.9 g <——<span>— this is the answer.
I hope this helps. =)
</span>
Answer:
59.2 grams
Explanation:
We are given that 70.4% of the weight of the total 200 g of the concentration is made up of nitric acid, the remaining information is not required to solve the problem. Since water and nitric acid are the only components of the solution, the total weight of water is given by:
There are 59.2 grams of water in this solution.
Answer:
Half life = 1600 years
Explanation:
Given data:
Total mass of sample = 45.00 g
Mass remain = 5.625 g
Time period = 4800 years
Half life of radium-226 = ?
Solution:
First of all we will calculate the number of half lives passes,
At time zero 45.00 g
At first half life = 45.00 g/ 2= 22.5 g
At 2nd half life = 22.5 g/ 2 = 11.25 g
At 3rd half life = 11.25 g/ 2= 5.625 g
Half life:
Half life = Time elapsed / number of half lives
Half life = 4800 years / 3
Half life = 1600 years
<h2>Diethylether (DTH) andTetrahydrofuran (THF).</h2>
Explanation:
- Grignard reactions reacts with water forming alkanes.
- The water present causes the reagent to decompose rapidly.
- So, the solvents which are utilized in the experimental procedure to minimize exposure of the grignard reagents to air and/ormoisture are solvents such as anhydrous diethyl ether or tetrahydrofuran(THF), poly(tetramethylene ether) glycol (PTMG).
- The reason for the use of these solvents is the oxygen present in these solvents stabilizes the magnesium reagent.
- THF (Tetrahydrofuran) is a stable compound.
Answer:
The mixture of B and C will melt as 130 - 139 ºC.
Explanation:
If the melting point (130 - 139 ºC) of a mixture of A and B is lower than the pure substances that is 149 - 150 ºC that means that one of these susbtances is an impurity because reduces the melting point.
If the melting point of the mixture of A and C is the same as the pure substances, we can deduce that they are the same substances, also because the melting point when a substance is pure is just 1 or 2 ºC like in this case.
So in a Mixture of B and C is going to be like the first case of the mixture among A and B, because the B substance is the impurity.
