Answer:
Dipole-Dipole attraction
Explanation:
Dipole-dipole attraction is a type of vander waals forces found in the molecules of sulfur dioxide.
Vander waals forces are weak attractions joining non-polar and polar molecules together. They are of two types:
- London dispersion forces which are weak attractions found between non-polar molecules.
- Dipole-Dipole attraction are the forces of attraction which exists between polar molecules. Such molecules have permanent dipoles. This implies that the positive pole of one molecule attracts the negative pole of another. This is what happens between the oxygen and sulfur molecules.
In order to compute the y-component of a vector, we simply use the formula:
Fy = F*sin(∅)
Where ∅ is the angle of the vector measured from the positive x-axis and F is the magnitude of the vector.
Similarly, the x-component is calculated by substituting sin(∅) with cos(∅)
Answer : The combustion is a process in which oxygen is released as a by-product of oxidation-reduction reactions.
Explanation :
Combustion reaction : It is defined as the reactions in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide and water.
The chemical equation of combustion reaction is:

The combustion reaction is also a redox reaction.
Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.
Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.
Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.
The combustion reaction is also a redox reaction in which the carbon shows oxidation by the addition of oxygen or removal of hydrogen and oxygen shows reduction by the addition of hydrogen or removal of oxygen.
Hence, the combustion is a process in which oxygen is released as a by-product of oxidation-reduction reactions.
Answer
D 160g
Explanation:
<u>Write the equation:</u>
Combustion reactions use oxygen and release water and heat, so
CH₃OH(g) + O₂(g) → CO₂(g) + H₂O(g)
Balance that:
2CH₃OH(g) + 3O₂(g) → 2CO₂(g) + 4H₂O(g)
<u>Find moles of carbon dioxide:</u>
We need to know the number of moles of CO₂. This rxn is at STP, so at STP one mole of gas = 22.4 liters.
112 L * 1 mol/22.4 L = <em>5 mol CO₂</em>
<u>Find moles of methanol:</u>
Based on the chemical equation, for every 2 mol methanol, there are 2 mol carbon dioxide. So for every 5 mol carbon dioxide, there are 5 mol methanol!
5 mol CO₂ = 5 mol CH₃OH
Molar mass of methanol: 12.01 + 3*1.008 + 16.00 + 1.008 = <em>32.04 g/mol</em>
Moles of methanol: 5 mol * 32.04 g/mol = 160.2 g methanol
≈ 160 mol methanol
Hello!
If the frequency of a radio station is 88.1 MHz, the wavelength of the wave used by this radio station for its broadcast is 3.403 m
<h2>Why?</h2>
We are going to use the following equation that shows the relation of the frequency of a wave with its wavelength, knowing that radio waves are electromagnetic waves and they travel at the speed of light (299 792 458 m/s):

Have a nice day!